Proof: Diagonals of a parallelogram bisect each other | Quadrilaterals | Geometry | Khan Academy - Free Educational videos for Students in K-12 | Lumos Learning

Proof: Diagonals of a parallelogram bisect each other | Quadrilaterals | Geometry | Khan Academy - Free Educational videos for Students in k-12


Proof: Diagonals of a parallelogram bisect each other | Quadrilaterals | Geometry | Khan Academy - By Khan Academy



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DESCRIPTION:

This video shows us how we can show that the diagonals of a parallogram bisect each other, and that any quadrilateral whose diagonals bisect each other MUST be a parallelogram.

OVERVIEW:

Proof: Diagonals of a parallelogram bisect each other | Quadrilaterals | Geometry | Khan Academy is a free educational video by Khan Academy.It helps students in grades HS practice the following standards HSG.CO.C.11.

This page not only allows students and teachers view Proof: Diagonals of a parallelogram bisect each other | Quadrilaterals | Geometry | Khan Academy but also find engaging Sample Questions, Apps, Pins, Worksheets, Books related to the following topics.

1. HSG.CO.C.11 : Prove theorems about parallelograms. Theorems include: opposite sides are congruent, opposite angles are congruent, the diagonals of a parallelogram bisect each other, and conversely, rectangles are parallelograms with congruent diagonals..


GRADES:

HS


STANDARDS:

HSG.CO.C.11

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