Graphing Lines Using an X/Y Chart | MathHelp.com - By MathHelp.com
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| 00:0-1 | here , were asked to graph the equation Y equals | |
| 00:03 | two X plus three . Given a domain of all | |
| 00:08 | real numbers . In this situation , I would first | |
| 00:13 | set up a chart that we can use to organize | |
| 00:18 | our information down the left side of the chart . | |
| 00:23 | We have our different values for X . That will | |
| 00:28 | be plugging into the equation down the right side of | |
| 00:32 | the chart . We have our different values for why | |
| 00:37 | that we end up with . And in the middle | |
| 00:40 | we have the side of the equation that contains the | |
| 00:43 | X . In this case two X plus three . | |
| 00:50 | Since our domain is all real numbers , we can | |
| 00:53 | choose any values . We want to to plug into | |
| 00:57 | the equation for X . So let's go with the | |
| 01:00 | values 10 and negative one just to keep things simple | |
| 01:10 | . So plugging a one into the equation for X | |
| 01:14 | . We have two times one plus three or two | |
| 01:20 | plus three , which is five , plugging a zero | |
| 01:27 | into the equation for X we have two times 0 | |
| 01:31 | plus three which is zero plus three or three plugging | |
| 01:38 | a negative one into the equation for X we have | |
| 01:40 | two times negative one plus three which is negative two | |
| 01:45 | plus three or one . I would always choose at | |
| 01:52 | least three values to plug into the equation for X | |
| 01:58 | . Notice that we now have three points that we | |
| 02:01 | can use to graph this equation . Our points are | |
| 02:06 | 1,5 , 03 And -1 1 . So setting up | |
| 02:16 | our coordinate system . Mhm . We have 15 Mhm | |
| 02:24 | . Yeah . Yeah 03 And -1 . 1 notice | |
| 02:38 | the pattern that is formed by these three points . | |
| 02:43 | They all lie along the same line . In fact | |
| 02:49 | if we had chosen any other value to plug into | |
| 02:52 | the equation for X besides 10 or negative one , | |
| 02:58 | we would have ended up with a different point . | |
| 03:01 | But that point would also lie along this line . | |
| 03:06 | So the graph of this equation is the line That | |
| 03:11 | contains these three points . |
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