Solving Algebra Problems | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Solving Algebra Problems | MathHelp.com - Free Educational videos for Students in k-12


Solving Algebra Problems | MathHelp.com - By MathHelp.com



Transcript
00:0-1 to solve this system of equations by substitution . The
00:05 idea is simple since our first equation tells us that
00:10 Y equals three X plus two . This means that
00:15 we can substitute a three X plus two In for
00:19 the why ? In our 2nd equation ? In other
00:23 words , since why means the same thing as three
00:28 X plus two . We can replace the Y in
00:32 the second equation With a three x plus two .
00:37 And rewriting our second equation . We now have seven
00:43 x -4 times parentheses . three x plus two equals
00:51 seven . Now we can solve for X By 1st
00:56 distributing the -4 through the parentheses . To get seven
01:02 x minus 12 , X -8 equals seven . And
01:10 simplifying further , we have negative five X minus eight
01:16 equals seven , Adding 8 to both sides , gives
01:23 us -5 , x equals 15 And dividing both sides
01:31 by -5 . Mhm . We find that x equals
01:37 -3 . Mhm . To solve for why we plug
01:44 a negative three back in for the X . In
01:48 our first equation , and we have Y equals three
01:55 times negative three plus two , which simplifies to Y
02:02 equals negative nine plus two , Or y equals -7
02:11 . What since X equals negative three ? And why
02:17 equals -7 ? Our solution is the ordered pair -3
02:25 -7 .
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