Inverse Relations | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Inverse Relations | MathHelp.com - Free Educational videos for Students in k-12


Inverse Relations | MathHelp.com - By MathHelp.com



Transcript
00:0-1 in this example , we're given a relation in the
00:03 form of a chart and we're asked to find the
00:06 inverse of the relation . Then graph the relation and
00:10 its inverse to find the inverse of a relation .
00:14 We simply switch the X and Y values in each
00:18 point . In other words , the .1 -4 becomes
00:23 -41 , The .20 become 02 , The .31 becomes
00:30 1 3 , And the .6 -1 becomes -16 .
00:38 Next we're asked to graph the relation and its inverse
00:42 . So let's first graph the relation Notice that the
00:46 relation contains the points 1 -4-0 3 , 1 and
00:52 6 -1 . And the inverse of the relation contains
00:57 the points negative 4102 13 and -16 . Finally ,
01:05 it's important to understand the following relationship between the graph
01:10 of a relation and its inverse . If we draw
01:14 a diagonal line through the coordinate system , which is
01:18 the line that has the equation , Y equals X
01:22 . Notice that the relation and its inverse are mirror
01:26 images of each other in this line . In other
01:29 words , the inverse of a relation is the reflection
01:33 of the original relation in the line Y equals X
00:0-1 .
Summarizer

DESCRIPTION:

Here we’re asked to solve for x in the equation: log base x of 144 = 2. Notice that we have a logarithmic equation, so let’s first convert the equation to exponential form. Remember that the base of the log represents the base of the power, the right side of the equation represents the exponent, and the number inside the log represents the result, so we have x…squared…= 144. Now, to solve for x, since x is squared, we simply take the square root of both sides of the equation to get x = plus or minus 12. Remember to always use plus or minus when taking the square root of both sides of an equation. However, notice that x represents the base of the logarithm in the original problem, and the base of a logarithm cannot be negative. Therefore, x cannot be equal to negative 12. So our final answer is x = 12.

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