Algebra Lesson Plans | MathHelp.com - By MathHelp.com
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| 00:0-1 | to solve this system of equations . By addition , | |
| 00:04 | notice that when we add these two equations together , | |
| 00:08 | neither one of our variables will cancel out in this | |
| 00:14 | situation , we need to set things up so that | |
| 00:17 | when we do add our two equations together , one | |
| 00:20 | of the variables will cancel out . Notice that we | |
| 00:24 | have a two a . In our first equation . | |
| 00:29 | If we had a negative to weigh in our second | |
| 00:31 | equation , then the A's would cancel out . In | |
| 00:37 | order to create a negative to A . In the | |
| 00:39 | second equation . We simply multiply both sides of the | |
| 00:44 | second equation . Bye negative two . Yes . Rewriting | |
| 00:57 | both equations , we have to A plus five B | |
| 01:04 | equals 11 . And for our second equation we have | |
| 01:09 | negative two way plus eight B equals 28 . Now | |
| 01:19 | when we add our two equations together are A terms | |
| 01:23 | will cancel out And we're left with 13 B equals | |
| 01:29 | 39 Dividing both sides by 13 B equals three . | |
| 01:39 | To solve for a plug a three in for B | |
| 01:43 | in either one of our two original equations . So | |
| 01:48 | let's go with our first equation to A plus five | |
| 01:51 | B equals 11 . If we plug a three back | |
| 01:56 | in for B , that gives us two A plus | |
| 02:02 | five times three equals 11 . That simplifies to two | |
| 02:09 | . A plus 15 equals 11 . Subtracting 15 from | |
| 02:14 | both sides gives us to A equals negative four . | |
| 02:20 | Finding both sides by two . We have A equals | |
| 02:25 | negative two , Since a equals negative two And B | |
| 02:30 | equals three . Our answer is the ordered pair negative | |
| 02:36 | 23 Notice that A comes before B . In . | |
| 02:44 | Our answer always put your answer in alphabetical order . |
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