Solving Equations with Fractions | MathHelp.com - By MathHelp.com
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00:0-1 | In this equation we have two fractions to deal with | |
00:04 | , But notice that both fractions have a denominator of | |
00:08 | two . What that means is we can get rid | |
00:12 | of both fractions at once by multiplying both sides of | |
00:16 | the equation by two . Mhm . Make sure you | |
00:28 | distribute the two through both terms on both sides of | |
00:34 | the equation . Yeah , on the left two times | |
00:41 | five halves B is five B and two times negative | |
00:46 | . Two is negative four on the right , two | |
00:52 | times B is to be and two times negative one | |
00:57 | half is negative one . Now we can move our | |
01:02 | bees to the left side of the equation and numbers | |
01:05 | to the right . And we start by subtracting to | |
01:09 | be from both sides . That gives us three B | |
01:18 | -4 Equals -1 . Now we can move our numbers | |
01:25 | to the right by adding four to both sides And | |
01:32 | we get three B equals three , Divide both sides | |
01:38 | by three oh and be equals one . |
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