Triangle Angle Bisector Theorem | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Triangle Angle Bisector Theorem | MathHelp.com - Free Educational videos for Students in k-12


Triangle Angle Bisector Theorem | MathHelp.com - By MathHelp.com



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00:0-1 here were asked to use the diagram shown to find
00:04 the value of X . Notice that we have a
00:08 ray that bisects and angle of the large triangle ,
00:12 so according to the triangle angle by sector theorem ,
00:16 the ray divides the opposite side of the triangle into
00:21 segments that are proportional to the other two sides .
00:26 So we can set up the proportion X is 2
00:30 30 -1 as 21 is to 24 . So we
00:36 right X over 30 -1 equals 21/24 . And solving
00:47 from here we have x times 24 or 24 x
00:54 equals 30 minus X times 21 or 21 parentheses ,
01:01 30 minus X . Our next step is to distribute
01:06 on the right side and we have 24 x equals
01:12 630 -21 x . And adding 21 x to both
01:19 sides . Mhm . Yeah , gives us 45 x
01:27 equals 630 And dividing both sides by 45 . Yes
01:36 . Yeah . We find that x equals 14 .
01:42 Yeah .
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