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This page provides a list of educational videos related to Solving Polynomial Equations. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Solving Polynomial Equations.
Solving Polynomial Equations
By refrigeratormathprof
The LA Valley College Mathematics Department presents Solving Polynomial Equations, an educational video resource on math.
Solving rational equations 2 | Polynomial and rational functions | Algebra II | Khan Academy
By Khan Academy
The instructor in this video (04:08) discusses how to solve rational equations using another problem. Sl Khan shows how to multiply to remove the fractions to make solving easier. He uses computer software for demonstration. The viewer may want to open the video to 'full screen' because the instructor has a lot of small writing on a black screen.
What Does the Fundamental Theorem of Algebra Tell Us about a Function?
By AutenA2Math
This video explains the Fundamental Theorem of Algebra and how it can assist us when solving a polynomial equation. (For those not familiar with the technique, this video demonstrates the use of "synthetic division.") Remember that the Fundamental Theorem of Algebra only applies when working in the Complex Number set. A polynomial like x^2 + 1 has no real roots, but it does have two complex roots.
ALL OF GRADE 9 MATH IN 60 MINUTES!!! (exam review part 1)
By Lumos Learning
Here is a great exam review video reviewing all of the main concepts you would have learned in the MPM1D grade 9 academic math course. The video is divided in to 3 parts. This is part 1: Algebra. The main topics in this section are exponent laws, polynomials, distributive property, and solving first degree equations. Please watch part 2 and 3 for a review of linear relations and geometry. If you watch all 3 parts, you will have reviewed all of grade 9 math in 60 minutes. Enjoy! Visit jensenmath.ca for more videos and course materials.
Polynomials: Adding and Subtracting
By PatrickJMT
In this video, the instructor defines polynomials, then gives some examples of how to add and subtract polynomials. He works through the steps of example problems to explain how to work add and subject polynomials. His explanations are clear and thorough and it would be easy to follow along as he explains.
Example 4: Adding and subtracting polynomials | Algebra I | Khan Academy
By Khan Academy
This video is from Khan Academy. It demonstrates the proper method of adding and subtracting polynomials
Adding and subtracting polynomials | Algebra Basics | Khan Academy
By Khan Academy
This video from Khan Academy features an example problem on simplifying an algebraic expression by subtracting two polynomials.
Adding and Subtracting Polynomials (Simplifying Math)
By Eric Buffington
A short lesson on adding and subtracting Polynomials. This video emphasizes the importance of adding and subtracting like terms.
12 - The Factor Theorem, Part 1 (Factoring Polynomials in Algebra)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
01 - Solving Equations in Quadratic Form - Part 1 (Learn to Solve Equations in Algebra)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
Add and subtract polynomials with one variable
By Khan Academy
Sal simplifies (x^3 + 3x - 6) + (-2x^2 + x - 2) - (3x - 4).
Add and subtract polynomials with one variable
By Khan Academy
Sal analyzes a polynomial subtraction process to find the step that has an error.
Add and subtract polynomials with one variable
By Khan Academy
Sal simplifies (16x+14) - (3x^2 + x - 9).
Add and subtract polynomials with one variable
By Khan Academy
Sal simplifies (5x^2 + 8x - 3) + (2x^2 - 7x + 13x).
06 - Solve Quadratic Systems of Equations by Substitution - Part 1 (Simultaneous Equations)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
18 - Descartes Rule of Signs, Part 1 (Find Roots of Polynomials)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
Work Word Problems | MathHelp.com
By MathHelp.com
To solve a polynomial inequality, like the one shown here, our first step is to write the corresponding equation. In other words, we simply change the inequality sign to an equals sign, and we have x^2 – 3 = 9 – x. Next, we solve the equation. Since we have a squared term, we first set the equation equal to 0. So we move the 9 – x to the left side by subtracting 9 and adding x to both sides of the equation. This gives us x^2 + x – 12 = 0. Next, we factor the left side as the product of two binomials. Since the factors of negative 12 that add to positive 1 are positive 4 and negative 3, we have x + 4 times x – 3 = 0. So either x + 4 = 0 or x – 3 = 0, and solving each equation from here, we have x = -4, and x = 3. Now, it’s important to understand that the solutions to the equation, -4 and 3, represent what are called the “critical values” of the inequality, and we plot these critical values on a number line. However, notice that our original inequality uses a greater than sign, rather than greater than or equal to sign, so we use open dots on our critical values of -4 and positive 3. Remember that ‘greater than’ or ‘less than’ means open dot, and ‘greater than or equal to’ or ‘less than or equal to’ means closed dot. Now, we can see that our critical values have divided the number line into three separate intervals: less than -4, between -4 and 3, and greater than 3. And here’s the important part. Our next step is to test a value from each of the intervals by plugging the value back into the original inequality to see if it gives us a true statement. So let’s first test a value from the “less than -4” interval, such as -5. If we plug a -5 back in for both x’s in the original inequality, we have -5 squared – 3 greater than 9 minus a -5, which simplifies to 25 – 3 greater than 9 + 5, or 22 greater than 14. Since 22 greater than 14 is a true statement, this means that all values in the interval we’re testing are solutions to inequality, so we shade the interval. Next, we test a value from the “between -4 and 3” interval, such as 0. If we plug a 0 back in for both x’s in the original inequality, we have 0 squared – 3 greater than 9 – 0, which simplifies to 0 – 3 greater than 9, or -3 greater than 9. Since -3 greater than 9 is a false statement, this means that all values in the interval we’re testing are not solutions to inequality, so we don’t shade the interval. Next, we test a value from the “greater than 3” interval, such as 4. If we plug a 4 back in for both x’s in the original inequality, we have 4 squared – 3 greater than 9 – 4, which simplifies to 16 – 3 greater than 5, or 13 greater than 5. Since 13 greater than 5 is a true statement, this means that all values in the interval we’re testing are solutions to inequality, so we shade the interval. Finally, we write the answer that’s shown on our graph in set notation. The set of all x’s such that x is less than -4 or x is greater than 3.
