Geometry Basics | MathHelp.com - By MathHelp.com
| 00:0-1 | in this example we're asked to classify each of the | |
| 00:03 | following pairs of angles as complementary , supplementary or neither | |
| 00:08 | In part a notice that the two angles share a | |
| 00:11 | common side and together they form a right angle which | |
| 00:15 | measures 90°. . If the sum of the measures of | |
| 00:19 | two angles is 90°, , then the angles are complementary | |
| 00:22 | . So here we say that the angles are complementary | |
| 00:29 | . Yeah . In part B notice that the two | |
| 00:39 | angles share a common side and together they form a | |
| 00:42 | straight angle which measures 180°. . If the sum of | |
| 00:47 | the measures of two angles is 180°, , then the | |
| 00:50 | angles are supplementary . So here we say that the | |
| 00:53 | angles are supplementary . Okay , thanks in part C | |
| 01:06 | notice that the two angles joined together to form an | |
| 01:09 | obtuse angle which is neither 90 degrees nor 180 degrees | |
| 01:14 | . So we say that the two angles are neither | |
| 01:17 | complimentary nor supplementary . In part d notice that the | |
| 01:25 | two angles don't share a common side , but if | |
| 01:28 | we join them together they would form a straight angle | |
| 01:31 | , which measures 180°. . So we say that the | |
| 01:35 | angles are supplementary . Yeah . Yeah . It's important | |
| 01:48 | to understand that two angles do not have to share | |
| 01:50 | a common side in order to be complementary or supplementary | |
| 00:0-1 | . |
DESCRIPTION:
This lesson covers permutations. Students learn that a permutation is an arrangement of objects in which the order is important. For example, the permutation AB is different than the permutation BA. Students are then asked to solve word problems involving permutations. For example: Find the number of different ways 6 books can be arranged on a shelf. Note that the number of permutations can be found by multiplying the number of choices for the 1st position (6 books) times the number of choices for the second position (5 books), and so on. So the number of permutations is 6 x 5 x 4 x 3 x 2 x 1, or 720. In other words, there are 720 different ways 6 books can be arranged on a shelf.
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