16 - Simplify Logarithms - Part 1 (Log Bases, Calculate Logarithms & More) - By Math and Science
Transcript
00:00 | Hello . Welcome back . The title of this lesson | |
00:02 | is called Simplifying logarithms . This is part one of | |
00:05 | several . Up until this point we have covered the | |
00:07 | concept of the exponential function . You should have already | |
00:10 | watched a lesson on what an exponential function is . | |
00:12 | It's a number raised to a power of the variables | |
00:15 | such as like for instance to to the X . | |
00:17 | 3 to the X . Those are exponential functions . | |
00:19 | We've also covered in great detail the concept of al | |
00:22 | algorithm . The algorithm is the inverse function of the | |
00:26 | exponential function . So you also should have learned in | |
00:28 | the past lessons on what an inverse function is . | |
00:31 | So long algorithm , an exponential function go together like | |
00:34 | peanut butter and jelly there in verses of one another | |
00:36 | . So there's two things I want you to remember | |
00:38 | in the back of your mind as we go and | |
00:40 | we start simplifying logarithms and really applying the definition of | |
00:43 | the law algorithm . The first thing is I want | |
00:45 | you to always remember that a law algorithm is the | |
00:47 | inverse function . It's kind of the opposite function of | |
00:49 | an exponential and likewise the exponential is an opposite function | |
00:52 | of algorithm . So later on down the road we're | |
00:55 | gonna use exponential and logarithms to undo each other . | |
00:58 | We're gonna use them to solve equations because we can | |
01:00 | undo those those functions with the universe function , right | |
01:04 | ? And the second thing is I want you to | |
01:06 | understand that a lot algorithm when you calculate what it's | |
01:10 | doing , it's giving you back an exponent . We | |
01:12 | talked about that in the last lesson when we introduce | |
01:14 | logarithms . When you calculate the algorithm of 10 algorithm | |
01:18 | based two of 15 or log rhythm based five of | |
01:21 | nine or whatever the calculation you get back is , | |
01:23 | it's returning the exponent back . The exponent required to | |
01:26 | calculate that number that you're taking the log rhythm of | |
01:30 | . So here we go , simplifying some logs . | |
01:32 | I want you to remember both of those things which | |
01:34 | you've covered in the past . |
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