Absolute Value Inequalities | MathHelp.com - By MathHelp.com
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| 00:0-1 | Remember from the previous section , that absolute value represents | |
| 00:04 | distance from zero . So if the absolute value of | |
| 00:08 | X is greater than two , That means that X's | |
| 00:12 | distance from zero is greater than two units . On | |
| 00:17 | a number line . The points that are greater than | |
| 00:19 | two units from zero would be all points greater than | |
| 00:23 | two , or all points less than -2 . So | |
| 00:29 | if we're given this absolute value inequality , we can | |
| 00:32 | split things up into two separate inequalities . Either X | |
| 00:38 | is greater than two , or X is less than | |
| 00:44 | -2 . Our first inequality will look just like the | |
| 00:49 | original problem minus the absolute value signs . In our | |
| 00:54 | second inequality , we must switch the direction of the | |
| 00:57 | inequality sign and make the right side negative . The | |
| 01:03 | word that goes between our two inequalities is based on | |
| 01:06 | the direction of the inequality sign in the original problem | |
| 01:11 | . Since we have a greater than sign in the | |
| 01:14 | original problem , we use the word or so our | |
| 01:19 | final answer can be written . The set of all | |
| 01:22 | X is such that X is greater than two , | |
| 01:27 | or X is less than -2 . |
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