Solving Quadratic Equations by Square Root Method | MathHelp.com - By MathHelp.com
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| 00:0-1 | the equation , a squared minus 18 equals zero is | |
| 00:04 | called a quadratic equation because we have a squared term | |
| 00:10 | as our highest power in the past . We've solved | |
| 00:14 | quadratic equations by first setting the equation equal to zero | |
| 00:20 | . Then factoring Notice however , that a squared -18 | |
| 00:27 | does not factor . So we must use a different | |
| 00:30 | strategy here . Our first step in this problem is | |
| 00:34 | to get the a square term by itself By adding | |
| 00:39 | 18 to both sides . That gives us a squared | |
| 00:46 | equals 18 . Next we must get the A by | |
| 00:52 | itself . And in order to do that we do | |
| 00:55 | the opposite of what is happening to a And since | |
| 00:59 | a is being squared , the opposite of squaring is | |
| 01:04 | square rooting . So to get a by itself , | |
| 01:08 | we square root both sides of the equation on the | |
| 01:14 | left , the square today squared is A and on | |
| 01:20 | the right . Remember the following rule when square rooting | |
| 01:24 | both sides of an equation . Always use plus or | |
| 01:28 | minus so on the right side of the equation we | |
| 01:32 | have plus or minus Route 18 . Finally , always | |
| 01:40 | break down your square root as much as possible , | |
| 01:44 | 18 is two times nine and nine is 3 times | |
| 01:50 | three , so we have a pair of threes , | |
| 01:53 | which means that a three comes out of the radical | |
| 01:56 | and a two stays inside . So our answer is | |
| 02:01 | a equals plus or -3 route to . |
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