SAT Math Part 4 - Solving Radical Equations and Plugging In Numbers - By The Organic Chemistry Tutor
Transcript
00:00 | number 16 According to the equation shown below . What | |
00:06 | is the value of X -7 squared ? So first | |
00:11 | we need to calculate the value of X . And | |
00:14 | then we can plug it into this expression to get | |
00:16 | that value . So let's begin by adding 12 to | |
00:21 | both sides . 28 plus 12 is 40 . Now | |
00:30 | our next step is to divide both sides by five | |
00:35 | 40 , divided by five is 8 . So we | |
00:40 | have this , The four fruit of x cubed is | |
00:43 | equal to eight . Now what do you think we | |
00:45 | need to do at this point ? What we need | |
00:48 | to do is convert this radical expression into a fractional | |
00:52 | exponents . So the four fruit of X cubed can | |
00:55 | be written as x rays and three of the four | |
01:01 | . Now we need to get X by itself . | |
01:04 | So we need to get rid of this fractional exponents | |
01:08 | . The best thing to do is to raise both | |
01:10 | sides to the reciprocal of 3/4 , Which is going | |
01:14 | to be 4/3 . So on the left side we | |
01:18 | can see that the threes will cancel and the forest | |
01:21 | will cancel . So X . Is equal to eight | |
01:26 | . Race to the 4/3 . Now , how do | |
01:29 | we evaluate this thing ? What is 8 ? Race | |
01:33 | to the 4/3 ? Well , we need to do | |
01:36 | is separate the four and 3 . We can say | |
01:39 | this is eight . Race to the 1/3 . The | |
01:41 | race to the 4th power . eight race of the | |
01:44 | 1/3 is basically the cube root of eight . One | |
01:48 | number multiplied it by itself three times is eight , | |
01:52 | you know , two times two times two is eight | |
01:54 | . So the cube root of eight is too . | |
01:56 | So now we have two to the fourth power . | |
01:59 | So we're multiplying 4 , 2s Two times two is | |
02:03 | 4 and four times 4 is 16 . So eight | |
02:07 | race to the 4/3 is 16 . So now we | |
02:11 | have the value of X . This is not the | |
02:14 | final answer . Our goal is to calculate the value | |
02:20 | of X -7 squared . So let's plug in accent | |
02:26 | to the expression . So it's going to be 16 | |
02:29 | -7 squared 16 -7 is nine And nine squared is | |
02:35 | 81 . So this right here is my answer as | |
02:40 | a choice . E . Number 17 . Which of | |
02:45 | the following answer choices represents the value of Y . | |
02:49 | If D is equal to three . Well , let's | |
02:53 | begin marble . Place in D with three . So | |
02:59 | now all we need to do is calculate the value | |
03:01 | of why at this point now we can actually try | |
03:05 | to solve it or we can plug in numbers . | |
03:09 | So let's try answer choice be let's see if both | |
03:13 | sides of the equation have the same value . If | |
03:16 | why is equal to one . So let's replace . | |
03:19 | Why with 1 ? three times one is stream 3 | |
03:25 | -5 is -2 . -3 is also negative too . | |
03:29 | Now the square root of -2 is not equal to | |
03:32 | -2 . So therefore we can eliminate answer choice B | |
03:39 | . Let's try see . So we have three times | |
03:42 | 4 -5 and on the right side four monastery now | |
03:47 | three times 4 is 12 And for ministry is one | |
03:52 | , 12 -5 is seven . The square root of | |
03:55 | seven does not equal one . So see is eliminated | |
04:00 | . Let's try answer choice deep . Let's see if | |
04:02 | Y is equal to seven . So we're going to | |
04:06 | have three times seven minus five is equal to seven | |
04:09 | . Monastery three times 7 is 21 , 7 -3 | |
04:15 | is four . Now 21 -5 is 16 And the | |
04:20 | square root of 16 does equal four . So because | |
04:23 | the left side is the same as the right side | |
04:26 | . Answer choice D . Is the correct answer . | |
04:32 | And now we're going to do at this point is | |
04:38 | we're going to show our work just in case this | |
04:43 | problem was a free response problem . So we're actually | |
04:47 | going to solve this problem now , how should we | |
04:51 | go about doing this ? So we have a square | |
04:54 | root symbol on the left and no square root symbol | |
04:58 | on the right because we have a radical function on | |
05:01 | the left . We need to take the square both | |
05:02 | sides just to get rid of it . So the | |
05:07 | square of the square root of 3 , -5 , | |
05:10 | it's just gonna be three Y -5 . The square | |
05:13 | root and the square will cancel . Now on the | |
05:16 | right side , we need to foil . Why monastery | |
05:19 | square ? So first let's expand the expression . So | |
05:24 | why times why is why squared ? And then we | |
05:27 | have y . times negative three Which is -3 Y | |
05:31 | . And then we have another negative three Y . | |
05:33 | And then negative three times negative three is positive nine | |
05:40 | . Now let's combine like terms on the right side | |
05:44 | . So negative three Y minus three . Y . | |
05:46 | That's gonna be negative six Y . Next Let's add | |
05:51 | 5 to both sides And let's subtract both sides by | |
05:55 | three wide . So we're going to have zero is | |
06:04 | equal to y squared . Now a negative six Y | |
06:08 | minus street Y . Is negative nine . Y . | |
06:11 | And nine plus five is 14 . So that's what | |
06:14 | we now have . So at this point we have | |
06:19 | a try no meal with the leading coefficient of one | |
06:23 | . So let's factor it will need to numbers that | |
06:25 | multiply to 14 but add to the middle coefficient of | |
06:29 | -9 . Now we know seven times two is 14 | |
06:33 | and seven plus two adds up tonight . But if | |
06:37 | we use negative seven and negative two it's gonna add | |
06:40 | up to negative nine but still multiply two positive 14 | |
06:46 | . So to factor the expression on the right It's | |
06:48 | going to be why -7 Times Y -2 . Our | |
06:53 | next step is to set each factor equal to zero | |
06:57 | . So on the left we're going to add seven | |
06:59 | on both sides . So this will give us the | |
07:02 | answer that we have , which is why is equal | |
07:04 | to seven . And on the right we're going to | |
07:07 | add to the both sides which will give us another | |
07:10 | potential answer why is equal to two now , because | |
07:13 | we don't have that answer , we're not gonna worry | |
07:15 | about it . But we can clearly see why D | |
07:18 | is a correct answer choice based on what's written in | |
07:21 | this problem . So that's it for this particular question | |
07:26 | number 18 . If the square root of B is | |
07:29 | equal to four , then what is the value of | |
07:32 | the expression shown below ? So what we're gonna do | |
07:36 | is we're going to calculate the value of B and | |
07:38 | then plug it in to that expression . So what | |
07:43 | is be equal to to get rid of the square | |
07:46 | root symbol ? We need to take the square of | |
07:48 | both sides . So the square of the square root | |
07:52 | of B is just be so B is four squared | |
07:55 | which means to be a 16 . So now we | |
07:58 | can plug in 16 But we already know that the | |
08:01 | square root of BS four so we can just replace | |
08:04 | that with four . I'm gonna plug in . I'm | |
08:09 | going to replace me of 16 on the right side | |
08:13 | . four times 16 is 64 . Now the cube | |
08:17 | root of 64 is going to be four Because if | |
08:22 | you multiply 43 times You get 64 . So that's | |
08:28 | the Cuban of 64 is for . So now we're | |
08:31 | left with this four times four , four times 4 | |
08:34 | is 16 . So this is the answer which corresponds | |
08:39 | to answer choice C . Number 19 . Let the | |
08:44 | function age be defined by H . of X is | |
08:47 | equal to seven x plus 25 . If the square | |
08:51 | root of HF be over four is equal to nine | |
08:56 | then what is the value of B . So here | |
08:59 | we have a free response problem . So let's write | |
09:03 | down what we know the square root of H . | |
09:07 | of the over four is equal tonight . Using this | |
09:12 | . How do we calculate B ? Well we know | |
09:15 | that H . Of X . Is seven x plus | |
09:19 | 25 . So based on that , what is age | |
09:23 | of be over 4 ? So in this case we | |
09:26 | need to replace acts with the over four . So | |
09:29 | it's seven times before plus 25 . So what we're | |
09:35 | gonna do now is replace H . F . b | |
09:37 | . of four with what we have here . So | |
09:41 | now we have this equation . The square root of | |
09:44 | seven times be over four plus 25 is equal tonight | |
09:51 | . So now we're solving a radical equation . So | |
09:54 | let's get rid of the square root by taking the | |
09:56 | square both sides . So on the left side we're | |
09:59 | gonna have seven times be over four Plus 25 . | |
10:03 | And on the right side We have nine squared nine | |
10:06 | Squared is 81 . Now let's subtract both sides by | |
10:11 | 25 , 81 -25 , 81 -20 is 61 and | |
10:21 | 61 -5 . That's going to be 56 . So | |
10:28 | we have 56 is equal to seven Times be over | |
10:32 | four . So let's multiply both sides by one of | |
10:35 | the seven . So on the left side , the | |
10:39 | seven and one of the seven will cancel . This | |
10:42 | is the same as dividing both sides by seven . | |
10:45 | On the right we have 56 divided by seven , | |
10:47 | which is eight , So be over four is equal | |
10:51 | to eight . So now let's cross multiply four times | |
10:55 | eight is 32 and that's equal to one times b | |
10:58 | , which is B . So now we have the | |
11:00 | answer B is equal to 32 . And so that's | |
11:04 | it for this problem . |
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