Solving Systems of Equations by Substitution | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Solving Systems of Equations by Substitution | MathHelp.com - Free Educational videos for Students in k-12


Solving Systems of Equations by Substitution | MathHelp.com - By MathHelp.com



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00:0-1 to solve this system of equations by substitution . The
00:05 idea is simple since our first equation tells us that
00:11 Y equals three X plus two , we can substitute
00:17 a three X plus two in for the Y .
00:20 In our second equation . In other words , since
00:24 why means the same thing as three X plus two
00:32 . We can replace the Y . In the second
00:34 equation with a three X plus two . Our second
00:41 equation then becomes seven X minus four times parentheses .
00:49 Three X plus two equals seven . Now we can
00:55 solve for X . If we simplify on the left
00:59 side , we get seven X minus 12 , X
01:04 minus eight equals seven , Which simplifies to negative five
01:09 , X -8 equals seven At 8 to both sides
01:16 , and negative five X equals 15 , divide both
01:21 sides by negative five and X equals negative three .
01:28 To find why Plug a negative three back in for
01:33 X . In the first equation to get y equals
01:40 three times negative three plus two , which simplifies to
01:47 Y equals negative nine plus two , Or y equals
01:52 -7 . So the solution to this system of equations
01:57 is -3 -7 .
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