Systems of Equations with Fractions | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Systems of Equations with Fractions | MathHelp.com - Free Educational videos for Students in k-12


Systems of Equations with Fractions | MathHelp.com - By MathHelp.com



Transcript
00:0-1 to solve this system of equations by substitution . Since
00:05 our first equation tells us that y equals 1/3 x
00:10 -1 . We can substitute this one third X minus
00:16 one in for the Why ? In our second equation
00:22 Which becomes three X -2 times Prince sees one third
00:29 X minus one equals four . Now we can solve
00:36 for X by first distributing this negative to through the
00:39 Prince cease to get three X minus two thirds X
00:45 plus two equals four . And now we need to
00:49 get rid of the fraction by multiplying both sides of
00:53 the equation by three to get nine X minus two
01:03 . X plus six equals 12 . Simplifying the left
01:09 side . We have seven X plus six equals 12
01:14 . Some track six from both sides And seven x
01:19 equals six . To solve for X . We divide
01:23 both sides by seven . Mhm And notice that x
01:28 equals the fraction 6 7th . To find why we
01:33 plug six sevens back in for X . In our
01:39 first equation to get Y equals 1 3rd Times France
01:46 . C 6 7th minus one . Notice that to
01:52 solve for why we're gonna need to deal with some
01:55 fractions . Simplifying the right side of this equation .
02:01 We have one third time six sevens So we can
02:05 cross cancel the six and the 3-2 and one .
02:10 We have one times two which is two and one
02:14 time seven which is seven . So why equals 2/7
02:19 minus one which can be thought of as Y equals
02:23 2/7 minus 1/1 . Uh huh . And we can
02:32 simplify this by finding a common denominator of seven .
02:36 So multiply top and bottom of the second , fraction
02:40 by seven to get y equals 2/7 minus 7/7 which
02:46 simplifies to y equals negative five sevens . So the
02:52 solution to this system is 6 7th -5 7th
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