Factoring by Grouping | MathHelp.com - By MathHelp.com
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| 00:0-1 | If you're asked to factor this problem , you'll soon | |
| 00:02 | realize that there is no greatest common factor for all | |
| 00:06 | four of these terms And it's not set up as | |
| 00:10 | a try no meal that can be factored as the | |
| 00:12 | product of two by no meals . So we need | |
| 00:15 | to figure out a new way of factoring this problem | |
| 00:19 | . The way you do it is by grouping terms | |
| 00:22 | together . If we group the first two terms together | |
| 00:27 | , X cubed minus two , X squared and the | |
| 00:31 | last two terms together Positive four X -8 , we | |
| 00:37 | can factor out a greatest common factor from our first | |
| 00:41 | group of terms and the greatest common factor from our | |
| 00:44 | last group of terms . The greatest common factor for | |
| 00:49 | X cubed minus two , X squared is X squared | |
| 00:55 | . That leaves you with x minus two . Inside | |
| 01:00 | the parentheses The greatest common factor for positive four , | |
| 01:05 | X -8 is positive for Mhm . That leaves you | |
| 01:10 | with X -2 . Also inside the parentheses . Now | |
| 01:17 | we can finish it just like the last problem you | |
| 01:19 | were doing , since there's an X -2 in each | |
| 01:22 | of these two terms , it factors out , So | |
| 01:27 | we have X -2 times what's left inside the parentheses | |
| 01:33 | , which is x squared plus four oh and that's | |
| 01:40 | your answer . |
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