Systems of Equations with Fractions | MathHelp.com - By MathHelp.com
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00:0-1 | to solve this system of equations by substitution . Since | |
00:05 | our first equation tells us that y equals 1/3 x | |
00:10 | -1 . We can substitute this one third X minus | |
00:16 | one in for the Why ? In our second equation | |
00:22 | Which becomes three X -2 times Prince sees one third | |
00:29 | X minus one equals four . Now we can solve | |
00:36 | for X by first distributing this negative to through the | |
00:39 | Prince cease to get three X minus two thirds X | |
00:45 | plus two equals four . And now we need to | |
00:49 | get rid of the fraction by multiplying both sides of | |
00:53 | the equation by three to get nine X minus two | |
01:03 | . X plus six equals 12 . Simplifying the left | |
01:09 | side . We have seven X plus six equals 12 | |
01:14 | . Some track six from both sides And seven x | |
01:19 | equals six . To solve for X . We divide | |
01:23 | both sides by seven . Mhm And notice that x | |
01:28 | equals the fraction 6 7th . To find why we | |
01:33 | plug six sevens back in for X . In our | |
01:39 | first equation to get Y equals 1 3rd Times France | |
01:46 | . C 6 7th minus one . Notice that to | |
01:52 | solve for why we're gonna need to deal with some | |
01:55 | fractions . Simplifying the right side of this equation . | |
02:01 | We have one third time six sevens So we can | |
02:05 | cross cancel the six and the 3-2 and one . | |
02:10 | We have one times two which is two and one | |
02:14 | time seven which is seven . So why equals 2/7 | |
02:19 | minus one which can be thought of as Y equals | |
02:23 | 2/7 minus 1/1 . Uh huh . And we can | |
02:32 | simplify this by finding a common denominator of seven . | |
02:36 | So multiply top and bottom of the second , fraction | |
02:40 | by seven to get y equals 2/7 minus 7/7 which | |
02:46 | simplifies to y equals negative five sevens . So the | |
02:52 | solution to this system is 6 7th -5 7th |
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