09 - Practice Graphing Parabolas - Part 1 (Vertex Form & Standard Form) - By Math and Science
Transcript
00:0-1 | Hello . Welcome back to algebra . The title of | |
00:02 | this lesson is practice graphing . Parable is this is | |
00:05 | part one ? We have a few parts to this | |
00:07 | lesson where the problem complexity will gradually increase . So | |
00:11 | we've talked about the general form of the vertex form | |
00:14 | of a parabola . Right ? We all know we | |
00:15 | can graph anything by just making a table of values | |
00:18 | and putting plugging in the table of values . But | |
00:21 | we have this vertex form of a parabola which makes | |
00:24 | it very easy to sketch the thing without making a | |
00:26 | table of values because we can read the vertex directly | |
00:29 | out of the equation . So we're gonna get practice | |
00:31 | without here . We're going to be doing several things | |
00:34 | . Were going to be graphing all of these problems | |
00:36 | . And what I mean by graphing is more like | |
00:37 | sketching it . We don't need any details . We | |
00:39 | just need to be able to sketch the general shape | |
00:41 | . Want to label the vertex , we want to | |
00:43 | label the axis of symmetry of every one of these | |
00:45 | parabolas . and we want to show the intercepts . | |
00:48 | In other words where does the parable across the X | |
00:50 | axis ? This opens up opens down it's going across | |
00:53 | the X axis somewhere . All right . So let's | |
00:55 | go ahead and refresh our memory . So I'm gonna | |
00:58 | say recall that the vertex form of parabola . It | |
01:04 | looks something like this . Why minus K is equal | |
01:08 | to a times X minus H quantity squared . If | |
01:13 | this equation looks foreign or crazy to you it's just | |
01:16 | because you haven't watched my lessons on shifting parameters around | |
01:19 | the xy plane , you should go back and do | |
01:20 | that . But basically what you have here is you | |
01:23 | have the basic parabola A X square . That's the | |
01:27 | basic shape of a parabola . Right ? And you're | |
01:29 | shifting it H units to the right , That's what | |
01:32 | the minus sign means . We talked about that in | |
01:34 | great detail and you're shifting at K units up in | |
01:37 | the Y . Direction . So minus sign means H | |
01:39 | units . This way minus sign here means K units | |
01:42 | up . And of course the A . Here in | |
01:44 | the front determines if it opens up or opens down | |
01:46 | and also the steepness of the problem . So we're | |
01:49 | gonna get a lot of practice with all this stuff | |
01:51 | . What we want to do with every one of | |
01:52 | these problems here is we want to graph it , | |
01:55 | sketch it I guess is a better word . We | |
01:57 | want to show the vertex of every one of these | |
02:00 | problems . We want to show the access or write | |
02:02 | down the axis of symmetry , which we've defined in | |
02:06 | the past . And we want to show the intercepts | |
02:12 | because if you know all of this stuff uh then | |
02:14 | you can sketch the graph . So that's what you're | |
02:16 | gonna be doing on your exams and you'll be given | |
02:18 | an equation and you'll be asked to sketch it and | |
02:21 | you'll be asked to sketch it without putting a table | |
02:24 | of values , without making a giant table values and | |
02:27 | drawing lots of points . You're not gonna be doing | |
02:28 | that , We're sketching it just by looking at the | |
02:31 | equation . So the first equation we have is something | |
02:34 | like this . Why is equal to negative three times | |
02:37 | X squared ? So we know it's a parable why | |
02:40 | ? Because it has a square term . The highest | |
02:42 | power of course is very simple . There are no | |
02:44 | other terms here , but the highest power is a | |
02:46 | square . So we know it's a parable up and | |
02:49 | we also know because we've talked about it before that | |
02:52 | the negative sign in the front is negative three here | |
02:54 | , the negative sign means the parabola opens down so | |
02:58 | whatever is in front of the X . Square term | |
03:00 | , no matter what the number is , if it's | |
03:01 | negative , the Parabola opens down like a like a | |
03:04 | frowny face . If it's a positive then it opens | |
03:06 | up like a smiley face . So we know this | |
03:08 | problem is going to go upside down like this , | |
03:11 | but we want to obviously talk about more than just | |
03:14 | that we want to sketch it . So let's go | |
03:16 | over here and draw a little access . We don't | |
03:20 | need to be exact about it , this is X | |
03:22 | . And this is why we're going to sketch this | |
03:24 | thing right here . So the first thing we need | |
03:26 | to do is figure out what is the vertex of | |
03:28 | this problem . So what you need to do is | |
03:30 | figure out a way to make this equation look like | |
03:32 | this one because when you have it in this form | |
03:34 | you can read the vertex directly out . So what | |
03:37 | I want you to do is think Think of this | |
03:40 | equation like this instead of why you need to think | |
03:42 | about it as why zero . You don't need to | |
03:47 | have the princes there if you don't want , in | |
03:48 | fact let me take them away . Just so it | |
03:49 | doesn't confuse anybody . Uh and that's going to equal | |
03:52 | to negative three . Now this X square , you | |
03:54 | can think about writing it as X minus zero quantity | |
03:57 | squared . Well , why am I doing that ? | |
03:59 | Because when I subtract zero from why it doesn't change | |
04:02 | anything , it's still why Right ? When I subtract | |
04:04 | zero from exit doesn't change X at all . So | |
04:07 | this is the same as this and this is the | |
04:09 | same as this . So even though it looks different | |
04:11 | , it's actually the same exact equation . But by | |
04:13 | writing in here now it matches this form right here | |
04:16 | . So because of that , you read the vertex | |
04:19 | directly off of this guy , you read the vertex | |
04:23 | so you can see the vertex is going to be | |
04:27 | at . In other words , the parabola here , | |
04:29 | the basic shape of the problem is shifted zero units | |
04:32 | and X and zero units . And why ? So | |
04:33 | that means it's just located at 00 like a regular | |
04:36 | parabola is so I'm going to put a dot here | |
04:39 | and I can say that the vertex is located at | |
04:44 | zero comma zero . In other words there is no | |
04:46 | shift of this parabola from the basic position of any | |
04:50 | parabola , there's no shift at all . So it's | |
04:52 | going to go here and we also know it's an | |
04:54 | upside down parabola because there is a minus sign in | |
04:57 | the front . So I can say it opens Yeah | |
05:00 | , down and we talked about this in the past | |
05:03 | as well , but because there's a three here , | |
05:05 | the value of the number in front tells you how | |
05:08 | steep it is . In other words , if it's | |
05:10 | a very large number of positive or negative , then | |
05:13 | the problem is very closed off , very narrow . | |
05:16 | If it's a very uh small number , like a | |
05:18 | one , like a typical one X square , just | |
05:21 | a one , then it's nice and open . And | |
05:23 | of course if you go to one half it opens | |
05:24 | up even more . So it's a fairly narrow steep | |
05:27 | problem uh here and it opens down . So the | |
05:32 | next thing we need to do , we know it's | |
05:33 | gonna go like this uh here . And so probably | |
05:37 | the easiest thing to do since we can see the | |
05:38 | vertex is right on the axis here is go ahead | |
05:40 | and sketch the thing . So we know it's going | |
05:42 | to open a little bit steeper than a traditional problem | |
05:46 | . A regular problem might come and open up a | |
05:48 | little bit more open like this . This one's a | |
05:50 | little bit steeper . The vertex is right here . | |
05:53 | It opens upside down . That's pretty much all the | |
05:55 | information that we have here . But we have one | |
05:57 | more thing we want to talk about . We're gonna | |
05:59 | graphic we're gonna put the vertex , We're going to | |
06:01 | talk about the axis of symmetry . Axis of symmetry | |
06:03 | is what is the line that cuts this parable in | |
06:06 | half ? So the axis of symmetry is going to | |
06:11 | be an equation of a line . A vertical line | |
06:13 | , always a vertical line . So it's going to | |
06:15 | be X is equal to zero . A vertical line | |
06:18 | . Remember , vertical lines are always X equals something | |
06:21 | . A vertical line at X equals zero . Is | |
06:23 | this line the y axis a vertical line and X | |
06:26 | equals five . Is a vertical line over here . | |
06:28 | A vertical line of X equals negative three is a | |
06:31 | line over here at negative three and so on . | |
06:33 | So the axis of symmetry is X equals zero . | |
06:35 | That's a vertical line that goes right and splits this | |
06:37 | thing in half because that is the symmetric , you | |
06:40 | can fold this thing over on itself like that . | |
06:42 | And then the last thing we want to talk about | |
06:44 | is the intercepts here . Usually these problems , like | |
06:46 | if it was upside down over here , it would | |
06:48 | intersect the axis in two points and we would have | |
06:51 | to find those points . But here , because the | |
06:53 | vertex is right here , it only touches the axis | |
06:55 | in one location . We know that the only intercepts | |
06:58 | here . Yeah , are at X is equal to | |
07:04 | zero . There's only basically one intersect . It's a | |
07:06 | double route basically right here because it touches in one | |
07:08 | location . So I don't need to put anything else | |
07:10 | there . So we have the intercepts which is only | |
07:13 | touching at one spot , the axis of symmetry . | |
07:15 | It opens down the vertex and we've sketched it . | |
07:18 | Now , of course you can make a table of | |
07:20 | value and tighten this thing up and get the exact | |
07:22 | shape . That's not the point . The point is | |
07:24 | to sketch it . You're gonna do this kind of | |
07:26 | thing in algebra where you're just sketching things , you're | |
07:28 | also going to do it in calculus , you spend | |
07:30 | a whole chapter sketching curves using the concepts that we | |
07:33 | learn later on in calculus . So sketching is something | |
07:35 | that you just have to get used to . All | |
07:37 | right , let's go onto the next problem . It's | |
07:39 | slightly more complicated than this one , But not complicated | |
07:42 | in general . What if the equation is why -4 | |
07:46 | is equal to negative x squared ? So we want | |
07:49 | to sketch it right ? Um Now we already want | |
07:53 | to compare it to this , so this is why | |
07:56 | minus some shift is equal to a X minus some | |
07:59 | shift squared . So this looks almost the same . | |
08:03 | But you wanna think And I'm gonna write the word | |
08:06 | , think . You want to think about this equation | |
08:08 | in a different way , you want to think about | |
08:09 | it is why -4 is equal to the negative sign | |
08:14 | , stays there from above . But this X just | |
08:16 | replace it with X minus zero in other words because | |
08:19 | there's nothing here , there is no shift in the | |
08:20 | X . Direction because X minus zero is what already | |
08:23 | already had there . But I do have a shift | |
08:25 | in the Y . Direction and no shift in the | |
08:27 | X . Direction . So if I come over here | |
08:29 | and draw a or sketch I should say an xy | |
08:33 | playing . So here's X . Here's why I'll just | |
08:38 | put some tick marks 12341234 I'm just sketching 123 If | |
08:43 | I don't need to be exact something like this . | |
08:45 | Where is the vertex of this ? Probably going to | |
08:47 | be ? Well there is no shift in the X | |
08:50 | direction . So that means the X coordinate of the | |
08:52 | vertex is zero , right ? But the y coordinate | |
08:58 | of the vertex is shifted up because remember minus signs | |
09:02 | mean shifted up . If that doesn't make sense to | |
09:05 | you , then it's because you need to go back | |
09:06 | and look at my lessons on shifting parabolas . I | |
09:08 | talk extensively on why the shifting happens when you have | |
09:12 | a minus sign here . This is the minus sign | |
09:14 | Also it just means there's no shift though . But | |
09:16 | here we're shifting upward in the Y direction for units | |
09:18 | . That means the vertex has to be positive for | |
09:21 | So we have 1234 . This problem is shifted up | |
09:25 | for units . I'm putting a doctor because that's the | |
09:27 | vertex , right ? So I'm gonna label this the | |
09:30 | vertex Is at 0:00 for that's the vertex of the | |
09:35 | problem . So the next thing you have to look | |
09:37 | at say , well , is it open up or | |
09:40 | is it open down ? In other words , does | |
09:41 | it look like a smiley face where the vertex here | |
09:43 | ? Or does it look like a frowny face with | |
09:45 | the vertex there ? Well , I have a negative | |
09:48 | sign which is in front of the X square term | |
09:50 | . So it opens down and also it's only a | |
09:55 | negative one out here . Seeing the previous problem , | |
09:58 | it was negative three . This was much steeper , | |
10:00 | much more closed off , much more constricted like this | |
10:03 | . But this is a negative one out here , | |
10:04 | which means it's not going to be quite so steep | |
10:06 | . It'll probably open something more like this . Uh | |
10:10 | like a traditional parable of shape , It's just flipped | |
10:12 | upside down . Now , you can sketch it with | |
10:15 | this information honestly because you know the vertex is here | |
10:18 | . You know , it opens down and so you | |
10:19 | could just sketch it . But the problem is you | |
10:21 | don't know exactly where this thing crosses the axis here | |
10:25 | . If I knew that it crossed here and it | |
10:27 | crossed here , then I can sketch through this point | |
10:30 | and I would have a pretty good idea for the | |
10:31 | shape . So that's why in these problems you want | |
10:33 | to sketch the graph , you want to talk about | |
10:35 | If it opens up or down , you want to | |
10:37 | know the vertex , you want to know the axis | |
10:39 | symmetry of course , and you want to know the | |
10:41 | intercepts . That means where does the problem cut into | |
10:44 | the axis ? Because if you know that , then | |
10:46 | you can sketch the thing through those points . So | |
10:49 | we have to figure that out . And unfortunately , | |
10:51 | the only way to really figure it out is to | |
10:53 | calculate it . So we know this thing is going | |
10:55 | to come down , it's gonna cut somewhere here . | |
10:58 | The function is going to go in both directions , | |
10:59 | that's going across the access , let's say right here | |
11:01 | and right here in both of these locations , the | |
11:05 | why value of the function is zero . If it | |
11:08 | if it did cross here at this point then the | |
11:10 | y value of this point is gonna be negative , | |
11:12 | something comma zero . The y value of this point | |
11:15 | or the point here would be let's say two comma | |
11:17 | zero . In other words , both of these points | |
11:19 | have a y value of zero . So the way | |
11:21 | we figure out where they are is we just set | |
11:24 | y is equal to zero , that's all we have | |
11:26 | to do . So we just take a zero and | |
11:27 | we stick it in there , it's gonna be a | |
11:29 | minus four . And then on the right hand side | |
11:32 | it's a negative sign inside here . We just make | |
11:34 | it x minus zero squared . And no , all | |
11:37 | we have to do is soft at the X values | |
11:39 | . These are gonna be the X values where the | |
11:41 | y value is zero . So you're setting the Y | |
11:45 | value equal to zero , forcing yourself to calculate the | |
11:48 | values of X where the Y . Values to zero | |
11:51 | . Those are gonna be the crossing points for the | |
11:54 | call it the X intercept . So it's the X | |
11:56 | intercept . In other words the intercept intersection points with | |
12:02 | the X axis . So then we can calculate this | |
12:04 | , we have negative four on the left and then | |
12:07 | this is X zero . So we just write it | |
12:09 | as negative x squared . And then we have to | |
12:12 | do is we have a negative sign and a negative | |
12:14 | sign . We can divide both sides by -1 . | |
12:17 | Right ? So I divide this by negative one . | |
12:18 | This by negative one . I'm gonna get a positive | |
12:20 | four in a positive X squared here . Just divide | |
12:22 | both sides by negative one . And then we flip | |
12:25 | it around and make it easy to see X squared | |
12:27 | is four . And I think you know what to | |
12:28 | do next ? You take the square root , so | |
12:30 | you get X is plus or minus the square root | |
12:32 | of four . We've done radical equations before , so | |
12:35 | you have X is plus or minus two , right | |
12:38 | ? So that means that at plus or minus two | |
12:41 | on the X axis , at plus or minus two | |
12:44 | on the X axis . The y value of the | |
12:46 | function is zero . So that means that right here | |
12:49 | there's an intercept at positive two for x and negative | |
12:53 | two for X . Of course the Y value is | |
12:54 | zero for both of those because it's on the axis | |
12:56 | . And now I have enough information , I can | |
12:59 | go here and just draw this guy going straight through | |
13:02 | like this and I'll try to do my best to | |
13:04 | go down like this and I didn't quite hit it | |
13:06 | . But you get the idea goes through like this | |
13:08 | , that's what this problem looks like . In order | |
13:10 | to do a proper sketch , you have to know | |
13:11 | where the vertex is , so you know where to | |
13:14 | start from and you have to know where the intercepts | |
13:16 | are . So you know where to go . All | |
13:18 | you need is a couple of points like that to | |
13:19 | draw a pretty good sketch of a problem . And | |
13:22 | then the last thing we need to do is what | |
13:24 | is the axis of symmetry ? So the axis of | |
13:28 | symmetry is just the line that cuts the thing in | |
13:32 | half and this thing is centered right here . So | |
13:34 | the y axis just like before is the same thing | |
13:36 | here . The axis of symmetry is X is equal | |
13:38 | to zero . Remember vertical lines X is equal to | |
13:40 | something X is equal to zero . Is a vertical | |
13:43 | line right here , which bisects this guy . So | |
13:45 | that's the axis of symmetry . We have the intercepts | |
13:48 | , we talked about here , the vertex we know | |
13:50 | it opens down . That's everything that was asked of | |
13:52 | us in this drawing and this problem and also to | |
13:55 | sketch the thing . So we're done every one of | |
13:59 | the problems after this . And also in the next | |
14:01 | couple of lessons are going to follow the same basic | |
14:04 | idea . We're going to figure out where the vertex | |
14:06 | is . We're going to calculate the intercepts and we're | |
14:09 | going to then try to sketch it and then look | |
14:10 | at the symmetry and all the other things and write | |
14:12 | them all down . That's what you're gonna be asked | |
14:14 | to do in all of your problems . Okay , | |
14:17 | next problem . What if we have y equals X | |
14:22 | -3 quantity squared . So we obviously want to figure | |
14:28 | out where the vertex is . So the easiest way | |
14:30 | to do is to think about it this way . | |
14:34 | Really ? This why is a Y minus zero on | |
14:36 | the right hand side ? I'm gonna leave it as | |
14:38 | x minus three quantity squared . This is now in | |
14:40 | the form of that vertex form of of a parabola | |
14:44 | . We can see the vertex has no shift in | |
14:47 | the Y direction , but it does have a shift | |
14:50 | in the positive X direction because negative science means you | |
14:52 | go and shift the thing to the right . So | |
14:54 | if I was going to kind of draw X , | |
14:59 | why I'll do some tick marks 123 put some tick | |
15:02 | marks all over the place here and have to be | |
15:04 | exact then where is this vertex going to live ? | |
15:07 | Well , again , it shifted three units to the | |
15:10 | right , that's over here , and zero units up | |
15:13 | . That means the vertex lives right here . Uh | |
15:16 | and this parable is either going to go upside down | |
15:19 | like this , or it's going to be right side | |
15:20 | up like this , and we're gonna get to that | |
15:22 | in a second . But for now , let me | |
15:23 | go ahead and write down that there's vertex here at | |
15:30 | three comma 03 extra single three Y is equal to | |
15:34 | zero . And that's something you need to solve the | |
15:38 | problem . The next thing you do is you look | |
15:41 | at the coefficient in front of the X square term | |
15:43 | , whatever is in front of here , In this | |
15:44 | case it's a positive one . So we know because | |
15:46 | it's positive that opens up and you also know that | |
15:50 | there's a one here . So the larger the number | |
15:53 | , the more closed up the problem is , so | |
15:55 | we know it's gonna be a regular shape kind of | |
15:56 | open for a because it's just the one and it | |
15:59 | opens up right there . Alright . The next thing | |
16:02 | we need to do is we need to talk about | |
16:04 | intercepts . Now , in this case you can see | |
16:06 | the vertex is on the axis . So , you | |
16:08 | know , the thing really doesn't have any other intercepts | |
16:10 | besides this point . So you could kind of just | |
16:13 | sketch the thing . In fact , let's just do | |
16:14 | that real quick . The problem is going to look | |
16:16 | something like this , that's probably a little too steep | |
16:19 | . It should be maybe a little bit more open | |
16:20 | than that , but basically that's gonna be the um | |
16:23 | the the problem . But just to be absolutely clear | |
16:29 | about it , let's go find those intercepts the X | |
16:32 | intercepts . Where does this parable across the X axis | |
16:37 | ? Of course you can see it right here . | |
16:38 | But let's do it . We're gonna set the y | |
16:40 | value equal to zero . We're gonna force the function | |
16:42 | to have a y value of zero . We're going | |
16:44 | to calculate this . So it's gonna be zero for | |
16:46 | y x minus three quantity square . So we have | |
16:49 | to find the X values . Okay , so then | |
16:52 | we have a zero here and here , we're gonna | |
16:54 | take the square root of both sides . Actually , | |
16:57 | no , we're not gonna take the square to both | |
16:58 | sides . Let's do it this way . We're gonna | |
16:59 | open it up and say x minus three , this | |
17:02 | is x minus three times x minus three . This | |
17:03 | is a much better way to clean a way to | |
17:05 | do it . And you can see that . To | |
17:06 | solve this equation , x minus three has two equals | |
17:09 | zero and x minus three has equal to zero , | |
17:11 | so X is equal to three and X is equal | |
17:14 | to three . So what you have is a double | |
17:15 | root at X is equal to three , which is | |
17:17 | exactly what you have . This is 123 there's a | |
17:20 | double root here anytime and parabola goes down to the | |
17:23 | axis and just touches it . Then you still have | |
17:25 | to roots but they're right on top of each other | |
17:28 | , infinitely close together , right on top of each | |
17:30 | other . And so we've shown it mathematically that the | |
17:33 | crossing points are in X is equal to three . | |
17:35 | And we already knew it from the fact that the | |
17:37 | vertex was here as well . So then we need | |
17:40 | to talk about the axis of cemetery . All you | |
17:46 | have to do is go up here and say , | |
17:47 | well what line cuts this thing in half ? It's | |
17:49 | going to be a line that goes right through the | |
17:51 | middle at X equals 123 It's always going to be | |
17:55 | a vertical line and any vertical line and math always | |
17:59 | has the form X equals something because for us we | |
18:02 | have a vertical line . All of the points on | |
18:04 | that line have the same X value . You know | |
18:07 | the point on the line right here has an x | |
18:09 | value of three . Here has an X value of | |
18:12 | three . Here has an X value of three . | |
18:14 | Any point on this line is three comma something because | |
18:17 | the Y values are all different , but the X | |
18:19 | values are all three . So to show that they're | |
18:22 | all equal to three . The line just as X | |
18:24 | equals three . That means all the points where X | |
18:26 | is equal to three . And that means there's a | |
18:27 | line here of points like this . So this is | |
18:29 | the axis of symmetry intercepts are here . It opens | |
18:32 | up and then the vertex we've already written down . | |
18:35 | All right , we have one more problem . This | |
18:37 | one's gonna take a little more time . Not because | |
18:39 | it's complicated , but just because the math gets a | |
18:42 | little bit cumbersome at the end . So let's go | |
18:45 | and work on that . Right now , let's say | |
18:46 | we have Y plus two is equal to princess X | |
18:51 | minus one quantity square . Now , this is probably | |
18:55 | the 1st 11 of the first ones . Anyway , | |
18:57 | we don't have to make any changes to the equation | |
18:59 | . It's already in vertex form . We can see | |
19:02 | that we have a shift in the X direction of | |
19:04 | the basic problem shape to the right one unit . | |
19:07 | And we can see we have a shift of the | |
19:09 | problem also down two units because the plus sign means | |
19:11 | down two units . So if we were going to | |
19:13 | do that , uh we're gonna go ahead and draw | |
19:17 | a quick little uh access here . Um Let me | |
19:23 | go and draw a couple tick marks . 123123123123 something | |
19:29 | like this . And let's go ahead and say that | |
19:32 | the vertex of this guy shifted one unit to the | |
19:34 | right , That means here and two units down 12 | |
19:37 | So the vertex of this problem is actually right here | |
19:40 | , down below . And the problem can either go | |
19:44 | upside down or it could be right side up . | |
19:46 | You have to look at other parts of the uh | |
19:49 | guy to figure that out . But we can write | |
19:51 | down that the vertex , is that one comma negative | |
19:55 | too ? One unit shifted to the right to unit | |
19:58 | shifted down so from the origin so have one common | |
20:00 | negative too . So then you have to ask yourself | |
20:03 | , okay , is it open up or doesn't open | |
20:05 | down ? So all you do is look at the | |
20:07 | number in front of the princes . But it's an | |
20:09 | invisible one positive one . So it's positive , which | |
20:12 | means it opens up . And that means that this | |
20:16 | equation is going to look something like this . Now | |
20:18 | . I don't want to sketch it yet because the | |
20:20 | problem is I don't know how wide it is or | |
20:22 | how narrow it is . So it could be a | |
20:24 | very steep problem that goes like this or could be | |
20:26 | a really shallow problem that goes like this . We | |
20:29 | need to know the X intercepts . Where does the | |
20:31 | thing cross the X axis here ? So let's find | |
20:34 | the X intercept . Let me switch colors . The | |
20:38 | X intercept you set Why equal to zero ? Because | |
20:43 | we're forcing white to be zero . We're looking for | |
20:45 | points in the function that lie on this axis . | |
20:48 | So why must be zero ? We just stick zero | |
20:50 | into the equation X minus one , quantity squared . | |
20:54 | All you do is take a zero in there and | |
20:56 | then you solve for the values of X . Whatever | |
20:58 | we get is going to be the crossing points on | |
21:01 | the X axis because we set Y is equal to | |
21:03 | zero . So notice we have x minus one square | |
21:06 | . So let's do this properly . It's going to | |
21:08 | be x minus one , X minus one . We're | |
21:10 | gonna have to foil this thing out . Right ? | |
21:13 | So on the right hand side is going to be | |
21:14 | X times X . Giving you X squared . This | |
21:17 | is going to give you negative X . The outside | |
21:19 | terms are also going to give you negative X . | |
21:21 | And these are gonna give you positive one . So | |
21:23 | you're gonna get two is equal to X squared minus | |
21:26 | . You add those together . Get two X plus | |
21:28 | one . All right ? But I have a two | |
21:30 | over here . So I need to solve this thing | |
21:32 | . So I need to move the two over . | |
21:34 | So what I'm gonna have a zero X squared minus | |
21:37 | two X . And then one minus two is gonna | |
21:40 | give you negative one . All I did was subtract | |
21:42 | two from both sides . So let me catch up | |
21:45 | and make sure I'm I'm good here . So what | |
21:48 | I want to do is try to factor this thing | |
21:50 | , I'm gonna set it equal to zero . Of | |
21:51 | course it's set equal to zero . And I'm gonna | |
21:53 | try to factor . So I see I have an | |
21:55 | X squared here , here's an X . And here's | |
21:56 | an X . The only way I can have a | |
21:58 | one is a one time to one like this . | |
22:01 | But then I run into problems because I have a | |
22:05 | negative sign there . So these have to be different | |
22:08 | signs . If I make it , for instance , | |
22:09 | plus and minus , Like that will make a negative | |
22:12 | one , but they don't have a plus X and | |
22:14 | uh minus X . I add those together . I'm | |
22:16 | not going to get the two X . So then | |
22:18 | I say , okay , well I'll flip it around | |
22:19 | again and you can already see it's not gonna work | |
22:21 | . I'll do this , make it , it has | |
22:23 | to be opposite to multiply these two give me negative | |
22:25 | one , but then I have the same problem . | |
22:26 | These don't add to give me this . So basically | |
22:30 | you just kind of cross through that and say you | |
22:32 | can't factor it . I mean most of the time | |
22:37 | , honestly in real life , most of the time | |
22:39 | you get a quadratic like that and you can't factor | |
22:41 | it most of the time . But it doesn't mean | |
22:44 | it doesn't have solutions . It just means it doesn't | |
22:45 | have solutions that are whole numbers . So because you | |
22:48 | can't factor it doesn't mean you give up , it | |
22:50 | just means you think okay how can I solve it | |
22:52 | ? Well we try to factor first that didn't work | |
22:54 | right . The next thing you can do is completing | |
22:56 | the square and then you definitely can factor it . | |
22:59 | But we already learned there's an easier way the quadratic | |
23:01 | formula is always easier . It always works and it | |
23:04 | basically comes from completing the square . So what we | |
23:07 | wanna do , we want to figure out the crossing | |
23:10 | points here . And this is why I said this | |
23:11 | problem becomes it's harder but it's not because it's conceptually | |
23:16 | harder , it's just there's more math to do . | |
23:18 | So now I have to get the X . Values | |
23:20 | by the quadratic formula which remember is it's going to | |
23:24 | be negative B plus or minus B squared minus four | |
23:27 | times A times C . All of that goes under | |
23:29 | a radical and then I have over two times a | |
23:32 | day . That's the quadratic formula A . Is one | |
23:35 | . B is negative to see as negative one . | |
23:37 | So for B I have a negative B but B | |
23:40 | itself is negative two . So I'm gonna wrap that | |
23:43 | in a pregnancy . So it's negative B . And | |
23:45 | I have plus or minus that have be square which | |
23:47 | is negative two , quantity square minus four A C | |
23:52 | minus four times A . Is one C . Is | |
23:55 | negative one . For a C . A radical goes | |
23:59 | around all of that and then this whole thing is | |
24:01 | two times A . Which is one . So that's | |
24:05 | negative B plus or minus B squared minus four times | |
24:08 | a times C . Over to aid . So we | |
24:10 | just have to crank through it and it's just work | |
24:11 | . But you'll get there so negative times negative positive | |
24:14 | too Plus or minus on the inside here . This | |
24:17 | is going to give you a positive four and then | |
24:21 | you have negative times negative gives you positive for also | |
24:25 | have positive for inside of there . You have a | |
24:27 | radical here and then you have on the bottom two | |
24:30 | . So what you have is two plus or minus | |
24:33 | the square root of four plus four is eight . | |
24:36 | And then you have a two here . Now if | |
24:38 | you simplify this radical which is an eight , remember | |
24:41 | we learned how to simplify radicals ? It's two times | |
24:44 | four and four is two times two . And we | |
24:46 | were looking for pair so we can pull out a | |
24:49 | two there . So what we have here is for | |
24:52 | this is gonna be two plus or minus . The | |
24:54 | square debate reduces to a two coming out a square | |
24:58 | of two left underneath . And we've learned all of | |
25:00 | that when we learned radicals . So you have to | |
25:03 | plus or minus two square root of two , divided | |
25:05 | by two , a lot of two . We want | |
25:07 | to simplify as much as possible . We notice we | |
25:09 | have a two , A two and a two here | |
25:11 | . So what we're gonna do is we're gonna split | |
25:13 | this thing up to help us cancel it easier . | |
25:15 | We're gonna split this whole fraction up . It's going | |
25:17 | to be written as 2/2 plus or minus two square | |
25:21 | root of 2/2 . All I've done is taken this | |
25:24 | and break it apart uh into two fractions so that | |
25:27 | I can cancel this and this and cancel this too | |
25:29 | with this too . Now remember when you , when | |
25:32 | you have something that's added on the top here or | |
25:35 | subtracted , then you can split it up because what | |
25:37 | you have , you can think of it going backwards | |
25:39 | if you had a common denominator of two and I | |
25:41 | told you to add these , you would say well | |
25:43 | the denominator has to be too and that will be | |
25:45 | two plus or minus this on the numerator , which | |
25:48 | is exactly what I have . So it's going the | |
25:50 | reverse of kind of fraction addition and it just helps | |
25:54 | to visualize the cancellation . So what you have here | |
25:56 | is this is 12 divided by two is one and | |
26:00 | then this two divided by two is one . So | |
26:03 | you have square root of two , so you have | |
26:05 | two answers , one plus the square root of two | |
26:07 | and one minus the square root of two . But | |
26:08 | for the purpose of sketching and these are the actual | |
26:10 | intercept . So I'm gonna circle this . This is | |
26:13 | the intercepts X intercepts X intercepts , but for the | |
26:20 | purpose of graphing it's kind of hard to figure out | |
26:22 | where that really is . So what we do is | |
26:24 | we say one plus the square root of two is | |
26:27 | approximately equal to one plus in the square to is | |
26:30 | about 1.4 , it's got an infinite decimals after it | |
26:34 | . Um so I'm truncating it but it's about that | |
26:36 | one plus 1.4 and that's going to be approximately equal | |
26:40 | to 2.4 . All right , and then if I | |
26:44 | take the other 11 minus the square root of two | |
26:46 | is approximately equal to one minus 1.4 , which is | |
26:49 | approximately equal to negative 0.4 . These decimals are not | |
26:53 | exact because the square root of two is an infinite | |
26:56 | non repeating decimal goes on forever , it's irrational . | |
26:59 | So the 1.4 is not exactly what this is , | |
27:02 | that's why I have the squiggly equal signs here . | |
27:04 | But basically it crosses somewhere around 2.4 and somewhere around | |
27:08 | negative 0.4 . So 2.4 would be one to let | |
27:12 | me switch to a different colour . 2.4 would be | |
27:14 | 12 here is 2.5 , So 2.4 is gonna be | |
27:17 | just to the left of that and then negative 0.4 | |
27:21 | is going to be here is negative 0.5 , negative | |
27:24 | 0.4 is a little bit shifted to the right of | |
27:26 | that . So now we have our vertex which is | |
27:29 | right here , this is vertex at one common negative | |
27:34 | too , whoops one common negative to like this and | |
27:38 | this Parabola is going to go through this point down | |
27:41 | here and then through this point up there like this | |
27:44 | it's gonna cross at positive 2.4 and negative 0.4 . | |
27:49 | So you can see that those make a nice symmetric | |
27:51 | parabola and then we can look in the middle and | |
27:55 | say where is the axis of symmetry ? So we | |
27:57 | have to find the dotted line that goes right through | |
27:59 | the center and I know I'm not being perfect with | |
28:01 | this , but the axis of symmetry is that X | |
28:05 | is equal to what X is equal to one because | |
28:08 | that's that's where the line is here is X is | |
28:10 | equal to one right here . So the axis of | |
28:12 | symmetry is that X is equal to one , The | |
28:15 | vertex is at one common negative two . We got | |
28:18 | that from the equation , the X intercepts are really | |
28:21 | exactly equal to one plus or minus the square root | |
28:23 | of two but we changed into decimal so that we | |
28:25 | could actually put it on the graph . The thing | |
28:27 | opens up just because of the coefficient is a positive | |
28:30 | number there and that's it . That's all you really | |
28:32 | have to do . The only reason this one was | |
28:33 | difficult or harder . It was because you couldn't factor | |
28:36 | it . We couldn't figure out how to factor it | |
28:37 | . Now . You can see why we couldn't factor | |
28:39 | it because the crossing points were not nice . Whole | |
28:41 | numbers , they're weird . Long , infinite repeating decimal | |
28:45 | . So you're not going to have whole numbers and | |
28:47 | so that's why we couldn't factor it . So this | |
28:50 | is practice graphing parables . We're putting everything together where | |
28:53 | we're looking at the vertex form of a parabola , | |
28:56 | we're figuring out where the crossing points are , we're | |
28:59 | looking at the vertex , we're looking at the , | |
29:01 | you know , the opens up versus opened down . | |
29:03 | The only other thing I'll say before I close is | |
29:05 | that in every one of these problems , let me | |
29:08 | go back to the beginning here . Let me start | |
29:10 | with this one . Like in this problem for instance | |
29:12 | , I'm writing it in my problems like this is | |
29:15 | the vertex form , why minus four equals this . | |
29:17 | You can also write it as just moved forward to | |
29:21 | the other side , Why is negative X squared ? | |
29:24 | And then the plus four comes over . Some people | |
29:26 | will call this a vertex form Right ? Uh some | |
29:29 | books will call that a vertex form or on this | |
29:32 | equation . You might write it as Y is equal | |
29:34 | to X -1 quantity squared . Just take the two | |
29:38 | and subtract it over . Right . So you can | |
29:41 | still read the vertex off here , but you have | |
29:43 | to be careful with the signs because this means shifting | |
29:45 | down and this means shifting to the right and so | |
29:49 | I'm kind of teaching it to you this way because | |
29:51 | negative signs means to the right , positive signs means | |
29:54 | down . But if you have given the equation here | |
29:57 | then you got to be careful because if they why | |
29:59 | shift is written on the right hand side as we've | |
30:01 | talked about many times before , this is a shift | |
30:03 | down , this is a shift to the right , | |
30:05 | so I'm just trying to kind of like keep you | |
30:08 | aware of all the gouaches here . And that's some | |
30:09 | books have it one way and some books have another | |
30:11 | way . You look on on on the internet and | |
30:13 | you'll see the vertex form one way and the vertex | |
30:16 | form another way . And so there's no right way | |
30:18 | , it's just where do you put that y shift | |
30:20 | on the left or on the right ? So make | |
30:22 | sure you can do every one of these problems and | |
30:23 | then follow me on to the next lesson . We're | |
30:25 | gonna get more practice with practice graphing parabolas . |
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