Properties of a Rhombus | MathHelp.com - By MathHelp.com
Transcript
00:0-1 | In this example we're given the quadrilateral A . B | |
00:04 | C . D . Is a rhombus and we're asked | |
00:07 | to find the values of X . Y . And | |
00:10 | Z . Since the diagonals of a rhombus bisect the | |
00:15 | angles diagonal D . B must bisect angle A . | |
00:21 | D . C . So angle A D . B | |
00:25 | must be congruent to angle B . D . C | |
00:29 | . Which means that X must equal 35 . Yeah | |
00:36 | . Mhm . Next , Since the diagonals of a | |
00:43 | rhombus are perpendicular , Why must equal 90 ? Yeah | |
00:56 | . And finally to find the value of Z , | |
00:59 | let's use triangle D . E . C . Since | |
01:04 | angle D . E . C . In the 90 | |
01:07 | degree angle are vertical angles . The measure of angle | |
01:11 | D . E . C . Must also be 90 | |
01:17 | . And since we already know that x equals 35 | |
01:23 | And the sum of the measures of the angles of | |
01:26 | a triangle is 180°. . We can set up the | |
01:30 | equation 35 Plus 90 plus z equals 180 . And | |
01:41 | simplifying on the left side , we have 125 plus | |
01:47 | Z Equals 180 And subtracting 125 from both sides . | |
01:56 | Yeah , yeah . We find that z equals 55 | |
02:05 | . Yeah . Yeah . |
Summarizer
DESCRIPTION:
This lesson covers evaluating expressions. Students learn to evaluate expressions by substituting the given integers in for the variables in the given expression, then simplifying. Students also learn to use parentheses when substituting.
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