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This page provides a list of educational videos related to Finding an Equation of a Line. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Finding an Equation of a Line.
Find the Equation of a Line Using Point-Slope Form
By PatrickJMT
Find the Equation of a Line Using Point-Slope Form - I show one complete example of finding the equation of a line using point-slope form. For more free math videos, visit http://PatrickJMT.com
Equation of the normal line at a point
By TheIntegralCALC
http://integralcalc.com/ Learn how to find the equation of the normal line at a given point. To find the equation of the normal line, you'll need to first calculate the derivative of the function, then plug the given point into the derivative to find the slope of the tangent line. Plug the slope and the given point into the point-slope formula for the equation of the line to find the equation of the tangent line. Then take the negative reciprocal of the slope of the tangent line to find the slope of the normal line, which is the line perpendicular to the tangent line. Finally, plug the new slope and the given point into the point-slope formula for the equation of the line to find the equation of the normal line
Example Problem - Solving a System with Linear and Quadratic Equations
By Khan Academy
Watch this example of solving a system of a linear equation and quadratic equation. The solution is found by finding the intersection of the the line and parabola graphically. Then, the solution is verified algebraically.
Inverse Functions | MathHelp.com
By MathHelp.com
In this example, we’re given a relation in the form of a chart, and we’re asked to find the inverse of the relation, then graph the relation and its inverse. To find the inverse of a relation, we simply switch the x and y values in each point. In other words, the point (1, -4) becomes (-4, 1), the point (2, 0) becomes (0, 2), the point (3, 1) becomes (1, 3), and the point (6, -1) becomes (-1, 6). Next, we’re asked to graph the relation and its inverse, so let’s first graph the relation. Notice that the relation contains the points (1, -4,), (2, 0), (3, 1), and (6, -1). And the inverse of the relation contains the points (-4, 1), (0, 2), (1, 3), and (-1, 6). Finally, it’s important to understand the following relationship between the graph of a relation and its inverse. If we draw a diagonal line through the coordinate system, which is the line that has the equation y = x, notice that the relation and its inverse are mirror images of each other in this line. In other words, the inverse of a relation is the reflection of the original relation in the line y = x.
Algebra I Help: Solving Systems of Linear Equations Part II Graphing 2/3
By yourteachermathhelp
The instructor uses a white board for demonstration and this video is suitable for high school students. Students learn to solve a system of linear equations by graphing. The first step is to graph each of the given equations then find the point of intersection of the two lines which is the solution to the system of equations. If the two lines are parallel then the solution to the system is the null set. If the two given equations represent the same line then the solution to the system is the equation of that line.
Graphing Systems of Equations Video: Graphing Systems of Equations
By yourteachermathhelp
This lesson explains how to solve a system of two equations by graphing. The instructor begins by graphing the line for each equation. Then he demonstrates how to find the point of intersection which is the solution for the system.
Slope-intercept equation from two solutions example | Algebra I | Khan Academy
By Khan Academy
Find the equation of a line given two points, neither of which is the y-intercept. To do this, first find the slope, then you may either graph the line (as is done here), or plug in one of the points in for "x" and "y" into y = mx + b to solve for "b."
One-step inequality involving addition
By Khan Academy
Watch this explanation of how to solve 1-step inequalities and respresent the solution on a number line. Solving an inequality means finding all of its solutions. A solution of an inequality is a number which when substituted for the variable makes the inequality a true statement. Unlike an equation an inequality has many solutions.
Parallel Lines | MathHelp.com
By MathHelp.com
This lesson covers imaginary numbers. Students learn that the imaginary number "i" is equal to the square root of -1, which means that i^2 is equal to (the square root of -1) squared, which equals -1. Students also learn to simplify imaginary numbers. For example, to simplify the square root of -81, think of it as the square root of -1 times the square root of 81, which simplifies to i times 9, or 9i. To simplify 11/8i, the first step is to get rid of the "i" in the denominator by multiplying both the numerator and the denominator of the fraction by i, to get 11i/8i^2, and remember that i^2 = -1, so we have 11i/8(-1), or 11i/-8, or -11i/8.
Inverse Relations | MathHelp.com
By MathHelp.com
Here we’re asked to solve for x in the equation: log base x of 144 = 2. Notice that we have a logarithmic equation, so let’s first convert the equation to exponential form. Remember that the base of the log represents the base of the power, the right side of the equation represents the exponent, and the number inside the log represents the result, so we have x…squared…= 144. Now, to solve for x, since x is squared, we simply take the square root of both sides of the equation to get x = plus or minus 12. Remember to always use plus or minus when taking the square root of both sides of an equation. However, notice that x represents the base of the logarithm in the original problem, and the base of a logarithm cannot be negative. Therefore, x cannot be equal to negative 12. So our final answer is x = 12.
Systems of Three Equations | MathHelp.com
By MathHelp.com
Here we’re asked to graph the following function and use the horizontal line test to determine if it has an inverse. And if so, find the inverse function and graph it. So let’s start by graphing the given function, f(x) = 2x – 4, and remember that f(x) is the same as y, so we can rewrite the function as y = 2x – 4. Now, we simply graph the line y = 2x – 4, which has a y-intercept of -4, and a slope of 2, or 2/1, so we go up 2 and over 1, plot a second point and graph our line, which we’ll call f(x). Next, we’re asked to use the horizontal line test to determine if the function has an inverse. Since there’s no way to draw a horizontal line that intersects more than one point on the function, the function does have an inverse. So we need to find the inverse and graph it. To find the inverse, we switch the x and the y in original function, y = 2x – 4, to get x = 2y – 4. Next, we solve for y, so we add 4 to both sides to get x + 4 = 2y, and divide both sides by 2 to get 1/2x + 2 = y. Next, let’s flip our equation so that y is on the left side, and we have y = 1/2x + 2. Finally, we replace y with the notation that we use for the inverse function of f, as shown here. And remember that we’re asked to graph the inverse as well, so we graph y = ½ x + 2. Our y-intercept is positive 2, and our slope is ½, so we go up one and over 2, plot a second point, graph the line, and label it as the inverse function of f. Notice that the graph of the inverse function is a reflection of the original function in the line y = x.
ALL OF GRADE 9 MATH IN 60 MINUTES!!! (exam review part 2)
By Lumos Learning
Here is a great exam review video reviewing all of the main concepts you would have learned in the MPM1D grade 9 academic math course. The video is divided in to 3 parts. This is part 2: Linear Relations. In this video you will review everything there is to know about y=mx+b, scatterplots, and distance time graphs.
12 - Solving 3-Variable Linear Systems of Equations - Substitution Method
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!