College Algebra | MathHelp.com - By MathHelp.com
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00:00 | think of the one in this problem as 1/1 . | |
00:07 | The common denominator for 41 and X is four X | |
00:13 | . So multiply both sides of the equation by four | |
00:17 | x . To get rid of the fractions . When | |
00:26 | multiplying four X times X minus 2/4 before is cancel | |
00:32 | . And we have X times parentheses X minus two | |
00:39 | . four x times positive one is positive for x | |
00:44 | . And when multiplying four X times 12 over X | |
00:48 | the X's cancel . And we have 12 times four | |
00:52 | or 48 distributing through the parentheses . We have X | |
01:00 | squared minus two , X plus four X equals 48 | |
01:08 | . And simplifying further on the left side , we | |
01:11 | have X squared plus two , X equals 48 . | |
01:19 | Notice that our equation has an X squared term in | |
01:23 | it . In this situation remember we must first set | |
01:28 | the equation equal to zero , then factor . So | |
01:33 | our next step is to move the 48 to the | |
01:36 | left side of the equation By subtracting 48 from both | |
01:40 | sides . To get x squared plus two , X | |
01:47 | minus 48 equals zero . Now we can factor to | |
01:54 | get X plus eight times , X minus six equals | |
02:01 | zero . So either X plus eight equals zero , | |
02:06 | or x minus six equals zero , which means that | |
02:10 | our solutions set is negative eight six . Finally make | |
02:17 | sure that neither of our solutions will make a denominator | |
02:22 | in the original equation equals zero , which they don't | |
02:27 | . So we can keep both answers . |
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