How To Derive The Sum Formula of a Geometric Series - Free Educational videos for Students in K-12 | Lumos Learning

How To Derive The Sum Formula of a Geometric Series - Free Educational videos for Students in k-12


How To Derive The Sum Formula of a Geometric Series - By The Organic Chemistry Tutor



Transcript
00:00 in this video , we're going to talk about how
00:02 to prove the formula that will help us to calculate
00:06 the sum of a geometric series and there's two of
00:09 them . There's a finite geometric series and the infinite
00:12 geometric series . We're going to talk about how to
00:14 prove the formula to calculate the sum of both of
00:17 those . So let's start with a geometric sequence .
00:22 Let's say we have a sequence three six 12 24
00:30 48 96 and so forth . three is the first
00:36 term . Six is the second term . 12 is
00:39 the third term . The common ratio is too you
00:46 need to multiply the first term by two to get
00:48 the second term three times to a 66 times two
00:52 is 12 , 12 times two is 24 . So
00:57 we have a common ratio of two . So no
01:01 to at the second term is the first term times
01:05 are six is 3 times two . The third term
01:11 is the first term times r squared 12 , His
01:17 three times 2 squared What three times for . Likewise
01:22 , if you want to find 1/4 term , it's
01:24 the first term times our cube 4 -1 History .
01:33 Make sure you understand that . Because we're going to
01:35 use that later to prove the formula . Now ,
01:39 what we have here is a sequence to convert it
01:43 into a series . We need to use the addition
01:46 sign . So this is a geometric series . So
01:54 let's add up the first six terms . So this
01:57 is going to be S6 , the partial some of
02:00 the first six terms , three plus six plus 12
02:07 plus 24 plus 48 plus 96 . That's 189 .
02:18 Now , let's use the formula to calculate that son
02:22 . This is the formula that helps us to calculate
02:24 the sum of a finite geometric series . It's a
02:28 sub one times one minus R a c n over
02:33 one minus R . So to calculate as sub six
02:37 is going to be a sub one the first term
02:39 which is three Times 1 -2 . Ours too .
02:45 It's race to the end And is basically the number
02:48 of terms which is six Over 1 -2 . So
02:53 this is going to be three one minus two races
02:57 . Six power . If you multiply 26 times You
03:01 get 64 , 1 - She was -1 , 1
03:06 -64 is -63 . The two negative signs will cancel
03:10 becoming positive . So it's three times 63 . three
03:15 times 6 is 18 , three times 3 is nine
03:18 . So we get 189 which is the same as
03:21 what we see here . So this is the formula
03:24 that helps us to calculate to some of a finite
03:29 geometric series . Now , what if we were to
03:34 have an infinite geometric series ? So let's say we
03:39 have the series eight plus four Plus two Plus 1
03:44 plus one half plus 1/4 and then plus dot dot
03:50 dot . So this series here it has the beginning
03:55 and it has an end . So it's a finite
03:58 geometric series . This series doesn't have an end ,
04:02 it goes on forever . So it's an infinite geometric
04:05 series . The common ratio , if you take the
04:10 second term divided by the first four divided by eight
04:13 is one half . The combination is 1/2 for all
04:16 terms . Now because the common ratio or rather the
04:21 absolute value of art Because it's less than one .
04:24 The series converges which means that the sum is finite
04:30 . If the absolute value of our if it was
04:32 greater than one , this series will diverge . And
04:35 you're you wouldn't be able to calculate the sum because
04:38 it can increase towards positive or negative infinity . So
04:42 it's important that the common ratio , the absolute value
04:45 of income ratio be less than one for this to
04:47 work . And the sum of this infinite geometric series
04:53 , we can write s sub infinity . It's the
04:58 first term divided by 1 -1 . So in this
05:01 example it's 8/1 minus a half . 1 -1 ,
05:09 eight divided by a half . If you multiply the
05:12 top and bottom by two , This becomes 16/1 ,
05:16 which is 16 . So if you were to add
05:19 these numbers eight plus four is 12 plus two ,
05:23 that's 14 plus 1 , 15 Plus 1 15.5 Plus
05:30 14 , If you keep doing this you're gonna get
05:33 closer to and closer to 16 but you're not going
05:35 to pass 16 . So that's the some of this
05:40 infinite geometric series . Now let's talk about how to
05:43 prove this formula as well as the other one .
05:50 So let's start with the formula that describes the sum
05:53 of an finance geometric series . So we're gonna have
06:00 S . S . N . Is a one plus
06:05 a two plus a three plus a four . And
06:13 then the second to last term is a sub N
06:15 -1 And the last term will be a seven .
06:24 Now , a sub two . Recall that a sub
06:27 two is a 71 times are and a sub three
06:32 . We said that it's a 71 times R squared
06:36 A four is a sub one times our Cube .
06:42 By the way , the formula that describes the f
06:45 term of a geometric series Or a geometric sequence is
06:50 a sub one . Our race to the N -1
06:55 . So in our first example where we had the
06:56 series or the sequence three , 12 24 48 let's
07:04 say . If we want to calculate the fifth term
07:06 , It would be a sub five Is equal to
07:09 a sub one which is three times are ours too
07:12 . Race the end -1 Or 5 -1 . 5
07:16 -1 is four . 2 to the 4th power two
07:20 times two times two times two at 16 , three
07:23 times 16 is 48 . So this formula here gives
07:27 you the f term of a geometric sequence . So
07:40 listening about that , if a sub N is a
07:43 sub one times are Race to the N -1 ,
07:47 What is a sub and -1 ? A 7 -1
07:52 . It's gonna be a sub one times are but
07:55 we're going to plug in and -1 into that expression
07:59 . So replace an end With N -1 . We
08:03 get a sub one . Are race to the End
08:06 monastery And that's what we're going to replace this thing
08:09 with . It's going to be a someone are To
08:14 the end -2 and then a sub N . We
08:17 already have that here . That's just a one To
08:21 the end -1 . Now for the next line ,
08:30 what we're gonna do is we're going to take this
08:32 equation and we're gonna multiply it by our so the
08:36 speed , this is gonna be our sn and then
08:41 this is going to be a one times are this
08:47 becomes if you multiply by our it's going to be
08:50 a one R squared and then plus a one .
08:54 Our cube plus a one Are to the 4th and
09:02 then multiply this by our The exponent is going to
09:05 increase by one . So N -2 plus one that's
09:11 going to be and minus one multiplying this by our
09:16 the export will increase by one as well . So
09:19 n minus one plus one Becomes simply and -1 and
09:23 positive one will cancel . Now what we're gonna do
09:28 is we're gonna multiply this equation by -1 . So
09:32 this is going to be negative . And then every
09:35 term within the bracket , once we distribute the negative
09:40 sign will be negative . So now we're gonna add
09:45 these two equations . So we're gonna have S seven
09:50 N plus negative R . S . F . N
09:54 . Or simply ss men minus R . S .
09:58 Event . And then we'll have a one . Now
10:07 A one AR -1 R . They're going to cancel
10:14 a one R squared minus a one R squared .
10:20 They will cancel as well . A one Our Cube
10:23 is going to cancel A one arch . The fourth
10:27 will cancel with something that's here and then A one
10:35 RN -2 will cancel with something that's there . And
10:39 then a one RN -1 will cancel as well .
10:45 This one will not cancel so but it has a
10:47 negative sign . So it's gonna be negative . A
10:51 one are raised to end . Now what we're gonna
10:54 do is we're going to factor out s event S
10:59 . M.N . by itself is one negative R .
11:03 S . F . N . Divided by S .
11:04 F . N . Is going to be negative .
11:06 Are Here we're going to factor out the first term
11:09 a sub one . A someone divided by itself is
11:13 one negative A one R . C N divided by
11:17 a one is negative . Our race to the end
11:22 And then we're gonna divide by 1 -2 . So
11:29 this gives us the formula for the partial sum of
11:31 a finite geometric series . It's the first term times
11:36 one minus the common ratio race to the end over
11:39 one minus R . So that's how we can derive
11:45 the son of a finite geometric series . Now ,
11:50 let's talk about how we can get this formula in
11:56 order to get that formula , we need to realize
11:59 that if the the absolute value of our is less
12:04 than one , and as N goes to infinity ,
12:10 our race to the end Goes to an Eagles0 ,
12:14 not infinity . Now , let's talk about that .
12:18 So if we have .9 , which is less than
12:21 one , raise the first power , that's 0.9 .
12:25 But what happens if we increase the exponent from 1-10
12:30 ? Will this number get bigger or lower .9 ?
12:35 Race to the 10th Power Is a smaller number .
12:39 It's .348 678 Let's use the approximate symbol . Now
12:53 , let's increase it to 100 .9 . Race to
12:58 100 . It's even smaller , it's point 00002656 .
13:09 So we can see that the limit as N goes
13:15 to infinity of our sub . And assuming that our
13:20 is less than one or the absolute value of our
13:22 is less than one . This Becomes a zero when
13:27 an approaches infinity . So the sum of an infinite
13:35 geometric series where The absolute value of ours less than
13:39 one . This is going to be the limit as
13:44 N goes to infinity of the the finite geometric series
13:48 formula , which is a sub one times one minus
13:52 our race of the N Over 1 -2 . Now
13:57 this is the only part of the equation that has
13:59 ended And we know that are to the end will
14:02 go to zero once we apply This limit , so
14:06 it becomes a sub one times 1 -0/1 -2 .
14:11 And 1 0 is simply one . A sub one
14:17 times 1 is simply a sub one . So the
14:20 sum of an infinite geometric series Boy , the athlete
14:24 valley of ours , less than one Is this equation
14:27 a sub 1/1 -2 . So that's how you could
14:31 derive it from this formula . It's by realizing that
14:36 as N goes to infinity are certain goes to zero
00:0-1 .
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