Rational Equations | MathHelp.com - By MathHelp.com
Transcript
00:0-1 | Start this problem by changing the -3 to plus a | |
00:06 | negative three to find the common denominator notice that we | |
00:11 | must factor y squared minus three y minus 10 . | |
00:16 | As Y -5 times y plus two . So we | |
00:21 | have five over , y plus two equals 13 over | |
00:30 | y minus five times Y plus two plus negative three | |
00:37 | Over . Why -5 . You can see that our | |
00:42 | common denominator is why -5 times y plus two . | |
00:47 | So we multiply both sides of the equation by this | |
00:52 | common denominator . Yeah , on the left , the | |
01:05 | Y plus two is cancel . So we have five | |
01:09 | times . Prince sees why -5 on the right . | |
01:14 | In the first fraction the denominator cancels out entirely . | |
01:18 | So we have 13 in the second fraction the y | |
01:25 | minus fives cancel . So we have -3 times prince | |
01:30 | sees y plus two distributing through the parentheses , we | |
01:36 | have five , y minus 25 equals 13 minus three | |
01:43 | y minus six . And solving from here we find | |
01:48 | that y equals four . Notice that back in the | |
01:56 | original problem , the variable why appears in the denominators | |
02:02 | . In this situation , we must plug our answer | |
02:05 | of four back in . For all the wise in | |
02:09 | the original equation . To see if it makes any | |
02:12 | of these denominators equal zero . If it does make | |
02:17 | a denominator equal to zero , then four cannot be | |
02:21 | a solution to the equation . So the answer would | |
02:24 | be the null set . Fortunately in this problem , | |
02:28 | it does not make any of the denominators equal to | |
02:30 | zero , so four is an acceptable answer . Remember | |
02:36 | always check to see if your answer makes any of | |
02:40 | the denominators equal to zero for every problem in this | |
02:44 | section . |
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