Algebra 1 Help | MathHelp.com - By MathHelp.com
Transcript
| 00:0-1 | In this equation , our first task is to simplify | |
| 00:04 | the left side . So we start by distributing this | |
| 00:08 | seven through both terms inside the parentheses seven times y | |
| 00:15 | is seven y and seven times negative . Two is | |
| 00:20 | negative 14 . So we have seven Y -14 -4 | |
| 00:27 | . Y equals 10 . The difference between this problem | |
| 00:32 | and the previous example is that you can simplify this | |
| 00:36 | left side one step further by combining seven y minus | |
| 00:41 | four Y to get three Y . Mhm . So | |
| 00:46 | we have three Y -14 equals 10 , and we | |
| 00:53 | can finish this problem in the usual way By adding | |
| 00:56 | 14 to both sides . Mhm . Yeah . Which | |
| 01:03 | gives us three y equals 24 and dividing both sides | |
| 01:09 | by three , Which gives us y equals eight . |
Summarizer
DESCRIPTION:
This lesson covers parallel lines. Students learn that if two parallel lines are cut by a transversal, then corresponding angles are congruent, alternate interior angles are congruent, and same-side interior angles are supplementary. Students are then asked to find missing values based on these concepts.
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