Algebra Word Problems | MathHelp.com - By MathHelp.com
Transcript
| 00:0-1 | Let's start by reading this problem through . one Number | |
| 00:04 | is four times as large as another . There's some | |
| 00:07 | is 45 . Find the numbers . The reason that | |
| 00:13 | students get intimidated by word problems is they try to | |
| 00:16 | look at all the information at once . The best | |
| 00:20 | way to approach a word problem is to break it | |
| 00:23 | down sentence by sentence . So let's take a look | |
| 00:27 | at the first sentence in this problem . One number | |
| 00:30 | is four times as large as another . The first | |
| 00:34 | sentence is going to tell us what variables will use | |
| 00:37 | to represent our numbers . So if you use X | |
| 00:41 | to represent one of our numbers and one number is | |
| 00:46 | four times as large as another . We can use | |
| 00:50 | four x to represent our other number and always label | |
| 00:57 | your variables . Let's call X . Our first number | |
| 01:03 | . Mhm And four X . Our second number . | |
| 01:09 | Now let's look at the 2nd sentence . There's some | |
| 01:13 | is 45 . The second sentence will tell you how | |
| 01:17 | you're going to set up your equation . There are | |
| 01:21 | some If our variables are X and four X will | |
| 01:25 | be X plus four . X is means equals 45 | |
| 01:37 | . Oh now we have an equation and we can | |
| 01:40 | solve for X . We start by simplifying the left | |
| 01:44 | side to get five x equals 45 , Divide both | |
| 01:50 | sides by five And x equals nine . So our | |
| 01:59 | first number X equals nine and our second number four | |
| 02:05 | X equals 36 . So our answers to this problem | |
| 02:12 | are nine and 36 . A common mistake would be | |
| 02:18 | to say that your answer is just nine . Make | |
| 02:22 | sure you go back up to where you labeled your | |
| 02:24 | variables and give both answers to the problem . |
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