01 - Visualize Roots of Equations - Linear, Quadratic, Cubic, Quartic Solutions - Free Educational videos for Students in K-12 | Lumos Learning

01 - Visualize Roots of Equations - Linear, Quadratic, Cubic, Quartic Solutions - Free Educational videos for Students in k-12


01 - Visualize Roots of Equations - Linear, Quadratic, Cubic, Quartic Solutions - By Math and Science



Transcript
00:00 Hello . Welcome back to the Algebra two course .
00:02 This is Unit nine . The topic of this batch
00:05 of lessons is basically going to be zeroing in on
00:07 solving these quadratic equations . You can also call it
00:11 finding the roots of these quadratic equations . But what
00:14 we're gonna do in this lesson is we're going to
00:15 back up the truck a little bit , zoom out
00:17 a little bit so that we don't forget what we're
00:19 doing . And I have a computer demo that I'm
00:21 gonna do for you here in about 20 seconds .
00:23 That's going to hopefully illuminate a lot of what we're
00:25 talking about before we get back to the board and
00:27 write the math down . So remember the point is
00:30 when we're talking about roots of an equation , What
00:32 we're really doing is we set that equation equal to
00:34 zero . Because those will be the points where the
00:37 graph crosses the X axis . Because those are the
00:39 points where the function is equal to zero . The
00:41 function is the y axis . Right ? So if
00:43 you set it equal to zero , you're finding all
00:45 the points where it crosses that X axis where the
00:47 value is equal to zero . So we have lines
00:50 which are linear guys like this that only crossed the
00:53 X axis in one location . We have quadratic ,
00:56 which look like the parameters we've talked about . They
00:58 generally cross the axis in two locations and then we
01:00 have Q bix and then we have the higher order
01:03 polynomial is beyond that . So what we're going to
01:05 be doing here is covering the general idea of linear
01:08 equations , quadratic cubic , which is the power of
01:11 three and the court equations , which is the power
01:14 of four . So before we get back to the
01:16 board here , let's do that . Computer demo .
01:17 And I'll show you graphically what the roots of these
01:19 different kinds of equations really look like . Okay ,
01:23 welcome back here . What we have here is a
01:25 little demo that I've done here , where I can
01:27 show you the different the graphs of the different kinds
01:30 of equations here . We have linear equations and the
01:32 higher order polynomial beyond that . So the simplest kind
01:35 of equation you can have is a horizontal line .
01:38 So the graph here , it just has three here
01:40 . That means why equals three . That's a horizontal
01:42 line that crosses it at the value of Y is
01:45 equal to three here . The line crosses at the
01:47 value of Y is equal to four . You can
01:49 see that this horizontal line does not cross the X
01:51 access at the X axis at all . So it
01:53 doesn't have any roots . But if we make the
01:56 line a little more interesting , if we put a
01:58 slant to it , then here's the equation of this
02:00 line two X plus four . You can see the
02:02 y intercept is up here at four and it has
02:05 a slope of to rise over run , that's what
02:07 this means , right . And you can see that
02:08 in general winning line is slanted , it is going
02:11 across the X axis in one location . Now I
02:13 can play around with this line , I can bring
02:16 it down like this . So the y intercept is
02:17 negative three down here and you can see that the
02:20 root here of this first order equation . See the
02:23 power of X here is just a one . So
02:25 we have a first order route here which basically means
02:29 we expect to have one solution when we set this
02:32 guy equal to zero , which means one crossing point
02:34 . Here's the crossing point . Now , no matter
02:36 what I do , even if I make the lines
02:38 slant the other direction . If I shift it up
02:41 or down , basically move the line around , it's
02:43 only going across the X axis in one location has
02:45 one root because the power of X is just a
02:48 number one . Now let's go up . And I'm
02:50 gonna drag my slider here to make a quadratic .
02:53 So this is a simple quadratic and I can reset
02:55 the rest of these guys here to kind of reset
02:57 what I have here . So this is the quadratic
02:59 , Y is equal to x squared If I change
03:02 it to make it for instance , X squared minus
03:04 three . This is what this curve looks like now
03:06 the highest power of X here is a two .
03:08 That means it's a quadratic . All quadratic have a
03:10 power of two for the highest power . And because
03:13 the power is too , that means that we have
03:15 to roots of this equation right ? In this case
03:18 one route is where it crosses the X axis here
03:21 , and the other route is where it crosses the
03:23 axis over here . So you can see that there
03:24 are mirror images . Now , as I change the
03:26 graph a little bit , you can see the crossing
03:28 points are in different locations . But there's still two
03:31 routes . Now , if I change very slightly what
03:33 the equation looks like , maybe make the problem or
03:36 more sharp by putting a higher coefficient in front of
03:39 the X squared here . It does change the shape
03:42 of the curve , but we still have two crossing
03:44 points . And with quadratic , sui have always expect
03:47 to have two crossing points because the highest power of
03:49 X is a two , just like in the case
03:51 of a line like this line right here or any
03:55 line in general , we always expect only one crossing
03:57 point because the highest power of X is one here
03:59 . So let's go back up and make it a
04:00 quadratic . Now you can see we have two crossing
04:03 points . You can see there's a crossing point here
04:05 , there's a crossing point here . So we have
04:06 two routes . Now what I want to draw your
04:08 attention to is if I drag this quadratic above the
04:11 X axis so that you see how it never intersects
04:14 this quadratic never intersects the X . Axis at all
04:16 . That means that this function never ever has a
04:19 value where it's equal to zero . So it doesn't
04:22 have any real roots . But as we're gonna learn
04:25 uh here very soon when we talk about the quadratic
04:27 formula , we're going to see that this quadratic equation
04:30 still has two roots , but because we don't have
04:33 any crossings on the X axis , they're not real
04:35 roots . We always have two routes , but it's
04:37 going to turn , we're going to turn out and
04:38 see that when the graph is floating up here ,
04:41 we have two complex roots are imaginary roots . We've
04:44 talked about complex numbers before . So this quadratic equation
04:47 still has two roots . It's just that they're both
04:49 complex and so we can't see them on this graph
04:52 of real numbers , the X and Y graph here
04:54 . So you see , no matter what I do
04:56 , if I move this guy maybe over here ,
04:58 maybe shift away up high . You see down below
05:00 once it crosses down below , we have two real
05:03 roots as I increase it , we still have to
05:05 real roots , we still have to real roots .
05:07 They're getting closer and closer and closer together . We
05:09 have two real roots right here here , we still
05:12 have to real roots , here's one here and here's
05:14 one here . But as I pop over to the
05:15 other side like this , then I have actually no
05:19 real roots , but I still have two routes in
05:21 total . I have to complex roots and we're going
05:23 to learn how to calculate the complex roots with the
05:26 quadratic formula here very soon . All right . One
05:29 more thing I'm gonna say before I leave quadratic here
05:32 is let's do our basic quadratic that's centered on the
05:34 X axis right ? Here are centered on the like
05:37 this guy that the general quadratic like two X squared
05:39 . Or you could say x squared notice here that
05:42 as I uh let me make it a simpler one
05:44 . Let's make make it why is equal to X
05:47 squared ? So here's the general y is equal to
05:49 X squared graph . Right ? Let me drag it
05:51 down below . And you can see that there's two
05:53 routes , one here and one here . Now as
05:56 I move it up higher , let's go farther down
05:58 . You see the roots are very far spaced apart
06:00 because the thing is way below the X . Axis
06:03 as I make this and shift this graph up the
06:05 roots get closer and closer together . You see what's
06:08 happening . They're getting closer here is negative one and
06:10 positive one . And as eventually I get to make
06:13 the graft shift up to this point , the roots
06:16 have gotten so close together that they're right on top
06:18 of each other . The roots were actually right here
06:20 at X . Is equal to zero but there's still
06:22 two of them . It's a quadratic . There has
06:24 to be two routes , they're right on top of
06:26 each other and we call that a double route .
06:28 So it's easy to see when you actually start down
06:30 here . We have double roots , double roots ,
06:32 double roots , double I'm sorry not double roots .
06:34 We have two routes to roots , two routes to
06:36 roots and so on . They're getting closer . Eventually
06:39 we still have to routes that are right on top
06:40 of each other , we call that a double route
06:42 and then as we go above the X axis we
06:44 have don't have any real roots at all , no
06:46 crossing points , but we still have to complex roots
06:49 which will learn about later . Now let's increase it
06:52 to a cubic , This is what a general cubic
06:54 function looks like and I can play with it to
06:56 try to make it more like a , like a
06:58 snake , it's kind of like a snaky function .
07:00 And so this is what a cubic looks like .
07:03 And you can see here have the highest power of
07:05 excess of three . So we expect three roots of
07:08 this equation , three crossing points . So here's a
07:10 crossing point of the X axis , here's another crossing
07:12 point here and here's another one . So there's three
07:14 roots of this equation in general . All cubic functions
07:17 are gonna look like this or they look like a
07:19 mirror image flip down below . In other words ,
07:21 it can go up and down or down and up
07:23 , but it'll still mostly look like a snaky kind
07:25 of function like this . And as I go and
07:28 drag this guy down interestingly , there's only one crossing
07:32 here of this function here . It still looks like
07:33 a like a snake , but we don't have one
07:35 root , which means one real root , we can
07:37 see over here , but you have to remember the
07:40 highest power here is a three . We always have
07:42 to have three roots total . So here we have
07:45 one actual crossing point and we have two other routes
07:48 which you could find . We're going to learn how
07:50 to solve these cubic slater and you'll find out you
07:53 have to complex roots for a total of three to
07:55 complex roots and then the one real root here .
07:58 As I drag the function up , we still have
08:00 to complex roots and then the one real root over
08:03 here . As I drag it up here , we
08:05 have one real root here and notice we have a
08:08 double room now because the function is now touching the
08:11 X axis . And then as I go through it
08:14 and we have three real roots , one , here's
08:16 two and here's three . And as I shift the
08:18 function up , we still have three real roots here
08:20 , three crossing points . And then we have on
08:22 this case we have the function crossing here . That's
08:24 a real route . We have a double room now
08:26 for a total of three routes here . And then
08:28 as the function gets shifted up uh it's a little
08:31 hard to see because it's shifted off the screen .
08:32 That's probably better . We have now a one real
08:35 root here on the negative side . And then we
08:38 only have , we don't have any other crossing points
08:39 . So the other two come up to make two
08:42 more imaginary or complex roots . So the bottom line
08:45 is you always have as many routes as you do
08:47 the highest power . But some of them can be
08:49 complex if you don't have enough crossing points in your
08:52 graph and that's the what it means to get complex
08:56 roots . Those are just routes that can't be displayed
08:58 on a real graph like this . But the real
09:00 crossing points will show up as roots as well .
09:03 Now real quickly we're not gonna go through the cortex
09:05 and higher too much . But let me just show
09:06 you generally what in general cortex function looks like ,
09:09 you can play around with it , make it look
09:10 various ways . So here in general you can see
09:13 it looks like a W . So whereas the cubic
09:15 look like a snake , the cortex look like a
09:17 W . Of course it could be flipped upside down
09:19 to look like an M . As well . But
09:21 if I drag this function down here , then this
09:25 core tech equation , this one here that we have
09:27 printed at the top has to real roots because we
09:29 have two crossing points . But we don't but we
09:32 don't have any more actual crossing points . So the
09:34 other two routes that we expect must be complex .
09:36 So this graph would have to real roots and too
09:39 complex routes that you can't see on this graph as
09:41 I shifted up , it's the same deal . We
09:43 have to real roots and too complex here . We
09:46 have too real and too complex . But now you
09:48 see the graph crosses and four locations . One ,
09:51 23 and four . So this graph has actually four
09:54 real roots and it doesn't have any complex roots .
09:57 And as I shifted up , we have what's let's
10:00 go here here . We have the same deal here
10:02 . 1234 real roots and no complex roots . And
10:06 as we shift , let me see if I can
10:07 get it here and can I have the granularity .
10:09 But as we go up higher above the axis of
10:11 this graph , this equation doesn't have any crossing points
10:15 at all . So all four of these routes must
10:18 be complex . So you can kind of predict from
10:20 the graph how many real and how many complex which
10:23 you're going to have now , I'm just gonna fly
10:24 through the rest of them because after you get to
10:27 the cortex , the rest of them are just kind
10:28 of hard to kind of visualize . But you can
10:30 see 1/5 order equation still kind of looks like a
10:33 snaky function . And if you uh if you push
10:37 it down like here you can see you have now
10:39 five crossing points , 1234 and then five matching the
10:44 five routes that we expect here are the five real
10:46 crossing points . If I shift this equation up ,
10:49 changing it slightly like this now the roots will be
10:52 one real root and all four of the remaining two
10:55 equal five must be complex roots and I can do
10:58 the same thing by dragging it down here . This
10:59 equation has one real root way over here and then
11:02 all of the other four must be complex roots .
11:05 And then in the middle as I shifted up and
11:07 down here you can see you can have various combinations
11:09 here . I have the 45 crossing points in total
11:12 . And just playing around with it more . You
11:13 can you can make crazier , higher order things like
11:16 this . Me see if I can find something interesting
11:19 . Uh Here you have one crossing point . Two
11:21 crossing points . 34 So I only have four crossing
11:25 points that I can see in this function . But
11:27 we know that there must be six routes because it's
11:29 1/6 order polynomial . So we have four real .
11:32 Therefore we must have too complex . So if you
11:34 solve and find all of the roots of this equation
11:36 , then you'll find four crossing points for rail routes
11:39 and then the other two must be complex . And
11:41 then we'll just do one more just because I know
11:43 you're curious . The seventh order . See what I
11:45 can make it look interesting . So this is the
11:47 seventh order polynomial . You can see the graph of
11:49 it , but how many crossing points do we have
11:50 ? One ? 2345 We have five real roots ,
11:55 therefore the other two to make seven must be complex
11:58 roots . So I wanted to show you the general
12:00 idea of what we were doing so that you can
12:02 get uh an idea of what real , what of
12:04 what real roots are and what complex roots really represent
12:08 . But what I want to do here closes ,
12:09 go back to the original thing . When we have
12:12 our general general quadratic equation are famous . F .
12:15 Of X is equal to X squared right ? If
12:18 it has two crossing points , that's too real roots
12:21 . If you have no crossing points at all ,
12:23 that's to purely complex or imaginary roots that you're gonna
12:26 get it when you solve this guy . And then
12:28 right , when it kisses the axis , you have
12:30 to real roots , which we call a double route
12:32 . You can see them getting closer and closer and
12:34 closer together until now they're just basically right on top
12:36 of each other . Uh fucking adjust it here ,
12:39 right here at X . Is equal to zero .
12:40 So now let's go back to the board and wrap
12:42 it up with writing down some equations . All right
12:47 . So now that we've seen the demo of how
12:48 these routes really behave when we have higher and higher
12:51 order polynomial is what we want to do is kind
12:53 of right . Some of the things down to make
12:54 sure you understand and have it all in one place
12:57 . So the simplest kind of equation that we really
12:59 have and learn about is called the linear equation .
13:02 That means it's an equation of a line . And
13:04 we talked about that many , many , many hours
13:06 long time ago in the equation of the line looks
13:08 like this F of X is equal to a X
13:11 plus B . Now A and B can be numbers
13:14 , any number . So it could be two X
13:15 plus three , three x minus five , you know
13:19 , and so on . And you can think of
13:21 this as the slope , whatever this is as a
13:22 slope in front of this and this is the Y
13:24 intercept . And the way that we find the roots
13:27 of this guy is we solve the equation A ,
13:31 X plus B . Whatever it is equal zero ,
13:33 we know how to solve for X . We move
13:34 be over , we divide by A . But in
13:37 general what we give is we saw in the video
13:39 , they're in general , the line could be horizontal
13:41 with no crossing points . That's true . But in
13:43 general it's going to have one crossing point . In
13:46 this particular case , this is X . This is
13:48 F of X . The crossing point is actually right
13:51 here at this value of X right here . So
13:53 this is one solution . And you can say it's
13:57 like an X is equal to two or something .
13:58 I'm just making this up . I'm just giving you
14:01 an example . As we saw in the video ,
14:03 there's one crossing point . There's one solution because we
14:06 expect one solution because the highest power of X is
14:08 just equal to a one . Now , moving up
14:11 the complexity a little bit , we have the famous
14:13 quadratic quadratic equations which we're gonna be using and zooming
14:19 in on almost entirely in this lesson . But the
14:22 quadratic equations in general look like this . All of
14:25 the quadratic equations have the form A X with the
14:28 power of two plus some number times X plus some
14:32 other number . Now A B and C can be
14:35 any value Except for one exception . And that is
14:38 that the power the value here a cannot be equal
14:42 to zero . In other words , for it to
14:44 be a quadratic , you have to have some ,
14:45 you can't have zero here , otherwise it would kill
14:47 the quadratic term entirely . Right ? So in order
14:50 to find the roots of the quadratic equation , how
14:53 many crossing points you have , What you do is
14:55 you take this quadratic equation , You have a X
14:57 squared plus bx plus C . And you set it
15:01 equal to zero , then you factor it . Or
15:03 you could do completing the square . Like we've been
15:05 doing , we're also going to learn about the or
15:07 we will we will be doing actually completing the square
15:09 to solve this guy will also be using the quadratic
15:13 formula to find out the values of X that satisfy
15:15 this equation . And then the main idea is what
15:18 is the values of those that equation actually actually represent
15:22 ? Well there's a couple of different cases and we
15:23 saw some of them uh in the video , they're
15:27 in the demo there . But let me just draw
15:29 a couple of cases here , if your quadratic depending
15:32 on the values of A . And B and C
15:34 happens to look something like this and upside down Parabola
15:37 , then there's two crossing points because you're setting the
15:40 value of this equation equal to zero . So this
15:43 is gonna be a solution and this is gonna be
15:45 solution is gonna be two solutions , right ? So
15:47 you're gonna have to solutions right ? And just to
15:51 kind of make things up , you could say that
15:52 X would be negative three and X could be positive
15:55 , you know , two or something . I haven't
15:57 exactly drawn it . But you see the idea you
15:59 have a positive sum to positive negative value in this
16:02 case you have to actual roots . What are some
16:05 other cases that you can get with ? Quadratic ?
16:07 So what does it actually mean ? Right . Well
16:09 you can have a case like this . You could
16:10 have of course a parabola that dips below the X
16:13 axis like this . So you have two crossing points
16:16 . Still you have a crossing point here in a
16:17 crossing point here , you still have two solutions .
16:20 You have two solutions and the values of these solutions
16:23 are both positive . So it might be for instance
16:25 , X is equal to one and X is equal
16:27 to three . Those are two real solutions but there
16:30 are other ideas and other kind of possibilities . Right
16:34 ? You could have let's go over here and draw
16:37 a couple of different possibilities . What if you had
16:40 the parabola as we saw in the demo there floating
16:43 kind of up above the X . X . What
16:44 you see , there's no crossing points . There's no
16:47 values where this equation actually equal zero . All of
16:50 the values of the function are all above zero .
16:52 So there are no crossing points . So there are
16:54 no real roots . Right ? So no real roots
17:00 . But what we're going to find is there's still
17:02 two routes of the equation . They're just both complex
17:04 , which involves imaginary numbers . Now , another example
17:08 of when you would have no real roots is what
17:10 if the equation kind of is down below , but
17:12 going upside down . So you see all of the
17:14 values are negative for this function . They do not
17:17 ever cross the X axis . So again , there's
17:19 no real roots here either , no real roots ,
17:25 right ? And then of course we have the one
17:27 final example that we really need to talk about ,
17:30 which is the case that we kind of illustrated in
17:32 the video here uh in the demo here just a
17:35 minute ago . And that is the case of the
17:37 double roots , right ? So what if you have
17:39 the quadratic come down and just barely touch the access
17:42 ? But only in one spot . It can be
17:44 a positive oriented curve like there , or it could
17:46 be in a negatively oriented curve where it only touches
17:49 in one spot here . In either case there's still
17:52 what we call to roots , but we call it
17:54 a double route . And when I was learning this
17:58 stuff the first time , the idea of a double
18:00 root really confused me . Why is it a double
18:01 root ? Well , it's because as I showed in
18:03 the in the demo there , as you , as
18:06 your quadratic goes closer and closer and closer to the
18:09 access . The roots get closer and closer together .
18:12 Eventually , when it's just touching the axis , there's
18:15 still two routes but they're infinitely close together . They're
18:17 basically on top of each other so they have the
18:19 same exact value X . Is equal to one and
18:22 then X is equal to one . The count twice
18:24 . You still have to have two routes . So
18:26 you still have two routes for this equation . Two
18:28 routes for this equation , two routes for this equation
18:30 . Two routes for this equation And even these equations
18:33 have two routes but they're both complex and we'll learn
18:36 how to find those when we , you know ,
18:38 continue learning how to solve the quadratic , so which
18:40 is what we're gonna be doing mostly in this section
18:43 . But this is an overview section and I want
18:45 to talk about more than quadratic . We talked about
18:47 this in the demo cubic equations . The general form
18:53 of the cubic equation looks like this . Ffx is
18:56 some number times X to the third power plus some
18:59 number X squared plus some number times X plus some
19:04 number . Right ? That's ffx that's a cubic equation
19:07 . This number here needs to be something other than
19:10 zero . But any of these other ones can be
19:12 zero , like B , C . Or D could
19:14 be zero because in other words it doesn't matter what
19:17 the rest of this thing is . It's a cubic
19:19 if the highest power is a . Three . So
19:21 to figure out the roots of this guy , what
19:24 you're going to be doing is you're going to solving
19:25 this equation X to the third plus B . X
19:28 squared plus C . X plus D . And you're
19:31 gonna set that guy equal to zero . And we're
19:33 going to learn as we get a little farther into
19:35 our how to solve cubic equations . We're gonna learn
19:37 how to factor things out and how to separate and
19:39 divide things and we're gonna figure out the roots of
19:42 this guy . But graphically what does it actually mean
19:44 ? We saw in the demo uh in general what
19:48 it means . But I want to make sure everybody
19:50 understands now in general the cubic equations . I call
19:53 them these snaky functions , they go up and then
19:55 down the back up . So you see , there's
19:57 three crossing points corresponding to the three solutions that we
20:01 expect to find . So for instance , you might
20:02 say that X is equal to like over here ,
20:04 -4 . You may see that this route is over
20:07 here at -1 . And you might say that this
20:09 route , is it positive to or something . So
20:11 there's three real roots here . Three real roots for
20:17 this equation . If this is what it would work
20:19 to look like . But there are other possibilities which
20:22 we saw over there when we did the demo there
20:25 and there's infinite possibilities really . But you might have
20:28 one that goes up like this and then snakes down
20:30 but doesn't quite go below the axis again . So
20:33 in this case you have only one real root ,
20:35 the other to what you have to have to make
20:37 three or you're gonna end up being complex roots .
20:39 So what you might say , for instance , is
20:42 that your real root is gonna be access equal to
20:45 like , let's say negative three , one real root
20:49 and then the other two routes to more complex .
20:55 Right ? So in other words , when we learn
20:57 how to solve these things , we might find out
20:58 that the real root is negative three and the complex
21:01 roots might be one plus I that's complex number and
21:04 then one minus I that's another complex number . For
21:07 a total of three . Right ? And then one
21:09 more quick case , since we're just trying to be
21:11 , you know , explicit about everything , we might
21:14 have something that looks like this . We might have
21:17 the function go back to bend back below and then
21:20 go up like this . It's a similar kind of
21:22 situation . You have one real root here , right
21:26 ? And you have two more routes that are complex
21:28 , which we haven't learned how to solve yet ,
21:29 but they have to add up to equal three .
21:31 So three real roots , three routes total only one
21:35 of which is real . Three routes total only one
21:37 of which is real . And we're only gonna do
21:39 one more here . We're gonna talk a little bit
21:41 about the court equations . The way you spell it
21:43 is like this core core tech equations . Right ?
21:49 And so the corn equation looks like this . It's
21:53 1/4 power A X to the fourth , B X
21:57 to the third , C X squared D X E
22:02 . So I have to use different letters . Right
22:04 ? And if you want to solve this quarter the
22:06 equation to figure out where the roots of the lie
22:08 , then you just set this whole thing equals zero
22:09 X to the fourth , BX to the 3rd ,
22:13 C x squared dx Plus the equals zero . Now
22:18 we have no idea how to solve this . We
22:19 haven't learned that yet . But there are methods and
22:21 techniques you can learn to figure out the values of
22:23 X . There's gonna be four values of X that
22:26 are going to make this thing equals 04 solutions because
22:28 it's 1/4 power . That's what we expect . So
22:31 in general the cortex which we kind of learned ,
22:33 we looked at in the demo there in general is
22:37 gonna look like this is going to be a w
22:39 of some kind is gonna go down and up kind
22:41 of like this right now . Of course it can
22:45 be flipped upside down so it can look like an
22:47 M . Right , but in general looks like a
22:49 W . So in this case you have 1234 crossing
22:52 points , so you have four real solutions like this
22:58 . Uh And then of course we have other possibilities
23:01 . Let's take a look at some of them really
23:03 quickly . What if we had uh case which we
23:06 briefly did examine something like this ? It goes down
23:09 then up but not quite high enough and then it
23:11 goes back up like this . We have only one
23:13 to real solutions and too complex . We can't represent
23:19 the complex solutions on this graph , but we know
23:21 they have to exist because we know there has to
23:23 be four total . And then we have the final
23:27 case which I want to talk to you about and
23:28 then we're basically almost to the end of all this
23:30 stuff . The final case , if the cortex actually
23:33 goes down and up and down and up and we
23:36 never had any crossings at all , then we would
23:38 have four complex solutions . Why have I gone through
23:44 all of this stuff ? The truth is we're not
23:46 gonna learn about court equations anytime soon . What we're
23:49 really going to be doing is focusing on the quadratic
23:52 equations . But oftentimes I know when I first learned
23:54 this stuff , I didn't understand why we were doing
23:57 it . Why do we care ? Well , it
23:58 turns out that solving polynomial these are all different kinds
24:02 of polynomial is really , really important . It has
24:04 applications and calculus and physics and chemistry and engineering because
24:09 a lot of times , even when you're solving really
24:11 complex equations , which are called differential equations and calculus
24:14 oftentimes it boils down to solving polynomial equations as part
24:19 of the solution process . So we have to crawl
24:21 before we walk right . But this entire set of
24:24 lessons is going to be focusing on the quadratic equations
24:26 . So I want to give you an intuitive feel
24:29 because sometimes you're going to figure out that you do
24:31 have the two solutions and sometimes you're gonna find out
24:34 that you have two solutions that are real and two
24:36 solutions in other cases that are complex . And I
24:39 never really understood when I learned this the first time
24:42 . When do you have the real solutions ? And
24:44 when do you have the complex solutions ? This is
24:46 what it boils down to lines . In general ,
24:48 crossing one location , you're gonna have one solution because
24:51 the highest power of X is one . The quadratic
24:53 are always going to have to solutions , but depending
24:56 on where the graph is , those two solutions can
24:59 be both real or both complex here we have two
25:01 crossing points , so we have to real solutions here
25:04 . We have two crossing points . We have to
25:05 real solutions here . We don't have any crossing points
25:08 at all . We still have to have two solutions
25:10 , but they're both complex . When you actually solve
25:13 those polynomial that would give rise to these graphs ,
25:16 you'll find you're gonna get with quadratic formula which will
25:18 learn soon , you're gonna find that you get imaginary
25:21 or complex solutions . And then we have the cases
25:24 where the graph just kisses the axis and we talked
25:26 about why these are double routes . They count as
25:28 two routes as well for a total of two .
25:30 Then we have the cubic equations which look like these
25:32 snaky functions of course . Remember you can mirror image
25:35 , reverse them so that they go up and then
25:37 kind of down like this in general , they're crossing
25:39 three locations . Three routes for a power of three
25:43 . In this case it doesn't look like there's three
25:44 routes really , but there is because there's one real
25:47 root and then we have the two imaginary roots are
25:49 complex routes that would make for a total of three
25:51 here . In this case we have one real root
25:53 and then the other two would be imaginary or complex
25:56 roots and then we have the cortex where in generally
25:59 we have four crossing points . But depending on where
26:01 the graph is , two of them might be real
26:03 and two of them might be complex . So that's
26:06 why when you're solving these equations and folks are gonna
26:08 be focusing on the quadratic . Sometimes you'll get real
26:11 , sometimes you get complex . What it means is
26:13 if you were to graph those functions that tells you
26:16 what the graph really looks like , it tells you
26:17 where the crossing points are , how many of them
26:20 are there . And that's basically what it boils down
26:23 to . Um and that's all I want to really
26:25 get into now . So what we're gonna do is
26:26 we're gonna be learning how to solve quadratic equations with
26:29 new methods that you haven't learned before . They're among
26:32 the most important topics and types of equations . We're
26:36 gonna learn how to solve that have applications and everything
26:38 , so we're gonna spend a lot of time on
26:40 it . So follow me through the next batch of
26:41 lessons and we'll be covering the solution methods for quadratic
26:44 equations in great detail .
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