Algebra Made Easy | MathHelp.com - By MathHelp.com
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00:0-1 | to solve this system of equations by addition , our | |
00:04 | first goal is to cancel out one of the variables | |
00:08 | by adding the two equations together notice that if we | |
00:13 | add these two equations together are plus Y and minus | |
00:19 | Y will cancel out . And on the left side | |
00:23 | three X plus seven X is 10 X . and | |
00:28 | on the right side five plus 15 is 20 , | |
00:34 | Dividing both sides of the equation by 10 . We | |
00:40 | find that x equals two . Yeah . To find | |
00:47 | why we simply plug a to back in for X | |
00:52 | in either one of our two given equations . So | |
00:56 | let's go with our first equation . three x plus | |
01:00 | y equals five . If we plug a two back | |
01:04 | in for X , this gives us three times two | |
01:12 | plus Y equals five , which simplifies to six plus | |
01:19 | Y equals five . And subtracting six from both sides | |
01:25 | , we find that why equals negative one , So | |
01:33 | x equals two and y equals negative one . And | |
01:37 | we can write our answer in the form of the | |
01:40 | ordered pair , 2 -1 . |
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