Graphing Linear Inequalities | MathHelp.com - By MathHelp.com
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| 00:0-1 | to graph the inequality Why is greater than -4 X | |
| 00:05 | -3 . We start by graphing what is called the | |
| 00:09 | boundary line and in this case that's why equals negative | |
| 00:15 | four x minus three . So setting up our chart | |
| 00:26 | , we have our exes are wise and -4 X | |
| 00:31 | -3 , Plugging our values of 10 and -1 in | |
| 00:40 | for X . We find that y equals negative four | |
| 00:45 | times 1 -3 or negative seven . -4 times 0 | |
| 00:54 | -3 or -3 . -4 times negative one minus three | |
| 01:01 | or positive one . So plotting these points on a | |
| 01:09 | coordinate system , We have 1 -7 . Mhm zero | |
| 01:21 | negative three And -1 1 before graphing a line through | |
| 01:34 | these points . However , let's take a look back | |
| 01:37 | at the original inequality . Notice that why is greater | |
| 01:43 | than -4 X -3 . It is not equal to | |
| 01:48 | -4 X -3 . So the line y equals negative | |
| 01:54 | four , X -3 is not a part of the | |
| 01:58 | solution set . However , it does form a boundary | |
| 02:03 | on the graph . So to represent this idea , | |
| 02:06 | we draw a dotted line through our points . The | |
| 02:16 | solutions to this inequality will all lie on either one | |
| 02:21 | side or the other of this boundary line . So | |
| 02:25 | to determine where the solutions lie , we choose a | |
| 02:29 | test point to plug back into the original inequality from | |
| 02:33 | either side of the boundary line . Usually the easiest | |
| 02:39 | point to try is the origin 00 So plugging , | |
| 02:46 | 00 back into the original inequality we have zero . | |
| 02:56 | Yes is greater than negative four times zero minus three | |
| 03:06 | or zero is greater than negative three , Since zero | |
| 03:13 | is greater than -3 is a true statement . That | |
| 03:18 | means the zero is part of the solution set . | |
| 03:26 | And in fact all points on this side of the | |
| 03:30 | boundary line will also be part of the solution set | |
| 03:35 | . So to represent this idea , we shade toward | |
| 03:40 | the point 00 Oh and we have our grass |
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