Algebra Classes | MathHelp.com - By MathHelp.com
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| 00:0-1 | To solve this radical equation , Our first task is | |
| 00:04 | to get the square root by itself on the left | |
| 00:08 | side . To do that , we add five to | |
| 00:13 | both sides of the equation To get the squared of | |
| 00:17 | x equals nine . Now we can get rid of | |
| 00:23 | the square root by simply squaring both sides of the | |
| 00:28 | equation and make sure you write out this step with | |
| 00:33 | the parentheses squared on each side , and we have | |
| 00:38 | X equals nine squared , which is nine times 9 | |
| 00:43 | or 81 . Finally check your answer back in the | |
| 00:49 | original equation to make sure that it works . Mhm | |
| 00:53 | . If we plug in 81 back in for X | |
| 00:56 | , we have the square root of 81 , which | |
| 00:59 | is 9 -5 -5 equals four , so our answer | |
| 01:05 | checks . |
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