Similar Triangles | MathHelp.com - By MathHelp.com
Transcript
| 00:0-1 | in this example we're given that the triangle shown are | |
| 00:03 | similar and we're asked to find the value of X | |
| 00:07 | . Remember that if two triangles are similar , the | |
| 00:10 | ratios of their corresponding sides are equal . Notice that | |
| 00:15 | the corresponding sides for the triangle shown have length five | |
| 00:19 | and 20 12 and X and 13 and 52 . | |
| 00:25 | So the ratios 5/20 12 over X . Yeah . | |
| 00:37 | And 13/52 . Mhm . Must all be equal . | |
| 00:45 | Mhm . Now to find the value of X , | |
| 00:49 | let's use the proportion formed by the first two ratios | |
| 00:54 | . 5/20 equals 12 over x . To solve a | |
| 00:58 | proportion , we use cross products five times X Equals | |
| 01:05 | 20 times 12 Or five x equals 240 . Finally | |
| 01:13 | , we divide both sides of the equation by five | |
| 01:18 | To get x equals 48 . It's important to understand | |
| 01:27 | that if we used the proportion 12 over X equals | |
| 01:30 | 13/52 we would get the same answer . X equals | |
| 01:35 | 48 . |
Summarizer
DESCRIPTION:
OVERVIEW:
Similar Triangles | MathHelp.com is a free educational video by MathHelp.com.
This page not only allows students and teachers view Similar Triangles | MathHelp.com videos but also find engaging Sample Questions, Apps, Pins, Worksheets, Books related to the following topics.
GRADES:
STANDARDS:
