07 - Equation of a Circle & Graphing Circles in Standard Form (Conic Sections) - By Math and Science
Transcript
00:00 | Hello . Welcome back to algebra . The title of | |
00:02 | this lesson is called comic sections circles part one . | |
00:06 | So a title at this this way because we're going | |
00:08 | to be learning about circles for the next five or | |
00:11 | six lessons , really diving into the details . But | |
00:14 | I also want you to keep in mind that it's | |
00:15 | part of the family of of of shapes that we | |
00:18 | call comic sections . We've already talked about the fact | |
00:20 | that we have circles . That's a comic section . | |
00:22 | We have ellipses , we have parabolas and we have | |
00:25 | hyperbole is we have four comic sections which can be | |
00:28 | obtained from taking cones , just a regular cone and | |
00:31 | slicing them in different ways . We get these different | |
00:33 | shapes called the comic sections . So we're gonna talk | |
00:35 | about probably the most important one . Circle . The | |
00:37 | most beautiful shape . It's always been said throughout history | |
00:40 | is a circle because it goes back in it joins | |
00:43 | back to its starting point . All right , So | |
00:46 | what we're gonna do in this lesson is I'm going | |
00:47 | to give you the equation of a circle right here | |
00:49 | in the beginning , we're gonna do a few quick | |
00:51 | examples to show you how to graph or how to | |
00:54 | sketch the shape of a circle . But really in | |
00:57 | the beginning here , you won't understand why that's the | |
00:59 | equation of a circle , right ? You're not going | |
01:01 | to really understand that . But the next part of | |
01:03 | this lesson , right after we get through with the | |
01:05 | first examples , we're going to really dive in and | |
01:07 | show why this equation I'm about to write on the | |
01:10 | board actually does describe the shape of the circle because | |
01:13 | I want you to understand what you're doing . I | |
01:15 | don't want you to just blindly trust me , I | |
01:17 | want you to understand . Hey , there's a , | |
01:19 | there's a logical way I can understand what this equation | |
01:22 | really is . So let's first write this equation down | |
01:25 | again , one of the most important equations . So | |
01:27 | here we have what we call a circle and you | |
01:30 | all know in general what a circle is . It | |
01:32 | has a central point . In all of the points | |
01:35 | on the circle are an equal distance away , which | |
01:37 | we call the radius from the central point . So | |
01:40 | what we say is if we have a center of | |
01:44 | the circle at the point H comma K . Because | |
01:48 | this circle we're going to draw , it can be | |
01:50 | in the center of the xy plane , or we | |
01:53 | can move the circle anywhere we want left , right | |
01:55 | up down in the xy plane , so it has | |
01:57 | to have some center . We call it H . | |
01:59 | K . These are just placeholders . The center of | |
02:01 | the circle can be one comma to the center of | |
02:04 | the circle can be negative 19 comma seven . The | |
02:07 | circle can be centered at 00 or any other value | |
02:10 | can come up with . So it has a center | |
02:12 | at H . Comma K . And a radius which | |
02:16 | we denote by our which is obvious because it's a | |
02:18 | radius . Right ? So what is the equation of | |
02:21 | the circle ? And this is the famous equation of | |
02:24 | a circle in general ? A circle has this form | |
02:26 | all circles look like this X minus h quantity squared | |
02:30 | plus why minus K . Quantity squared is equal to | |
02:35 | r squared . Now I'm gonna let that sink in | |
02:38 | for a little second even though you don't really understand | |
02:40 | why it's the case . But I'm gonna I'm gonna | |
02:42 | circle it on the board because we're gonna leave it | |
02:43 | up there . Now in general were saying the center | |
02:47 | is at H . Comma K . So we're saying | |
02:49 | the center of the circle can be anywhere that we | |
02:51 | want it to be . But for now let's just | |
02:53 | pretend the circle is centered at the origin , right | |
02:56 | ? The circle is centered at the origin . If | |
02:58 | the center then is at zero comma zero then this | |
03:01 | is zero and this is zero and then the entire | |
03:03 | equation boils down to x squared plus y squared is | |
03:07 | equal to r squared . So the equation of a | |
03:10 | circle is quite beautiful really . When you think about | |
03:12 | it , you have the X variable squared plus the | |
03:14 | Y variable squared is equal to whatever the radius is | |
03:17 | squared . Now you don't understand yet why this actually | |
03:21 | does describe the circle . In fact , this equation | |
03:23 | looks really weird compared to any equation or function that | |
03:26 | we have drawn in the past , right ? Because | |
03:28 | usually when we grab things , we put why the | |
03:32 | variable Y on one side of the equal sign and | |
03:34 | everything else on the other side . So we have | |
03:36 | for instance , Y equals mx plus B or three | |
03:39 | X plus four for a line or for a parabola | |
03:42 | will say why equals 16 X squared . Or for | |
03:45 | any other polynomial why is equal to two X squared | |
03:48 | plus three X plus four always why is on one | |
03:50 | side of the equal sign and everything else is on | |
03:53 | the other side of the equal sign . Which lets | |
03:54 | us plot the thing . But this is different because | |
03:57 | we have the X . Variable in the Y . | |
04:00 | Variable variable which are both squared . Of course we | |
04:03 | have the H . And the K . We'll talk | |
04:04 | about that later but they're both squared and they're both | |
04:07 | on one side of the equal sign . So it's | |
04:08 | not set up like the other equations you've ever plotted | |
04:11 | before . And that's because Connick sections are just a | |
04:13 | little bit different . All of them are like that | |
04:15 | . The equation of a circle is set up this | |
04:17 | way it looks a little different . The equation of | |
04:19 | their lips looks very , very different than other equations | |
04:22 | you've plotted or looked at before . The equation of | |
04:25 | hyperbole and parables also look different . So you're just | |
04:27 | gonna have to get used to the idea that the | |
04:29 | comic section equations look a little bit different than what | |
04:32 | you've graft in the past , and that's because they're | |
04:34 | defined in a different way . So in fact one | |
04:37 | thing I want you to keep in the back of | |
04:38 | your mind is one reason why circles look so different | |
04:41 | . The equation of a circle looks different is it | |
04:43 | turns out a circle is not a function . And | |
04:46 | I know you might say well if it's not a | |
04:47 | function , why do we care ? Well , lots | |
04:48 | of things are important in our functions . And this | |
04:50 | is one of the most important ones . The circle | |
04:52 | is not a function because if you think about a | |
04:54 | circle being circular figure , it fails that vertical line | |
04:57 | test . Remember we said long time ago with functions | |
05:00 | that in order for it to be a function there | |
05:02 | needs to be a 1 to 1 correspondence between the | |
05:05 | X . Value and the Y . Value , you | |
05:07 | know ? So that means it passes that vertical line | |
05:09 | test . If it's a function . Now with a | |
05:12 | circle , of course you're gonna always cut through two | |
05:14 | halves of the circle , no matter how you do | |
05:15 | the vertical line test . So it's not a function | |
05:17 | . Does it mean a circle is not important ? | |
05:19 | Of course not . Circles are one of the most | |
05:21 | important things . All right . So let's jump into | |
05:24 | some examples to show you how to use this equation | |
05:26 | really quickly and then we're gonna derive it . I'm | |
05:28 | gonna show you where it comes from . All right | |
05:30 | . So , let's take the most simple circle I | |
05:31 | can probably think of Here is the simplest one in | |
05:34 | existence . X squared plus Y squared is equal to | |
05:37 | one . This is an equation of a circle . | |
05:39 | You might say . How does he know ? It's | |
05:41 | an equation of a circle ? Well , the way | |
05:42 | you know is because it follows this form , you | |
05:45 | have the X variable square plus the y variable squared | |
05:48 | equals something squared . Yes , I know it's a | |
05:50 | one but when you think about it , one is | |
05:52 | really one squared . So the right hand side is | |
05:55 | something squared , right ? And you might say , | |
05:57 | well wait a minute , it's different than this . | |
05:58 | Well not really . If the center is H comma | |
06:01 | K . Then we know from this that I can | |
06:04 | write this . You know I I didn't give it | |
06:07 | to you this way but I could write it as | |
06:08 | hr minus zero squared . I'm sorry x minus zero | |
06:10 | squared plus why minus zero square is equal to one | |
06:15 | square . So I'm not gonna give it to you | |
06:17 | like that on a test . I'm gonna give it | |
06:18 | to you like this . And I'm gonna say hey | |
06:20 | what is the center and what is the radius of | |
06:22 | that circle ? And in your mind you need to | |
06:24 | say well I can that's really a shift , a | |
06:26 | shift of the centre by zero units and a shift | |
06:29 | of the centre in the y direction by zero units | |
06:32 | . And so what this really tells me is the | |
06:34 | center of the circle is located at 0:00 and the | |
06:40 | radius is equal to one . Why is it one | |
06:45 | ? Because the right hand side is r squared . | |
06:47 | The radius is what we call our but the right | |
06:50 | hand side is r squared . So really defined the | |
06:52 | radius . You take the square root of one , | |
06:54 | and so the radius is equal to one . So | |
06:58 | the bottom line for a circle , you read the | |
07:00 | center directly out of how the X and Y variables | |
07:03 | are shifted and the radius is read directly off the | |
07:06 | right hand side . You take the square root of | |
07:08 | whatever is on the right hand side . Because remember | |
07:10 | the right hand side is the radius squared . So | |
07:13 | to read the radius out , I take the square | |
07:14 | root to get back the radius that I have . | |
07:16 | So this particular circle , for instance , if I | |
07:20 | wanted to draw or sketch it , I'm not gonna | |
07:22 | sketch every one of these things , but we just | |
07:24 | put it off in a little xy plane here . | |
07:27 | The center is located at zero comma zero . That | |
07:29 | means the center is right in the center of the | |
07:31 | coordinate system and the radius is one . Now the | |
07:33 | radius of a circle means all of the points on | |
07:36 | the circle r the distance radius one radius unit , | |
07:40 | however far the radius is away from the center . | |
07:42 | So the way the sketch it is , if this | |
07:45 | is one and this is one and this is negative | |
07:48 | one and this is negative one , then the circle | |
07:51 | must go through all these points because the radius is | |
07:53 | one . So if I'm gonna sketch and I'm gonna | |
07:55 | go down , I'm gonna go down through here , | |
07:57 | I'm gonna go up through here and I'm gonna go | |
07:58 | up through here . Is that a perfect circle ? | |
08:00 | No , you can tell . It's lopsided the way | |
08:02 | I've drawn it here because I didn't do my tick | |
08:04 | marks perfectly . But you get the idea when you | |
08:06 | sketch it , you're saying one unit away , one | |
08:08 | unit away , one unit away , one unit away | |
08:11 | . The center is read directly out . The radius | |
08:13 | is read by taking the square root of the right | |
08:14 | hand side . I do not expect you to understand | |
08:17 | yet why this equation actually gives you this shape . | |
08:22 | We haven't talked about that yet . For now I | |
08:25 | want you to trust me . And let's do a | |
08:26 | couple of quick little examples . And then when we | |
08:29 | get through those , I will show you exactly why | |
08:31 | this equation actually produces the shape . All right . | |
08:35 | So for now let's let's just kind of plow ahead | |
08:38 | and let's take a look at another circle . Let's | |
08:40 | say I give you another circle X -1 quantity squared | |
08:44 | plus why minus one quantity squared is equal to 25 | |
08:50 | . Now , first you ask yourself , does it | |
08:52 | follow the form of what I have here ? And | |
08:54 | the answer is yes , X minus some number squared | |
08:57 | . Why minus some number squared radius squared . So | |
09:00 | the way you do this is you read the center | |
09:03 | directly out of the equation . So the center of | |
09:06 | this circle is located at 1:01 and the radius Is | |
09:15 | equal to whatever's on the right hand side . You | |
09:16 | take the square root of 25 , so the radius | |
09:19 | is equal to five . Notice I picked this number | |
09:21 | nicely , so I could take the square root of | |
09:23 | it uh there but you don't have to have a | |
09:26 | nice number . If I put 10 on the right | |
09:27 | hand side , then the radius we the square root | |
09:30 | of 10 . The square root of 10 is an | |
09:32 | ugly number but it's a number . If whatever numbers | |
09:35 | on the right , you take the square root of | |
09:36 | it . If you don't have a nice perfect square | |
09:38 | , it's okay . You just have A radius that | |
09:40 | some decimal units long . Of course you can have | |
09:42 | a circle with a 1395 centimeter radius . Of course | |
09:47 | that can happen . But in this case I'm choosing | |
09:49 | nice numbers so notice what we're saying if the center | |
09:52 | is that H comma K . It's x minus h | |
09:55 | y minus K . So I just read the center | |
09:57 | directly off this minus business comes directly from the idea | |
10:00 | of shifting a function . Now we've talked about shifted | |
10:04 | functions great length in the past and I don't want | |
10:07 | to get into an entire lesson on why this shifted | |
10:10 | version with these minus signs produces a shift to the | |
10:12 | right . I've done that many many times in the | |
10:14 | past but probably the easiest way to do it is | |
10:17 | to compare this equation x squared plus y squared is | |
10:19 | one with this equation x minus one squared y minus | |
10:23 | one squared . And you can , in your mind | |
10:24 | you can replace this with a one . Basically this | |
10:26 | equation is shifted to the right one unit and up | |
10:29 | one unit . Because if I put a one in | |
10:31 | here and I put a one in here I'm gonna | |
10:33 | get a zero square and zero squared . If I | |
10:37 | put a zero here I'm gonna have a zero squared | |
10:39 | in a zero square . So the bottom line is | |
10:42 | the only way I can get these equations to kind | |
10:44 | of like look similar to one another is if I | |
10:46 | shift every X value to the right one unit because | |
10:50 | one minus one is zero and every why value up | |
10:53 | one unit because one minus one is zero . So | |
10:55 | when you're comparing the basic equation of a circle , | |
10:57 | this is the basic equation of a circle . The | |
11:00 | equivalent shifted version would look something like this , X | |
11:03 | minus , let's say two quantity squared plus y minus | |
11:07 | two quantity squared is equal to one . So I'm | |
11:10 | claiming that this equation is exactly the same shape as | |
11:14 | this , one has the same radius , but this | |
11:16 | one is shifted to the right to units and up | |
11:19 | two units . And the reason or I don't want | |
11:21 | to get into a bunch of lecturing on it . | |
11:23 | But the reason that it's that way with a minus | |
11:25 | sign shifting to the right and a minus sign shifting | |
11:27 | up is because when you compare these equations are exactly | |
11:30 | the same . But if I want to for instance | |
11:32 | , make this quantity zero here . The only way | |
11:34 | I can do it is to feed X values in | |
11:36 | here two units bigger than I'm feeding them in here | |
11:40 | Because to -2 as zero . So if I want | |
11:42 | these to be , I mean we know it's the | |
11:43 | same shape , we know they have the same radius | |
11:45 | , But I want to figure out how to make | |
11:47 | them kind of equivalent . How do I go from | |
11:49 | here to here . And the only way I can | |
11:51 | do that is to feed x values and that our | |
11:53 | two units bigger than that two minutes to giving you | |
11:55 | 00 being here . And also the same thing with | |
11:59 | why if I envision feeding a Y value of zero | |
12:02 | in here , the only way I can do it | |
12:03 | is to feed a Y unit into this equation two | |
12:05 | units bigger . So it's the same exact shape . | |
12:08 | It's just shifted over to the right and up two | |
12:11 | units over to the right to units and up two | |
12:13 | units . Because the only way that I can feed | |
12:15 | the same values as I'm feeding into the base equation | |
12:18 | is to feed two units bigger into the shifted version | |
12:22 | . That's why it becomes shifted over to the right | |
12:24 | and shifted up there . All right . So anyway | |
12:27 | , getting back to our problem is shifted over to | |
12:29 | the right and up one . So the center is | |
12:31 | 11 The radius is five . Now , we're not | |
12:33 | gonna do this for every single problem , but let's | |
12:35 | go ahead and sketch this one as well . So | |
12:38 | here is X . Y . Plane , right ? | |
12:42 | And the center of this thing is that one comma | |
12:44 | one . So here is one comma one . We're | |
12:46 | gonna put a dot right here . Now the center | |
12:47 | is no longer at the origin . The center is | |
12:49 | shifted over to the right up one , but the | |
12:51 | radius is five . So how do we do that | |
12:54 | ? Well , you have to be five units away | |
12:55 | . So 12345 I'm gonna put a little tick mark | |
12:59 | here , 12345 and put a little tick mark here | |
13:04 | . I need to go to the left five units | |
13:05 | one , 2345 And put a little tick mark here | |
13:09 | and then I need to go down 12345 Need to | |
13:13 | put a tick mark here . I put these little | |
13:15 | tick marks here because that helps me guide my pencil | |
13:19 | whenever I am drawing the circle . And of course | |
13:22 | I'm not a good artist . So it's not going | |
13:23 | to be a good drawing . But you see the | |
13:25 | idea here , when you look here at the at | |
13:28 | the uh , my pencil is a little bit too | |
13:30 | long , but you can see the radius is five | |
13:32 | units of constant five units away . So basically you | |
13:34 | put your center down , you count five units down | |
13:37 | five units up five units to the right , five | |
13:39 | units to the left foot . A little tick mark | |
13:41 | . And then you can of course see that . | |
13:43 | This is 123456 This is six units away . This | |
13:46 | is negative one negative two negative three . This is | |
13:47 | negative four units away and so on . I can | |
13:50 | count up and count down as well . All right | |
13:54 | , we're gonna get a little more practice with the | |
13:56 | circle business before we move on . What if we | |
13:58 | have the circle X minus two plus , Why squared | |
14:03 | is equal to 16 ? Now , a lot of | |
14:04 | students look at a circle like this and say , | |
14:06 | well , it doesn't really look like a circle . | |
14:08 | It's uh sorry , Mr squared there . It's um | |
14:11 | it looks different . This one shifted in , this | |
14:13 | one isn't Okay , well , that's fine . If | |
14:15 | you want to in your mind transform this , That's | |
14:18 | fine too . You don't have to do this . | |
14:20 | But a lot of times what I'll tell people to | |
14:21 | do , as I say , write it like this | |
14:23 | instead of why squared ? Right ? It is why | |
14:25 | zero squared . Now suddenly it mirrors exactly what the | |
14:29 | form of the circle should be . If you were | |
14:32 | going to read the center of the circle off of | |
14:34 | this equation , what would the center be ? The | |
14:37 | center would be ? There's a shift to the right | |
14:40 | to units . That means that the center is two | |
14:43 | units to the right , but the shift up or | |
14:45 | down is really zero . So it's just two comma | |
14:47 | zero , that's the center , Right ? The radius | |
14:50 | is whatever is on the right hand side , you | |
14:52 | take the square root of it . Because what's on | |
14:54 | the right hand side of this equation is the radius | |
14:55 | squared . So that means the radius is squared of | |
14:58 | 16 , which is four . Okay , again , | |
15:02 | we're not gonna do sketching of a million of these | |
15:04 | things , but we will do a little bit here | |
15:08 | . So the center here being at two comma zero | |
15:11 | means the center is 12 units over comma zero means | |
15:14 | it's right on the line right there and the radius | |
15:17 | is four units . So I have 1234 units to | |
15:21 | the right . 1234 units up . I'm gonna put | |
15:24 | a little tick mark there because that's where my radius | |
15:26 | is gonna be , 1234 tick marks to the left | |
15:30 | and 1234 tick marks directly below . Now you see | |
15:35 | I have a tick mark all through here that I'm | |
15:37 | gonna try to go through . Is it perfect ? | |
15:41 | No , but that's mostly what you're trying to do | |
15:43 | . Two comma zero radius of four . You can | |
15:45 | see it's a constant distance away from the center of | |
15:48 | this guy . So the base equation of the circle | |
15:51 | is just X squared plus y squared is r squared | |
15:53 | . Whatever you're doing inside the parentheses , shifting the | |
15:56 | thing left or right up or down is just determining | |
15:58 | where the new center is . Again . Because when | |
16:02 | I shift the thing , I have to feed units | |
16:04 | have to feed X and Y values two units bigger | |
16:07 | and why value two units bigger in order to give | |
16:10 | me the same shape as my original base equation . | |
16:13 | All right now I want to do a couple of | |
16:16 | more and I think I want to try to squeeze | |
16:17 | them in over here because I need to save the | |
16:20 | last two boards for the probably the most important part | |
16:22 | of this lesson here . Let's go and take a | |
16:24 | look at X squared Plus y squared is equal to | |
16:29 | 100 . What would be I'm not gonna graph this | |
16:31 | one , but what is the center and what is | |
16:33 | the radius here ? So , you know , as | |
16:36 | I said , you know , you can it's almost | |
16:39 | exactly the same thing as what we've done up here | |
16:41 | , X minus zero squared , you can write it | |
16:43 | as why minus zero squared ? You can write it | |
16:45 | as but you know you don't have to do that | |
16:47 | , that's something that I tell people to do in | |
16:49 | the beginning . But really when you don't see any | |
16:50 | shift here then you know right away that the center | |
16:54 | is just located at zero comma zero , right ? | |
16:57 | And the radius is just whatever is on the right | |
16:59 | hand side , but you have to take the square | |
17:02 | root of it . So the radius is 10 units | |
17:04 | . So if I wanted to sketch this I would | |
17:06 | draw an X . Y plane , I would put | |
17:07 | the center of the circle right in the in the | |
17:10 | origin right at 00 and I would count 10 units | |
17:12 | to the right . 10 units up 10 units to | |
17:14 | the left . And that would basically draw my circle | |
17:16 | which would be a pretty large circle . Alright , | |
17:18 | so that's just one more little example . I want | |
17:21 | to do one more and have a little space too | |
17:22 | graphic . Um Because it's a little more important , | |
17:26 | what if you have X plus two quantity squared plus | |
17:31 | y minus one quantity squared is equal to nine . | |
17:35 | Now this one looks a little different because the y | |
17:37 | minus one is written just like it is here why | |
17:40 | ? Minus something ? But the ex here there's no | |
17:43 | minus sign . So a lot of times students will | |
17:44 | get confused . Okay when you're shifting functions and I | |
17:47 | covered all of this when we did the original shifting | |
17:49 | functions less than a long time ago . When you | |
17:51 | shift things when you shift any function it could be | |
17:54 | a circle , could be a line , could be | |
17:55 | a parabola , could be cubic , could be a | |
17:58 | square root , anything any graph , you can shift | |
18:00 | anywhere you want on the xy plane . When the | |
18:04 | X variable is shifted with a minus sign , it | |
18:07 | means it shifted in the positive X . Direction . | |
18:09 | When the Y variable as a minus sign shifted shifted | |
18:11 | in the positive Y direction , but when you have | |
18:14 | plus signs it's shifted in the opposite direction . Why | |
18:18 | ? Because you can write this um you can write | |
18:21 | this X plus two , you can write it as | |
18:23 | X minus and minus two if you want to you | |
18:26 | don't have to I'm just trying to give you different | |
18:28 | ways to think about it . Yeah this is perfectly | |
18:32 | exactly the same as this . So this is a | |
18:34 | shift to the right but negative two units . So | |
18:37 | I'm shifting to the right but oh hold on a | |
18:38 | second I'm actually shifting to the left because I'm shifting | |
18:41 | negative two units to the right . So it's a | |
18:43 | little bit of a convoluted way to think about it | |
18:45 | . But the way to really think about it is | |
18:47 | that when you see a plus sign you actually go | |
18:49 | the opposite direction which is left . When you see | |
18:51 | a minus sign you go to the right . So | |
18:53 | the center of this guy , Yeah The center is | |
18:58 | really located at -2 comma positive one like this . | |
19:04 | And the radius is the square root of nine which | |
19:07 | is three like this . Okay . And I will | |
19:11 | try to do a little quick sketch here let's see | |
19:13 | if we can we can fit it in right here | |
19:16 | , we're going to do it we're gonna do it | |
19:18 | right here we're gonna go and say okay we have | |
19:21 | an xy plane where is the center negative two comma | |
19:25 | one . So negative two for X . Here's negative | |
19:28 | one negative two for X . One for why ? | |
19:30 | So there's one for why ? So the the center | |
19:33 | is no longer on the right hand side of the | |
19:35 | plane . It's on the left hand side of the | |
19:36 | plane , the radius is a . Three . So | |
19:38 | you have to count up 123 units from there . | |
19:41 | Put a tick mark 123 units left from there . | |
19:44 | 123 units down from there and 123 units from there | |
19:49 | . So I'm putting a little tick marks there . | |
19:51 | So there's 123123123123 Now I know these tick marks are | |
19:57 | not perfect because they're not evenly spaced and I did | |
19:59 | a little sloppy job with that . But this is | |
20:01 | basically what you're looking for . The reason it looks | |
20:03 | a little bit oblong is because these tick marks are | |
20:06 | a little bit wider than those . But there's there's | |
20:09 | a radius of 123 to the left , 123 to | |
20:13 | the right . It's just that compressed things a little | |
20:14 | bit but that's more or less how you how you | |
20:17 | graph this thing . So now what we've done is | |
20:19 | I've introduced the equation of a circle and you know | |
20:22 | how to use it . But so far you don't | |
20:24 | know why it works . You don't know why . | |
20:25 | I mean when we learn how to graph lines we | |
20:27 | make a table of values and we show that that's | |
20:30 | the graph of the line . We do graph parabolas | |
20:32 | , initially we do a table of values and I'll | |
20:35 | show you that that's how you graph a problem . | |
20:37 | But here for the circle business I just told you | |
20:39 | trust me this is the equation of a circle but | |
20:41 | you don't actually know why it's the equation of a | |
20:42 | circle . So what we're gonna do now is we're | |
20:45 | gonna go and explore that in more detail . It's | |
20:48 | extremely important when you get into higher math to know | |
20:50 | where things come from . Otherwise you're not doing anything | |
20:53 | other than just repeating what you've been taught . So | |
20:57 | what we wanna do is I want to do a | |
20:59 | circle . I want to show a circle with center | |
21:05 | at zero comma zero and a radius of four . | |
21:09 | So what I want to do is draw this and | |
21:11 | I want to figure out what the equation of that | |
21:13 | circle must be . Now we already know what it | |
21:16 | must be because I already showed you what the equation | |
21:18 | of a circle is . But let's pretend we have | |
21:19 | no idea what an equation of a circle is . | |
21:21 | And I want to draw this and I want to | |
21:25 | understand where everything comes from . So what we do | |
21:29 | is we say , okay , I'm gonna go and | |
21:31 | draw an X . Y plane , I'm gonna try | |
21:33 | to draw at large so that we can see everything | |
21:35 | . So there's X . Here's why And the center | |
21:39 | of this circle is 00 right there . And the | |
21:42 | radius is for that means that there must be 1234 | |
21:46 | , must be a little crossing there . 1234 crossing | |
21:50 | there . 1234 crossing there , 1234 crossing there . | |
21:55 | So the circle must look something like this , it | |
21:58 | goes down and then it goes way down here and | |
22:02 | it goes way over here and goes way up . | |
22:04 | Is that perfect ? No , it's not perfect . | |
22:05 | But that's basically what the circle centered at zero radius | |
22:08 | of four looks like . Now , what we want | |
22:11 | to do is we want to recognize that the blue | |
22:14 | line here is the set of all points that make | |
22:17 | up that thing that we call the circle . There | |
22:19 | must be some kind of an equation that will predict | |
22:23 | for lack of a better word . All the points | |
22:25 | that lie on the blue curve , if we can't | |
22:27 | figure out what the equation is of what's on the | |
22:29 | blue curve , then we failed . So we need | |
22:31 | to figure out what the equation is that describes what | |
22:34 | the blue curve is . How do we do that | |
22:36 | ? Well , let's first go over here and say | |
22:38 | , well , let me switch colors . Actually , | |
22:39 | uh up here , we're gonna say that the points | |
22:42 | on this curve uh there's infinite points , of course | |
22:46 | , on this blue curve , but I'm just gonna | |
22:48 | pick one of them right here . And I'm gonna | |
22:50 | say it's point P . Because that makes sense , | |
22:51 | point P . Right ? And this point P has | |
22:53 | a value X . Comma y . Now we're saying | |
22:56 | that the blue curve really is the set of all | |
22:58 | points P . Right ? So there's a point P | |
23:00 | . Here , another point P . Here , another | |
23:02 | point P . Here there's an infinite number of points | |
23:03 | all the way around . And every one of those | |
23:05 | points have a different value . X comma Y . | |
23:08 | Right . This one might be I don't know . | |
23:10 | This is 123 comma 12.8 or something . So this | |
23:14 | might be three comma 2.8 . Whatever you can see | |
23:16 | that as you go around the circle , the different | |
23:19 | values of P . R gonna all be different . | |
23:20 | But there should be an equation to predict what those | |
23:23 | points are . All right ? So what we're gonna | |
23:25 | do to figure this out is the following . We | |
23:27 | want to we want we know , let me put | |
23:30 | it this way that between the center and all of | |
23:33 | the points on here . The critical thing is the | |
23:35 | distance here is what we call the radius . The | |
23:39 | distance here is what we call the radius . And | |
23:41 | we know that it's equal to four units . That's | |
23:44 | the critical thing that lets us figure out the equation | |
23:46 | of a circle , because we know that if the | |
23:47 | point is here , the distance must be four units | |
23:50 | . If the point is over here , the distance | |
23:52 | must also be four units . If the distance is | |
23:54 | here for units , distance here for units , no | |
23:56 | matter where I point the thing , the distance from | |
23:59 | the center must be point For units . Now remember | |
24:02 | I'm saying the distance from the center must be four | |
24:04 | units . The distance from the center must be four | |
24:07 | units . Remember we learn something called the distance formula | |
24:10 | . We know how to find distances anytime . We | |
24:13 | have two points in the xy plane , we can | |
24:15 | just stick it right into the distance formula and calculate | |
24:18 | the distance . And we're saying that all of these | |
24:20 | points have to be four units from the center . | |
24:22 | So we can then write down the equation by using | |
24:26 | that . Now . Remember the distance formula comes directly | |
24:28 | from the pythagorean theorem , which we've discussed a long | |
24:31 | time ago . All right . So if you think | |
24:34 | about it , if this is the point X , | |
24:38 | I'm sorry , P which is X comma Y , | |
24:40 | then there must be some X value right here uh | |
24:46 | corresponding for that value of P . And there must | |
24:48 | be some wise guy . This is the X . | |
24:50 | Comma Y . X . You read it from this | |
24:51 | axis and why you read it from this axis right | |
24:55 | ? And the center , don't forget is located at | |
24:59 | zero comma zero . That's what a center is . | |
25:02 | It's located at zero comma zero . So how can | |
25:04 | we write down what we need to figure out ? | |
25:07 | We know the distance from zero comma zero to whatever | |
25:15 | point we care about X comma Y is equal to | |
25:19 | four . But for this particular circle four units , | |
25:21 | the distance from zero to whatever point . But I | |
25:24 | drew the point here , but I could've drawn the | |
25:26 | point here or here or here . It doesn't matter | |
25:28 | . Whatever the point is , the distance between the | |
25:30 | center and that is four units . So how do | |
25:32 | we write that down ? The way we're gonna write | |
25:35 | that down is called the distance formula . What is | |
25:38 | the distance between 00 and X . Y . Now | |
25:41 | I know we don't know what Xy is , that's | |
25:43 | the whole point . We don't know what P X | |
25:44 | . Y is but we know that there's some point | |
25:47 | has an X . Value and it has some Y | |
25:49 | value . So if if we were going to find | |
25:51 | the distance between here and here , we would do | |
25:53 | it exactly . As we always do remember , the | |
25:55 | distance formula is what it's X two minus X . | |
25:58 | One quantity squared plus Y tu minus y one quantity | |
26:03 | squared . We take the square to that whole thing | |
26:05 | , right ? That's what the distance formula is . | |
26:07 | The only thing about it is we know what one | |
26:09 | of the points is . But the other point we | |
26:11 | don't really know what it is . We just know | |
26:13 | it has some X and some Y value . So | |
26:15 | then to find the distance between them going from here | |
26:18 | , subtracting here , the distance would be whatever X | |
26:21 | is minus zero quantity squared plus whatever . Why is | |
26:27 | minus zero ? This is the distance between those two | |
26:31 | points . Make sure you understand it ? Yes , | |
26:33 | I don't know what X and Y is . Of | |
26:34 | course , I don't know what they are . Could | |
26:35 | be , you know , 12 This would be two | |
26:38 | point something , you know , whatever . Two point | |
26:40 | something . Of course , I don't know what it | |
26:41 | is , but I know it's xy so I take | |
26:43 | X minus the X value . Why , minus the | |
26:46 | Y value . I stick it into the distance formula | |
26:48 | . And I know that this must be equal to | |
26:52 | A distance of four units of four units . Why | |
26:57 | ? Because the radius of the circle is four units | |
27:00 | . I know what the distance is . So I | |
27:01 | calculate the distance between the points and I set it | |
27:04 | equal to four because that's the radius of the circle | |
27:07 | I drew . Now how do I do anything with | |
27:09 | this equation ? I have this large square root but | |
27:12 | I'm going to not deal with that right now . | |
27:13 | Let's go ahead and just rewrite this . This is | |
27:15 | just x minus zero squared . So we can write | |
27:17 | it as X squared . This is why minus zero | |
27:20 | squared , We can write it as this square . | |
27:21 | We still have a square root is equal to four | |
27:23 | . Now , in order to get rid of the | |
27:24 | square and on the left , what do I do | |
27:26 | ? I take the square of both sides ? Right | |
27:29 | ? So I say x squared plus y squared is | |
27:32 | equal to four . I have a square root . | |
27:35 | But what I can do is I can raise the | |
27:38 | left hand side to the power of to and since | |
27:40 | it's an equation , I can do the same thing | |
27:42 | to the right hand side , I can do anything | |
27:44 | . I want to both sides of the equation . | |
27:46 | Now on the left hand side , the square kind | |
27:48 | of cancels with the square root . So all you | |
27:50 | have is X squared plus y squared is equal to | |
27:53 | four squared which is 16 . This is the equation | |
27:56 | of the circle . This is exactly what we would | |
28:00 | expect based on the problems that we did before . | |
28:03 | Right , we said a center of circle always has | |
28:06 | a center h comma K in a radius of four | |
28:09 | . The center is located at whatever the shift is | |
28:11 | here . But in this case the circle that we | |
28:14 | drew on the board , we didn't have any shift | |
28:17 | at all . So we expect it to be , | |
28:18 | X squared plus y squared is equal to something and | |
28:21 | it has to be whatever the radius is squared , | |
28:23 | the radius is for you square it , you get | |
28:25 | 16 . So this is the equation of the circle | |
28:29 | With a radius centered at 0:00 with a radius of | |
28:34 | four . And you can generalize this . So let's | |
28:37 | generalize this . Mhm . Because we drew the circle | |
28:42 | is a radius of four , but we know if | |
28:43 | we make the circle bigger or smaller , the only | |
28:46 | thing that's really going to change is the distance formula | |
28:49 | , we're going to change what's on the right hand | |
28:50 | side . So even if you make it a generic | |
28:52 | are all you're saying is that a circle has the | |
28:55 | general form of X squared plus y squared is equal | |
28:58 | to the radius squared . That's all we did on | |
29:00 | the right hand side , we squared the radius . | |
29:02 | So if the radius were 10 we would square it | |
29:04 | and we would get 100 on the right . If | |
29:07 | the radius were three we would square it and we | |
29:09 | would get nine on the right . So this is | |
29:11 | the equation of a circle Centered at 00 with a | |
29:15 | radius of our whatever that radius is . So that's | |
29:19 | how we go from . Here's a special shape called | |
29:22 | a circle to what is the equation of that now | |
29:24 | . It's not like a traditional equation that you've learned | |
29:27 | before because the Y . Is not by itself on | |
29:30 | the left hand side . It and notice it's not | |
29:32 | a function either because it fails the vertical line test | |
29:36 | , I'm cutting through two values of the relation here | |
29:40 | every time I cut through like this . So back | |
29:43 | to what is a function back we learned a long | |
29:45 | time ago . It's not a function . But that's | |
29:47 | okay . It doesn't mean it's not important . Circles | |
29:49 | are one of the most important shapes in all of | |
29:51 | nature . I mean , really ? And I mean | |
29:52 | that's serious . I mean you get to calculus , | |
29:54 | you're using circles all the time , but it's not | |
29:56 | a function . That's okay . So if you get | |
29:58 | a trick question on the test is a circle of | |
30:00 | function . No , it's not a function , but | |
30:02 | it's an extremely important relation , which is what we | |
30:05 | would call or equation . Now this I went from | |
30:08 | a circle centered at the origin with a radius of | |
30:10 | four and we figured out what the equation of the | |
30:12 | circle must be . So we can generalize this is | |
30:14 | why the equation of a circle looks like this . | |
30:16 | But what if the circle is not centered at 00 | |
30:19 | ? Let's quickly do that . If you can understand | |
30:22 | that , which I know that all of you can | |
30:23 | then the next one is not hard at all . | |
30:26 | Let's shift let's shift the circle . Um two units | |
30:35 | right , and three units down . So what we | |
30:43 | want to do is go through the whole exercise again | |
30:45 | . But with the circle in a slightly different location | |
30:47 | . And we want to show that the thing that | |
30:49 | you get out of it is actually this business . | |
30:51 | We want to show that that describes a circle that's | |
30:54 | shifted anywhere other than the origin . Mhm . All | |
30:58 | right . So , we're gonna draw a xy plane | |
31:01 | so we can always have a picture . I always | |
31:02 | recommend that . So here is our xy plane like | |
31:07 | this . Now we're saying basically that the center of | |
31:11 | the circle is two units to the right and three | |
31:14 | units down . So here's two units to the right | |
31:16 | 123 units down . That means the center of the | |
31:18 | circle is here . So we say the center is | |
31:24 | uh sorry , can still center , we say the | |
31:26 | center is at two comma negative three . Right ? | |
31:30 | And we say the radius is the same as the | |
31:31 | radius before . We're not changing anything . We're saying | |
31:33 | the radius is still four , Everything is the same | |
31:36 | . Um But we're just shifting the thing here . | |
31:39 | So , how do we draw ? Sorry , not | |
31:41 | R equals R . Were saying R is equal to | |
31:42 | four , same as before . We're just shifting the | |
31:45 | thing . So how do we draw this ? Well | |
31:46 | if the radius is four it's 1234 and then 1234 | |
31:53 | We're gonna put a little tick mark there then 1234 | |
31:56 | we put a little tick mark there , then 12 | |
31:59 | then 34 we'll put a little tick mark here . | |
32:02 | So this should describe this circle something like this . | |
32:08 | Now before we go on I want you to agree | |
32:10 | with me that this circle is exactly the same as | |
32:14 | this one . I mean I know I drew it | |
32:15 | maybe it's the tick marks are a little different but | |
32:17 | you see the idea this one's centered at the origin | |
32:19 | radius of four . All I'm doing is shifting it | |
32:21 | over two units three units down . It was originally | |
32:26 | here over two units 3 units down . But the | |
32:28 | circle is the same . I mean the shape of | |
32:30 | the thing is the same . It's just located in | |
32:31 | a different place . So how would I go about | |
32:34 | doing that ? How would I go about figuring out | |
32:36 | what happens here ? Well , we do the same | |
32:38 | kind of thing . We pick a point on the | |
32:40 | circle . Let's call it this one . Let's call | |
32:42 | a point , pete . It's got X comma y | |
32:45 | . The center here is now at two comma negative | |
32:48 | three . That's what the center of the circle is | |
32:52 | , right ? But we also know that the radius | |
32:56 | From this point to this point is four units same | |
32:59 | as before four units exactly the same thing . So | |
33:04 | we're gonna do the exact same thing . We're gonna | |
33:05 | figure out what is the distance , using the distance | |
33:07 | formula from this point to this point . And no | |
33:10 | matter where you are in the circle , the distance | |
33:13 | must be four units . That's what the circle is | |
33:15 | , that . That's what defines the shape of the | |
33:19 | points that we call the circle . So if we're | |
33:21 | gonna put that distance formula in there , we're gonna | |
33:23 | do the same thing . It's X two minus X | |
33:26 | one quantity squared plus y tu minus y . One | |
33:31 | quantity squared . This is the distance between any two | |
33:34 | points in the xy plane . But this point has | |
33:36 | an X coordinate of , we're just calling it X | |
33:39 | . This thing has an X coordinate now too . | |
33:41 | So we have to subtract two . This thing has | |
33:45 | a Y coordinate of why . But this thing has | |
33:47 | a Y coordinate of negative three . So we do | |
33:49 | have to subtract it , but you have a negative | |
33:51 | three here and that's squared . And we take the | |
33:54 | square were saying this distance is what we have written | |
33:56 | down as the distance formula between those two points . | |
33:58 | And we're saying that it's a radius of four units | |
34:01 | away . So we have to put that the distance | |
34:03 | between them is equal to four . Now let's crank | |
34:06 | through this and see what we get . We're gonna | |
34:07 | have X -2 quantity squared . Now we're going to | |
34:11 | have this becomes y plus three quantity squared , We | |
34:17 | have a square root here , and this is equal | |
34:19 | to four . Now the same exact sort of thing | |
34:21 | can happen in order to get rid of the square | |
34:23 | root , we can just square both sides to make | |
34:26 | it clear , I'm gonna say x minus two , | |
34:28 | quantity squared plus y plus three quantity squared . I'm | |
34:33 | going to take the square root , I'm gonna have | |
34:35 | four . Now , in order to make it clear | |
34:37 | what I'm saying is it's an equation , I can | |
34:39 | do what I want to both sides . I'm gonna | |
34:40 | square the left hand side . So then I also | |
34:42 | have to square the right hand side , so immediately | |
34:44 | the square cancels with square root right here . And | |
34:48 | so what you're going to have left over is just | |
34:50 | what's underneath , X minus two , quantity squared plus | |
34:54 | Y plus three quantity squared is equal to 16 . | |
34:58 | Were saying this is the equation of a circle that | |
35:01 | has a radius of four , meaning you take the | |
35:03 | square root of the right hand side but located somewhere | |
35:06 | other than zero comma 02 units to the right , | |
35:09 | three units down , let's go back and look and | |
35:11 | see if that makes sense . Center is located . | |
35:14 | H comma K radius . And of course I can't | |
35:17 | spell radius . Sorry about that radius of our um | |
35:22 | the shift of the white in the Y . Direction | |
35:25 | is what do we have , what do we pull | |
35:26 | out of it ? Uh Two units to the right | |
35:30 | , in the X . Direction . And because there's | |
35:31 | a plus sign , it's actually the opposite direction , | |
35:34 | three units down , that's exactly what we would predict | |
35:36 | from here . It's two years to the right , | |
35:38 | this is a plus sign . So it was three | |
35:39 | units down , so we can then generalize exactly as | |
35:43 | we did before that . Really , the equation of | |
35:46 | a circle is X minus h quantity squared plus why | |
35:49 | minus k quantity squared is equal to whatever the radius | |
35:53 | is . Because we just picked a circle here . | |
35:55 | So this is the general circle , right ? And | |
36:01 | all circles will look like that . You put the | |
36:03 | equation the equation of a circle down on your paper | |
36:06 | , you put the center in , you put the | |
36:07 | radius in , you square the thing and that and | |
36:09 | that's what it is . That's what the equation of | |
36:11 | a circle is . It comes directly from the distance | |
36:13 | from formula , knowing that the distance between the center | |
36:17 | to any point on the circle has to be the | |
36:18 | same for all the points . And so we just | |
36:19 | crank through it . So make sure you understand this | |
36:23 | . You should understand the general idea of what a | |
36:24 | circle is , you should understand where it comes from | |
36:26 | . We're not done not by a long shot . | |
36:28 | We need to sketch circles , we need to do | |
36:30 | more complicated problems . We need to do all kinds | |
36:32 | of things . We have a lot to do , | |
36:33 | but this is the most important part of it all | |
36:35 | . Follow me on to the next lesson will continue | |
36:38 | conquering comic sections and specifically circles . |
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