Saxon Math Algebra 1 | MathHelp.com - By MathHelp.com
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| 00:0-1 | to solve this equation . Since our variable end is | |
| 00:03 | on both sides of the equation , we need to | |
| 00:06 | put our variables together on one side of the equation | |
| 00:08 | and our numbers together on the other . So let's | |
| 00:11 | put our variables together on the left side of the | |
| 00:14 | equation by adding to end to both sides of the | |
| 00:18 | equation . Yes . Mhm . On the right side | |
| 00:23 | of the equation , the negative to N . And | |
| 00:26 | positive to end cancel each other out . And we | |
| 00:29 | have one and on the left side of the equation | |
| 00:32 | three N plus two , N is five . And | |
| 00:36 | so we have five N plus 11 equals one . | |
| 00:40 | Next let's put our numbers together on the right side | |
| 00:44 | of the equation by subtracting 11 from both sides of | |
| 00:48 | the equation On the left side of the equation , | |
| 00:51 | the positive 11 and -11 cancel each other out and | |
| 00:55 | we have five n . And on the right side | |
| 00:58 | of the equation 1 -11 is -10 . Now , | |
| 01:04 | since N is being multiplied by five , we need | |
| 01:08 | to divide by five on both sides of the equation | |
| 01:11 | , on the left side of the equation , the | |
| 01:13 | fives cancel each other out , and we have N | |
| 01:16 | . And on the right side of the equation negative | |
| 01:19 | 10 , divided by positive five , is negative two | |
| 01:23 | , So an equals -2 , which is the solution | |
| 01:27 | to our equation . Finally , remember to always check | |
| 01:30 | your solution to make sure it's correct . |
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