High School Algebra | MathHelp.com - By MathHelp.com
Transcript
| 00:00 | To solve this equation , We start by distributing the | |
| 00:04 | two through the parentheses on the left side . So | |
| 00:09 | we have two times X Which is two x and | |
| 00:15 | two times positive three , Which is positive six . | |
| 00:21 | So our equation now reads two X plus six equals | |
| 00:27 | 20 Solving from here . We subtract six from both | |
| 00:32 | sides of the equation And we have two x equals | |
| 00:38 | 14 and dividing both sides by two , we find | |
| 00:46 | that X equals seven . Yeah . Remember that . | |
| 00:54 | We can check our answer by plugging a seven back | |
| 00:58 | in for X in the original equation and we have | |
| 01:05 | two times parentheses . 7-plus 3 equals 20 seven plus | |
| 01:14 | three is 10 , So we have two times 10 | |
| 01:19 | equals 20 or 20 equals 20 so which is a | |
| 01:26 | true statement . So our answer checks . |
Summarizer
DESCRIPTION:
This lesson covers perimeter word problems. Students learn to solve "Geometry" word problems involving perimeters of rectangles
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