Volume of a Pyramid | MathHelp.com - By MathHelp.com
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| 00:0-1 | In this example , we're asked to find the volume | |
| 00:02 | of the given pyramid . To find the volume of | |
| 00:05 | a pyramid . We use the formula volume equals one | |
| 00:10 | third times the area of the base times the height | |
| 00:15 | . And notice that the base of the pyramid is | |
| 00:17 | a rectangle . So to find the area of the | |
| 00:20 | base , we use the formula for area of a | |
| 00:23 | rectangle , which is area equals length times width , | |
| 00:29 | since the length of the rectangle is eight yards and | |
| 00:32 | the width of the rectangle is seven yards . We | |
| 00:35 | can plug this information into the formula to get eight | |
| 00:40 | yards times seven yards , Which equals 56 yards squared | |
| 00:52 | . So the area of the rectangle or the area | |
| 00:54 | of the base of the pyramid is 56 square yards | |
| 00:59 | . Now to find the volume of the pyramid , | |
| 01:02 | We take 1/3 Times the area of the base , | |
| 01:06 | which is 56 square yards . Yeah , yeah , | |
| 01:11 | yeah . Times the height of the pyramid , which | |
| 01:15 | is 12 yards . Okay ? Yeah . 1/3 times | |
| 01:22 | 12 yards is four yards . And we have four | |
| 01:27 | yards . Times 56 square yards , Which equals 224 | |
| 01:36 | yards cubed . So the volume of the given pyramid | |
| 01:40 | is 224 cubic yards . A common mistake in this | |
| 01:48 | problem is to forget the 1/3 in the formula for | |
| 01:51 | volume of a pyramid . Be aware of this common | |
| 01:54 | mistake so you can make sure to avoid it . |
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