11th Grade Math | MathHelp.com - By MathHelp.com
Transcript
| 00:00 | start this problem by distributing the mono meals through the | |
| 00:04 | binomial inside each set of parentheses . So distributing four | |
| 00:10 | X to the third through three X plus one . | |
| 00:16 | Think of three X as three X to the first | |
| 00:20 | And multiplying are coefficients and adding the exponents . We | |
| 00:25 | have 12 X to the 4th Plus four X to | |
| 00:32 | the 3rd . Think of this minus five X squared | |
| 00:37 | as plus a negative five X squared so that you | |
| 00:42 | know you're distributing a negative five X squared through the | |
| 00:46 | second set of parentheses , Multiplying the coefficients and adding | |
| 00:51 | the exponents . We have negative 10 X to the | |
| 00:57 | 4th minus 25 X to the 3rd . Remember X | |
| 01:06 | can be thought of as X to the first . | |
| 01:10 | The difference between this problem and the last is that | |
| 01:12 | we now have like terms that can be combined 12 | |
| 01:18 | X to the fourth minus 10 X to the fourth | |
| 01:21 | is two X to the fourth and positive for X | |
| 01:26 | to the third minus 25 X to the third is | |
| 01:31 | negative 21 X to the third . So this is | |
| 01:36 | our final answer . |
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