Ohm's Law - Simple Circuits - By tecmath
Transcript
00:0-1 | Good day . Welcome to take Math channel . I'm | |
00:01 | josh . What we're going to be having a look | |
00:03 | at in this video is Homes Law what it is | |
00:05 | and how to use it . So let's start out | |
00:07 | with the basics and this is not going to take | |
00:09 | too long . So before we get to OEMs Law | |
00:11 | , I'm just gonna quickly show you an electrical circuit | |
00:14 | and how Holmes Law relates to this . An electrical | |
00:17 | circuit . You know , one of these is where | |
00:18 | we have a power source , such as a power | |
00:20 | point or a battery as we have here with a | |
00:22 | bunch of wires coming from it . And then we | |
00:24 | have some fun item that we're trying to run , | |
00:26 | such as a light or a fan , you know | |
00:28 | , stuff that you plug into power points or need | |
00:31 | a battery . For the first thing we're going to | |
00:33 | consider is this part here , which is the power | |
00:35 | source now , power source of battery or a power | |
00:38 | point , it provides the voltage . And when we | |
00:41 | talk about aims law , we give this the letter | |
00:43 | . The voltage is measured in volts and they are | |
00:47 | also have the unit of V there and pretty much | |
00:51 | what this is . It's the electrical potential between two | |
00:55 | points here . So pretty much a nice way of | |
00:57 | saying the pressure of pushing electrons down a while . | |
01:01 | But you can just think about this as being power | |
01:05 | . The second part that we have is the actual | |
01:07 | power that is running along the wires here . And | |
01:10 | I guess if we could actually have a look at | |
01:12 | this wire hand , we could open it up and | |
01:14 | we can see how much electricity or how many electrons | |
01:17 | are running past a given point at a given amount | |
01:20 | of time . This flow rate , this flow rate | |
01:23 | is called the current . The current is the flow | |
01:26 | rate of electrons going past a particular point . And | |
01:29 | it's given the letter When we give homes law of | |
01:31 | I we measure current in eps which have the letter | |
01:37 | . I now look , I I think it might | |
01:40 | actually stand for intensity or something like this . I'm | |
01:43 | not 100% certain on that one . I don't know | |
01:45 | why they didn't get the letter C . Maybe it's | |
01:46 | going to confuse people with a cool . Um , | |
01:48 | but we use the letter I for that . So | |
01:50 | current is the amount over electrons flowing down this wire | |
01:54 | . And first off what arms law says is the | |
01:57 | following . It says that when we consider voltage and | |
02:01 | current , that voltage is directly proportional to the current | |
02:06 | . That is to say if you were to increase | |
02:08 | the voltage in this battery here , you would increase | |
02:11 | the current going along the wires there . And if | |
02:13 | you were to decrease the voltage of the battery here | |
02:16 | , you would decrease the current going along the wires | |
02:19 | . Now , these are not the only sets of | |
02:21 | numbers that we need to consider with arms Law , | |
02:23 | there is one last set of numbers that we need | |
02:25 | to think about and that is for resistance , which | |
02:30 | when we talk about arms law is given the letter | |
02:33 | ah and resistance is measured in homes , which is | |
02:36 | given the greek letter omega . Now , resistance , | |
02:41 | if you imagine as electrons are moving along this wire | |
02:44 | , they have all sorts of parts of the wire | |
02:46 | that are causing resistance there impeding the actual flow of | |
02:50 | electrons . It could be that they're made of a | |
02:52 | different material that has more islands on it that slow | |
02:55 | the electrons as they go along the wire might be | |
02:57 | thinner , the wire might be longer and all of | |
03:00 | these contribute to the resistance of that particular wire . | |
03:04 | So how do you know what the resistance of a | |
03:07 | particular wire is ? Well , it's pretty simple to | |
03:09 | work out . What we would do is the following | |
03:12 | . We could get the voltage and we could divide | |
03:15 | that by the current and that would give us the | |
03:18 | resistance . And this here is Homes Law . The | |
03:22 | resistance in Homes is equal to the voltage , divided | |
03:26 | by the current . Now , this is usually written | |
03:28 | a little bit differently . And you might have seen | |
03:29 | this written depending on whether we're talking about voltage , | |
03:32 | current or resistance . We could change this all around | |
03:36 | and we can actually say , okay , what we | |
03:37 | have is we have the voltage and that's equal to | |
03:40 | the current multiplied by the resistance . Or we could | |
03:43 | also say that we have the current and that is | |
03:47 | equal to the voltage divided by the resistance , depending | |
03:50 | on how we ordered that particular equation . But just | |
03:52 | one little thing , there's a really , really easy | |
03:54 | way that we can actually remember this and I'm going | |
03:56 | to show you this right now . We can put | |
03:58 | all of this together in a triangle known as the | |
04:01 | OEMs Law triangle , where we can say voltage is | |
04:05 | equal to the current multiplied by the resistance . Let | |
04:09 | me show you how this particular triangle here works . | |
04:12 | So so we wanted to work out voltage here . | |
04:14 | We put our finger over the voltage and as you | |
04:17 | can see , current is sitting next to resistance there | |
04:20 | . It means we multiply these guys . So voltage | |
04:22 | is equal to current . Multiplied resistance . Say we | |
04:25 | were trying to work out the current . I put | |
04:26 | my finger right here and I could say the current | |
04:29 | is equal to the voltage over the resistance voltage divided | |
04:33 | by the resistance . Finally , we can look at | |
04:35 | the resistance and I can say , okay , what | |
04:37 | we want to do is we want to know what | |
04:38 | the resistance is . The resistance we put our finger | |
04:40 | here is equal to the voltage divided by the current | |
04:44 | . So as you can see here this saves you | |
04:47 | remembering a whole bunch of formulas , you have it | |
04:49 | all written there and all you really need to know | |
04:51 | is that voltage is equal to current , multiplied by | |
04:55 | resistance . You draw a triangle there and then you | |
04:57 | can start working at all sorts of things there . | |
05:00 | But as you can see voltage current resistance are totally | |
05:03 | related to one another . So let's do some problems | |
05:06 | that you might encounter with James Law . So I'll | |
05:09 | get rid of the used to start off with and | |
05:11 | once again I'll draw my own law triangle over here | |
05:15 | . Okay so always a good way to start . | |
05:17 | I'll keep it there and it's going to be voltage | |
05:20 | is equal to the current , multiplied by the resistance | |
05:24 | . So I have my own law triangle . Now | |
05:27 | let's go through and put some values into our particular | |
05:30 | diagram here . We'll get a bit fancy with our | |
05:32 | diagrams and do some proper diagrams in a minute . | |
05:34 | But let's start with this diagram and say for instance | |
05:37 | we had a six volt battery . And then what | |
05:41 | we did is we got an ammeter and we're actually | |
05:44 | measured how much current is going through the wires here | |
05:48 | . And when we did that we found out that | |
05:49 | we had a current of 1.5 amps . Okay I | |
05:55 | is equal to 1.5 amps . And you know what | |
05:57 | I'm going to ask are we going to say ? | |
05:59 | Okay well what is the resistance equal to ? Okay | |
06:02 | . So how much is resistance and how do we | |
06:06 | go through and work that out ? Well it's pretty | |
06:07 | simple . We use our Homes law triangle . Here | |
06:09 | we go . The resistance . Put our finger here | |
06:12 | and it's equal to the voltage over the current . | |
06:16 | So equals the voltage over the current . All right | |
06:19 | , let's work this out . What's the voltage ? | |
06:21 | Well , you can see it's 6V and the current | |
06:23 | is 1.5 amps . Six divided by 1.5 . We | |
06:28 | get our answer . Six divided by 1.5 . We | |
06:31 | have four homes . Is the resistance . Cool . | |
06:36 | Well let's do another one of these . So let's | |
06:39 | draw one more circuit up . I'm going to draw | |
06:40 | the proper schematics on this one this time . So | |
06:43 | first off , we have the power source and this | |
06:45 | is how you draw these guys . We have the | |
06:47 | big line here , which is the positive , the | |
06:49 | little line here , which is the negative . We | |
06:51 | have the wire coming off from that . And we're | |
06:53 | going to show resistance . Resistance is shown through this | |
06:57 | line here , This symbol here and then the conductor | |
07:00 | goes all the way back around to the negative terminal | |
07:04 | there . Let's put some values on our diagram . | |
07:06 | Okay , so what we have here is an 18 | |
07:09 | volt battery and we have a resistance that we know | |
07:12 | which is 24 homes . And you know , we're | |
07:15 | gonna be trying to work out , we're going to | |
07:17 | try and work out what the current is . So | |
07:20 | how do we go about doing this ? Well , | |
07:22 | first off , let's draw up our homes law triangle | |
07:26 | . We have voltage eagles , current multiplied by resistance | |
07:30 | . We're trying to work out the current right here | |
07:32 | . So this is the current is going to be | |
07:34 | equal to the voltage divided by the resistance . Okay | |
07:39 | , so what have we got here ? We have | |
07:40 | the voltage which is 18V . We have the resistance | |
07:44 | which is 20 for OEMs and we can work this | |
07:48 | out 18 divided by 24 . We get our answer | |
07:51 | which is a current of 0.75 apps . Okay , | |
07:57 | let's do some more of these . So I'm gonna | |
07:58 | put up five more of these and do as many | |
08:00 | as you need to . It's well worth getting used | |
08:02 | to these as they are needed in the next steps | |
08:04 | . When we look at series and parallel circuits by | |
08:06 | the way , if you like this video , let | |
08:07 | me know and subscribe . But here's some more questions | |
08:11 | how many nights I was gonna do ? We're gonna | |
08:13 | do five more . Okay . The first of five | |
08:17 | questions an iPod uses a 1.5 volt battery . It | |
08:22 | has a current of 0.01 apps . What is the | |
08:26 | resistance in the circuit ? So you know how we're | |
08:28 | going to solve this . First off , we're going | |
08:30 | to draw up our homes law triangle . That voltage | |
08:35 | is equal to current multiplied by resistance . And we're | |
08:38 | trying to work out the resistance . The resistance is | |
08:40 | equal to the voltage divided by the current . Resistance | |
08:44 | equals voltage divided by the current . And this is | |
08:48 | going to be equal to the following . We have | |
08:50 | a voltage of 1.51 point five volts and we have | |
08:54 | a current of 0.1 amps . Nice and easy . | |
09:00 | 1.5 divided by 0.1 We get our answer here . | |
09:05 | We have a resistance of 150 homes Nice and easy | |
09:11 | . Cool . What about we do a second question | |
09:14 | . Okay , a second question . A 12 volt | |
09:17 | car battery runs a headlight whose circuit has a resistance | |
09:20 | of 15 homes . How much is the current we're | |
09:22 | talking about here ? So what would I do first | |
09:25 | ? I draw my Homes Lord Triangle up . And | |
09:27 | I'm gonna say voltage equals current multiplied by resistance . | |
09:31 | We're trying to work out the current here . So | |
09:33 | current is equal to voltage Divided by resistance . So | |
09:37 | current is equal to voltage divided by resistance which is | |
09:41 | equal to the following . The voltage is 12V . | |
09:45 | We have the resistance which is 15 homes . And | |
09:49 | we're gonna get the answer . It's going to be | |
09:51 | an amps . 12 divided by 15 . We get | |
09:54 | our answer of 0.8 amps the current 0.8 apps . | |
09:59 | These are pretty easy . Right ? Okay . Third | |
10:02 | question . A light bulb has a resistance of five | |
10:05 | homes with a maximum current of 10 apps . What | |
10:08 | is the maximum voltage that can be used ? So | |
10:11 | once again let's put our Homes Law Triangle there . | |
10:14 | Good practice . Just get really used to it , | |
10:16 | voltage equals current , multiplied by resistance . We're trying | |
10:20 | to work out voltage . So we're gonna go voltage | |
10:22 | equals current , multiplied by resistance . Nice and easy | |
10:26 | when it's gonna be multiplying we have a current which | |
10:29 | is 10 amps and we have a resistance which is | |
10:32 | five homes . So five OEMs . What we get | |
10:36 | 10 times five . We have 50 volts . So | |
10:40 | the maximum voltage that can be used is 50 volts | |
10:43 | . Alright , our fourth question . And you can | |
10:45 | see I've even stopped them and writing proper questions these | |
10:47 | days we have 41.5 volt batteries . So four by | |
10:51 | 1.5 . We have total of six volts running into | |
10:54 | this particular circuit . And we have the bulb which | |
10:57 | has a resistance of three homes . Okay , So | |
11:00 | what current is needed to power this ? All right | |
11:03 | . So , how we go about doing this ? | |
11:05 | All right , Pretty simple . We draw up our | |
11:08 | triangle and we say that voltage is equal to current | |
11:12 | , multiplied by resistance . We're trying to work out | |
11:15 | the current . So the current here is equal to | |
11:18 | the voltage divided by the resistance . Nice and simple | |
11:22 | . We have the voltage that is six volts . | |
11:25 | And we have the resistance of three homes and everything | |
11:29 | works out nice and easy . Six divided by three | |
11:31 | . We have 22 amps . So we have two | |
11:34 | amps of current running through that wire . All right | |
11:37 | , we're going to get to that last question . | |
11:39 | Okay , Final Question . Toy has 31.5 volt batteries | |
11:43 | . The current is 0.5 amps . What is the | |
11:45 | resistance ? So let's draw this up first . We | |
11:48 | have our Homes law . Triangle voltage equals current times | |
11:53 | resistance . We're trying to work out the resistance . | |
11:55 | So the resistance here is going to equal the voltage | |
11:59 | divided by the current . Easy . All right . | |
12:02 | So what's the voltage ? It has three times 1.5 | |
12:05 | batteries . So three times 1.5 we have 4.5 volts | |
12:10 | . So let's put that in 4.5 volts And the | |
12:13 | current is 0.5 amps . Let's put that in 0.5 | |
12:17 | amps 4.5 divided by 0.5 . That is going to | |
12:22 | equal nine . And the unit we use for resistance | |
12:24 | once again is Homes . Because OWNS is all about | |
12:28 | resistance . Anyway , Thank you for watching . There | |
12:31 | is an upcoming video where we're going to be looking | |
12:33 | at series and parallel circuits and it's really worth knowing | |
12:36 | your Homes law if we're going to get into those | |
12:39 | anyway . I hope you like that video . Like | |
12:41 | subscribe . You know the rest . Thank you for | |
12:44 | watching . See you next time . Bye . |
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