Algebra for Dummies | MathHelp.com - By MathHelp.com
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00:0-1 | we start this problem by applying the power rule for | |
00:04 | each set of parentheses to simplify three . M to | |
00:09 | the fifth . And squared We first square the coefficient | |
00:14 | of three to get nine . Then multiply each of | |
00:20 | our exponents by two . So we have five times | |
00:25 | 2 which gives us em to the 10th and think | |
00:30 | of N as end to the first . So one | |
00:33 | times two is 2 and we have and square To | |
00:39 | simplify to MN to the 4th cubed . We would | |
00:44 | first cube are coefficient of two To get two times | |
00:48 | 2 times two or 8 . Think of em as | |
00:54 | M two the first and multiply each of the exponents | |
00:59 | times three . So one times three is three and | |
01:03 | we have M to the 3rd and four times 3 | |
01:08 | is 12 . So we have N to the 12 | |
01:14 | next we multiply these two terms together . And to | |
01:18 | do that we must apply the product rule from the | |
01:21 | last section . Remember we can simply multiply the coefficients | |
01:26 | together nine times 8 is 72 , but we must | |
01:32 | add the exponents on the like basis . So M | |
01:38 | to the 10th times M to the third is M | |
01:42 | to the 13th , And then squared times end to | |
01:47 | the 12th is N To the 14th . So our | |
01:53 | answer is 72 M2 , the 13th and to the | |
01:57 | 14th . |
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