Rational Equations | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Rational Equations | MathHelp.com - Free Educational videos for Students in k-12


Rational Equations | MathHelp.com - By MathHelp.com



Transcript
00:0-1 Start this problem by changing the -3 to plus a
00:06 negative three to find the common denominator notice that we
00:11 must factor y squared minus three y minus 10 .
00:16 As Y -5 times y plus two . So we
00:21 have five over , y plus two equals 13 over
00:30 y minus five times Y plus two plus negative three
00:37 Over . Why -5 . You can see that our
00:42 common denominator is why -5 times y plus two .
00:47 So we multiply both sides of the equation by this
00:52 common denominator . Yeah , on the left , the
01:05 Y plus two is cancel . So we have five
01:09 times . Prince sees why -5 on the right .
01:14 In the first fraction the denominator cancels out entirely .
01:18 So we have 13 in the second fraction the y
01:25 minus fives cancel . So we have -3 times prince
01:30 sees y plus two distributing through the parentheses , we
01:36 have five , y minus 25 equals 13 minus three
01:43 y minus six . And solving from here we find
01:48 that y equals four . Notice that back in the
01:56 original problem , the variable why appears in the denominators
02:02 . In this situation , we must plug our answer
02:05 of four back in . For all the wise in
02:09 the original equation . To see if it makes any
02:12 of these denominators equal zero . If it does make
02:17 a denominator equal to zero , then four cannot be
02:21 a solution to the equation . So the answer would
02:24 be the null set . Fortunately in this problem ,
02:28 it does not make any of the denominators equal to
02:30 zero , so four is an acceptable answer . Remember
02:36 always check to see if your answer makes any of
02:40 the denominators equal to zero for every problem in this
02:44 section .
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