Systems of Three Equations | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Systems of Three Equations | MathHelp.com - Free Educational videos for Students in k-12


Systems of Three Equations | MathHelp.com - By MathHelp.com



Transcript
00:0-1 in this example notice that each of our variables X
00:04 , Y and Z appears in all three equations to
00:09 solve this system . We use the addition method .
00:14 In other words , let's start with our first two
00:16 equations , X plus Y plus Z equals four ,
00:21 an x minus Y plus Z equals two . Notice
00:26 that if we add these equations together , the plus
00:29 Y and minus Y will cancel out . And we
00:33 have two , X plus two , Z equals six
00:37 . So in our new equation two X plus two
00:41 Z equals six . We've eliminated the variable . Why
00:46 ? Unfortunately we still haven't solved for any of our
00:50 variables . However , if we can create another equation
00:55 with just X and Z in it , then we'll
00:58 have a system of equations in two variables , which
01:02 we can use to solve for X and Z to
01:06 create another equation with just X and Z in it
01:10 , we need to eliminate why we can't add the
01:14 1st and 2nd equations together because we've already done that
01:19 . However , notice that if we add the 1st
01:22 and 3rd equations together , the first equation has a
01:26 plus Y And the 3rd equation has a -Y .
01:30 So we'll be able to eliminate the why . So
01:34 we have our first equation , X plus Y plus
01:37 Z equals four . And our 3rd equation x minus
01:42 y minus Z equals zero . And adding them together
01:47 . Notice that the plus y minus Y cancels out
01:51 and as a bonus the plus z minus Z also
01:55 cancels out . So we have two . x equals
01:59 four And dividing both sides by two , x equals
02:04 two . Now , since we know that X equals
02:08 two , notice that if we plug a two in
02:11 for X in the equation that we created earlier ,
02:14 we can solve for Z and we have two times
02:19 two plus two , Z equals six or four plus
02:24 two , Z equals six . And subtracting four from
02:27 both sides , we have two . Z equals two
02:32 and dividing both sides by two , Z equals one
02:36 , So x equals two , z equals one .
02:40 And to find the value of why we simply plug
02:43 our values of X and Z into any of the
02:47 equations in the original system . Let's use the first
02:51 equation , X plus Y plus Z equals four ,
02:57 since X equals two and Z equals one . We
03:00 plug a two in for X and a one in
03:03 for Z . And we have two plus Y plus
03:08 one equals four or three plus Y equals four .
03:13 And subtracting three from both sides , Y equals one
03:18 , So x equals two , y equals one and
03:22 z equals one . And finally we write our answer
03:26 as the ordered triple , X , Y , Z
03:30 Or 2 . 1 , 1 .
Summarizer

DESCRIPTION:

Here we’re asked to graph the following function and use the horizontal line test to determine if it has an inverse. And if so, find the inverse function and graph it. So let’s start by graphing the given function, f(x) = 2x – 4, and remember that f(x) is the same as y, so we can rewrite the function as y = 2x – 4. Now, we simply graph the line y = 2x – 4, which has a y-intercept of -4, and a slope of 2, or 2/1, so we go up 2 and over 1, plot a second point and graph our line, which we’ll call f(x). Next, we’re asked to use the horizontal line test to determine if the function has an inverse. Since there’s no way to draw a horizontal line that intersects more than one point on the function, the function does have an inverse. So we need to find the inverse and graph it. To find the inverse, we switch the x and the y in original function, y = 2x – 4, to get x = 2y – 4. Next, we solve for y, so we add 4 to both sides to get x + 4 = 2y, and divide both sides by 2 to get 1/2x + 2 = y. Next, let’s flip our equation so that y is on the left side, and we have y = 1/2x + 2. Finally, we replace y with the notation that we use for the inverse function of f, as shown here. And remember that we’re asked to graph the inverse as well, so we graph y = ½ x + 2. Our y-intercept is positive 2, and our slope is ½, so we go up one and over 2, plot a second point, graph the line, and label it as the inverse function of f. Notice that the graph of the inverse function is a reflection of the original function in the line y = x.

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