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6.NS.5-Understanding Positive and Negative Numbers(Grade 6 Math) | www.lumoslearning.com

By Lumos Learning

6.NS.5-Standard description : Understand that positive and negative numbers are used together to describe quantities having opposite directions or values (e.g., temperature above/below zero, elevation above/below sea level, credits/debits, positive/negative electric charge); use positive and negative numbers to represent quantities in real-world contexts, explaining the meaning of 0 in each situation. Using the Lumos Study Programs, parents and educators can reinforce the classroom learning experience for children and help them succeed at school and on the standardized tests. Lumos books, dvd, eLearning and tutoring are used by leading schools, libraries and thousands of parents to supplement classroom learning and improve student achievement in the standardized tests.

Subtracting Integers | MathHelp.com

By MathHelp.com

Imaginary roots of negative numbers | Imaginary and complex numbers | Precalculus | Khan Academy

By Khan Academy

Khan Academy presents Imaginary Roots of Negative Numbers, an educational video resource on math.

Math Antics - Integer Multiplication & Division

By mathantics

Math Antics - Negative Numbers

By mathantics

Quadratic Word Problems | MathHelp.com

By MathHelp.com

A number is 56 less than its square. Find the number. To solve this problem, let’s translate the first sentence into an equation. A number, that’s x, is, =, 56 less than it’s square, that’s x squared – 56. Remember that “less than” switches the order around. In other words, “56 less than its square” is not 56 minus x squared, it’s x squared minus 56. Next, since we have an x squared term in our equation, we set it equal to 0 by subtracting x from both sides, and we have 0 = x squared – x – 56. Next, we factor the right side as the product of two binomials. In the first position of each binomial, we have the factors of x squared, x and x. In the second position of each binomial, we’re looking for the factors of -56 that add to -1, which are -8 and positive 7. So we have 0 = x - 8 times x + 7, which means that either 0 = x – 8 or 0 = x + 7. Finally, in the first equation, we add 8 to both sides, to get 8 = x. And in the second equation, we subtract 7 from both sides, to get -7 = x. So 8 = x or -7 = x. It’s important to understand that both of these answers work. Plugging an 8 back into the original problem, we have 8 is 56 less than 8 squared, or 8 = 8 squared – 56, which simplifies to 8 = 64 – 56, or 8 = 8, which is a true statement. And plugging a -7 back into the original problem, we have -7 is 56 less than -7 squared, or -7 = -7 squared – 56, which simplifies to -7 = 49 – 56, or -7 = -7, which is also a true statement.