Trigonometry made easy - By tecmath
Transcript
00:00 | get a welcome to Tech Math channel . What we're | |
00:02 | going to be having a look at in this video | |
00:04 | is trigonometry . So sit back and learn all about | |
00:06 | it and if you like the video , please remember | |
00:08 | hit the like button beneath the video there and subscribe | |
00:11 | to the Tech mouth channel . So trigonometry deals with | |
00:14 | this particular shape here , a right angle triangle . | |
00:17 | And what it does is it's a branch of mathematics | |
00:20 | that studies the relationships between the science of this triangle | |
00:23 | and the angles that occur within it . Okay , | |
00:26 | so pretty much we can use say an angle here | |
00:30 | and a side length to work out other side leaks | |
00:33 | . Or we could use tattoo side legs here to | |
00:35 | work out unknown angles . That's what trigonometry allows us | |
00:38 | to do . So how does it do this ? | |
00:40 | Well , it's fairly simple if we want to consider | |
00:43 | , say an angle here in this triangle . So | |
00:46 | I'm just going to put this down and this angle | |
00:47 | here is called feta . Pretty much what it's saying | |
00:50 | is this for this particular angle here , in a | |
00:53 | right angle triangle , in this particular location , In | |
00:56 | that right angle triangle . These two side links here | |
00:59 | would have a particular ratio . They would always be | |
01:02 | an equivalent length compared to one another . Okay , | |
01:05 | this length and this length would have a certain ratio | |
01:07 | of this length and this length would have a certain | |
01:09 | ratio . And trigonometry uses this to be able to | |
01:12 | work out unknown side lengths and unknown angles . So | |
01:17 | how do we do this ? Well , the first | |
01:18 | thing we have to do is we have to be | |
01:20 | able to label the sides of this particular triangle . | |
01:24 | So in this particular triangle , you notice we've got | |
01:26 | a right angle here , we have this angle feta | |
01:28 | , which we are we've already labeled here . We | |
01:31 | also have three sides here , we have this longest | |
01:34 | side here . The longest side is called the high | |
01:37 | pot news . I'm going to write that in the | |
01:38 | high pot and news . I'm going to put that | |
01:42 | down as a high church here we have the opposite | |
01:46 | side . Alright that over here . The opposite . | |
01:50 | What I mean by that this particular side is opposite | |
01:53 | feet up . We put that down as a no | |
01:56 | along this particular side , this remaining side which is | |
01:59 | next to feeder . We have the adjacent adjacent adjacent | |
02:04 | means next to . And we label that with an | |
02:07 | A . So now we've done that as I would | |
02:10 | say all these sidelines here , the opposite the adjacent | |
02:13 | to high point news . All have particular ratios to | |
02:17 | one another based on whatever this particular angle here is | |
02:21 | . Okay , so there's three different functions we are | |
02:24 | thinking about when we're thinking about these ratios because we | |
02:26 | have three different ways . We can compare the sides | |
02:28 | . We can be comparing these two sides to feed | |
02:30 | her or these two sides . We can be comparing | |
02:33 | these two sides and our three main trigger gnomic functions | |
02:37 | are as follows . We have the sine function which | |
02:40 | is the ratio of the opposite and the high point | |
02:43 | news . We have the cosine function which is the | |
02:47 | ratio between the adjacent and the high pot news . | |
02:51 | And we have the tangent function which is the ratio | |
02:55 | between the opposite and the adjacent function . Now there's | |
03:00 | a really really easy way we can remember these when | |
03:03 | we're doing these and this is as follows . Alright | |
03:05 | this pneumonic down right now and here it is . | |
03:08 | Some old hags can't always hack their old age . | |
03:12 | Okay . Shh . Sine equals opposite over . Hypotenuse | |
03:17 | can't always hack cause eagles adjacent . Over . Hypotenuse | |
03:20 | , their old age tan equals opposite over adjacent . | |
03:24 | So when I was solving a trigger gnomic equation , | |
03:27 | pretty much the very first thing I do is what | |
03:30 | we did . First off here , I'd label these | |
03:31 | unknown sides . The next thing I do is I | |
03:34 | determine which trigger gnomic function I was going to use | |
03:38 | . So we're pretty much all set now to solve | |
03:40 | some true economic problems . So let's do that . | |
03:43 | So for our first example here we have a right | |
03:45 | angle triangle . Okay it has an angle of 35°. | |
03:49 | . It has one side length of 12 m and | |
03:52 | another unknown side length which we're gonna be trying to | |
03:55 | work out . So the very first step to work | |
03:57 | out this unknown side leaf is we are going to | |
03:59 | do what we do with any true economic equation or | |
04:02 | any true economic problem . We are going to label | |
04:04 | the unknown sides . So first off we have this | |
04:07 | long side here which is the high pot news . | |
04:11 | Then we have this side which is opposite . This | |
04:13 | angle , opposite is 35 here . This is the | |
04:16 | opposite . So which of our true economic functions deals | |
04:19 | with the opposite and the high pot news . And | |
04:21 | you're gonna say that it's sign here sign is equal | |
04:24 | to opposite overhyped news . Some old hags . So | |
04:27 | I'm gonna write this down sign feta is equal to | |
04:31 | the opposite over there . Hi pot news . And | |
04:35 | now what we do is we just go through and | |
04:37 | substitute in our values has signed feeder . This is | |
04:40 | signed 35° is equal to the opposite . The opposite | |
04:46 | is what we're trying to work out here . X | |
04:48 | . So I put that in his ex Over the | |
04:50 | high pot news which is 12 . So we can | |
04:55 | now work this out a little bit further . We | |
04:57 | could actually say , Okay , uh signed 35 . | |
05:00 | We put that into a calculator . We're going to | |
05:02 | get the answer is 0.57 which is equal to X | |
05:07 | over 12 . What can we do now ? So | |
05:11 | what we have to do is we have to get | |
05:12 | X by itself . Okay , So X is going | |
05:16 | to be equal to what there's a little trick I | |
05:18 | use here . This may or may not help . | |
05:20 | You may or may not like it . Okay . | |
05:22 | I'm sure I'm gonna get plenty of hate for this | |
05:24 | . But what I do is this when I'm not | |
05:26 | certain what to do here and I'm trying to solve | |
05:28 | this particular problem here , I just write up an | |
05:30 | equation next to it . A friendly equation as it | |
05:33 | were the equation I'm going to write as this one | |
05:35 | , three equal 6/2 . And we're trying to deal | |
05:39 | with this particular value here , The value up here | |
05:43 | . So what would you do with three and two | |
05:45 | to get six ? We would multiply them . So | |
05:47 | we're going to multiply These two numbers 12 Times 0.57 | |
05:53 | , so 12 times 0.57 . And we'll get our | |
05:57 | answer . So if you do that , what answer | |
05:59 | do you get you get our answer of 6.88 m | |
06:04 | . Okay , so this side link , this opposite | |
06:07 | is 6.88 m and that's how easy trigonometry is to | |
06:10 | use . Okay , so we're gonna go through another | |
06:13 | example and then I'm going to go through an example | |
06:15 | where I look at how to work out the angle | |
06:17 | from 29 side things . So it's a bit of | |
06:20 | a tweak here , so stay tuned for that one | |
06:22 | as well . Okay , but let's just go through | |
06:24 | another one of these time examples . Okay , for | |
06:26 | our second example , let's have a look . We | |
06:28 | have a right angle triangle . We have an angle | |
06:30 | of 48°. . We know that this side length here | |
06:33 | is 15 and we're trying to work out this unknown | |
06:36 | side length here . So let's label our sides first | |
06:40 | . We have this particular site here which is opposite | |
06:44 | the angle here . So that's the opposite . We | |
06:46 | know that this one here is the high pollen . | |
06:48 | Is that's the easy one spot . So it leaves | |
06:50 | this one here being the adjacent . Okay , and | |
06:54 | it makes sense . It's the shorter one that's running | |
06:56 | next to the angle here . So which one of | |
06:58 | these functions uses opposite and adjacent you're going to see | |
07:01 | here is tan ted feta equals opposite over adjacent . | |
07:08 | So let's sub in our values now . So tan | |
07:10 | feeder becomes tan 48 degrees , Which is equal to | |
07:15 | the opposite , which is 50 m Over Aaron . | |
07:20 | No one x . Okay , we can put 1048 | |
07:25 | into the calculator . If you do this , you're | |
07:27 | gonna get this answer of 1.11 . Okay . The | |
07:30 | opposite and adjacent have that particular ratio of 1.11 for | |
07:34 | an angle of 48° which is equal to 15 over | |
07:37 | X . So now to solve for X and if | |
07:40 | you're not certain what to do you might know this | |
07:42 | straight away but you could do this once again you | |
07:44 | can go OK three equals six divided by two . | |
07:48 | And we're trying to work out the value on the | |
07:50 | bottom here . The two . So that would be | |
07:51 | six divided by three . This number divided by this | |
07:54 | number , this number divided by this number X . | |
07:58 | Xia is going to be equal to this number divided | |
08:01 | by this number 15 divided by 1.11 . Which is | |
08:06 | equal to how much 13.51 matters . Okay , so | |
08:13 | that's how that particular type of our function in trigonometry | |
08:17 | works . It's pretty simple right now , we're gonna | |
08:19 | go through some examples . We're going to look at | |
08:21 | how to work out the angle from snow inside links | |
08:24 | . It's fairly simple . There's just a couple of | |
08:26 | tweaks with this . So in this example here we | |
08:29 | have a right angle triangle and we know to side | |
08:31 | links . We know that this side length here is | |
08:33 | 100 and five m and we know that this side | |
08:35 | length here is 33 m . What we're trying to | |
08:38 | find out is we're trying to find out this unknown | |
08:40 | angle that would accommodate these side links . So how | |
08:43 | do we do that ? Well , it's just one | |
08:44 | little variant and I'll get to that as we are | |
08:46 | do this particular problem . The very start though is | |
08:49 | exactly the same . We are just going to go | |
08:51 | through a label whether our sides are opposite . High | |
08:54 | pot news are adjacent . So we know this long | |
08:57 | side here is going to be the high pot news | |
09:00 | . We know that this side opposite angle feature here | |
09:04 | is the opposite . So which one are the functions | |
09:07 | that we're dealing with ? This is our second thing | |
09:09 | we can deal with which function and we're going to | |
09:11 | do dealing with sign here . Sign feta is going | |
09:16 | to equal the opposite over the high pot news . | |
09:20 | So what is the opposite over the high point news | |
09:24 | ? We're going to see here that we have The | |
09:27 | opposite , which is 33 m over 105 m . | |
09:33 | Okay , so signed feeder is equal to 33 over | |
09:37 | 105 . It would have worked this out . What's | |
09:39 | 33 divided by 105 . You're gonna see that sign | |
09:43 | feeder is equal to 0.314 . Okay , that's just | |
09:49 | a matter of going . 33 divided by 105 . | |
09:52 | And we get this answer here . So what we | |
09:54 | do now is just a little variant Because we have | |
09:58 | to actually go back . We've got the ratio . | |
09:59 | We're trying to go back to the angle . You're | |
10:01 | going to notice some calculators . That is either a | |
10:04 | second function or something like that . That allows you | |
10:07 | to go from sign to this particular thing , sign | |
10:11 | -1 . OK . We want to be using that | |
10:14 | here . We're going to be hitting 30.314 and we're | |
10:17 | gonna hit sign negative one or second function side . | |
10:21 | Here we do that . We're going to get the | |
10:24 | answer of feta being equal to 18.3°. . Okay , | |
10:31 | So just make sure you know how to do that | |
10:33 | on your calculator . Okay , uh anyway , we'll | |
10:36 | go through one more of these examples . Okay , | |
10:39 | for this example here we have a right angle triangle | |
10:42 | . We have to sidelines . We know we know | |
10:44 | that this one here is 17 . You know this | |
10:46 | one here is 12 and we're trying to work out | |
10:48 | the angle that accommodates these . So let's go through | |
10:51 | and do this . The very first thing we do | |
10:53 | is we're going to label our sides . We have | |
10:55 | the hypotheses which you can see , we're not gonna | |
10:58 | be dealing with the opposite . Were in fact dealing | |
11:00 | with the adjacent . So which one of these functions | |
11:03 | are we dealing with ? And you're going to see | |
11:05 | here the adjacent to the high pot news is the | |
11:08 | co signed function . So , cause feeder is equal | |
11:13 | to the adjacent over the high pot news . Okay | |
11:18 | , So what is that going to be ? Cause | |
11:20 | feeder which is what we're trying to find out is | |
11:23 | equal to the adjacent which is 12 over The High | |
11:28 | Point News which is 17 . So we work out | |
11:30 | what's well divided by 17 means we get the answer | |
11:34 | of 0.71 Okay . Cause fever is equal to 0.71 | |
11:41 | So we're going to be not working out cause we're | |
11:43 | gonna be working at the inverse of cause caused the | |
11:46 | negative one . So you're gonna get second function Cause | |
11:49 | and you're going to get when you do that . | |
11:51 | You're going to get the answer for Feta Feta or | |
11:53 | an angle here is equal to 45.1°. . So that's | |
11:59 | how you go doing trigonometry . And its most basic | |
12:02 | it's pretty simple right ? It's just those tweets there | |
12:05 | and it's also getting to know the calculator that you | |
12:07 | are using . So anyway , hopefully that video is | |
12:09 | of some help to you . If you've got any | |
12:11 | problems , please let me know and I'll make some | |
12:13 | more videos on trigonometry . I'm sure I'm going to | |
12:17 | have some issues where people are gonna get stuck with | |
12:19 | these . Please . If you like the video , | |
12:21 | remember like and subscribe . Hey and below the video | |
12:24 | in the description there there is the patron feed . | |
12:28 | Their you can always subscribe , but you can also | |
12:30 | actually donate to the tech mouth channel on a video | |
12:32 | by video basis so we can keep plugging these videos | |
12:35 | and making more and more and more and more of | |
12:37 | them . Anyway , thanks for watching . We'll see | |
12:39 | you next time . Bye . |
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