Standard Form of a Line | MathHelp.com - By MathHelp.com
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| 00:0-1 | So let's say we're asked to convert the equation of | |
| 00:03 | this line from slope intercept to Standard form . Remember | |
| 00:10 | that Standard Form cannot have any fractions in it . | |
| 00:14 | So our first step in this problem is to get | |
| 00:17 | rid of the fraction by multiplying both sides of the | |
| 00:20 | equation by three . On the left we have three | |
| 00:33 | Y . And on the right we distribute the three | |
| 00:39 | through both terms inside the princes to get three times | |
| 00:44 | two thirds X , which is two X Plus three | |
| 00:50 | times 4 which is 12 . In our next step | |
| 00:57 | we move the X term to the left side of | |
| 01:00 | the equation By subtracting two x from both sides . | |
| 01:09 | That gives us negative two X plus three Y equals | |
| 01:15 | 12 . Notice that I put the X term first | |
| 01:21 | on the left side of the equation so that this | |
| 01:23 | will eventually match up with Standard Form which is written | |
| 01:28 | A X plus B , Y equals C . Finally | |
| 01:34 | remember that in standard form the coefficient of the X | |
| 01:38 | term must be positive and in this case we have | |
| 01:42 | a negative coefficient . So our final step would be | |
| 01:46 | to divide Both sides of the equation by -1 . | |
| 01:53 | To get to X -3 y equals negative 12 . |
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