The Quadratic Formula | MathHelp.com - By MathHelp.com
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00:0-1 | to solve this equation Using the quadratic formula . Remember | |
00:05 | from the previous example , the quadratic formula states that | |
00:10 | the variable we're solving for in this case x is | |
00:16 | equal to negative B plus or minus the square root | |
00:22 | of B squared minus four ac All over to a | |
00:31 | . The values for a B and C . In | |
00:33 | the formula Come from the coefficients on our three terms | |
00:38 | in the tri no meal . The value for A | |
00:43 | comes from the coefficient on the X square term , | |
00:47 | Which in this case is one . So we say | |
00:50 | that A equals one . The value for B comes | |
00:56 | from the coefficient on the x term , which in | |
00:59 | this case is -3 . So we say that B | |
01:03 | equals -3 . And the value for C comes from | |
01:09 | the constant term which in this case is negative four | |
01:13 | . So we say C equals negative four , Plugging | |
01:19 | these three values in for AB&C . Into the quadratic | |
01:23 | formula we have X equals negative B which is negative | |
01:32 | of negative three , or positive three . Yeah plus | |
01:37 | or minus the square root of B squared which is | |
01:43 | negative three squared or positive nine minus four times A | |
01:52 | which is one . Mhm times C which is negative | |
01:56 | for All over to a which is two times 1 | |
02:05 | or two . Simplifying inside the radical we have X | |
02:14 | equals three plus or minus the square root of nine | |
02:20 | minus four times one times negative four , which is | |
02:24 | nine plus 16 over to simplifying further inside the radical | |
02:34 | We have x equals three plus or minus the square | |
02:39 | root of 25 . Over to EN Route 25 is | |
02:46 | just five so we have three plus or -5 over | |
02:53 | to . So our solution is either three plus 5/2 | |
03:00 | Which is 8/2 or four or 3 -5/2 Which is | |
03:10 | negative 2/2 or negative one . |
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