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Division of Polynomials made Easy! 1 of 2

Algebra Math Trick - Division

12 - The Factor Theorem, Part 1 (Factoring Polynomials in Algebra)

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Quality Math And Science Videos that feature step-by-step example problems!

Long Division of Polynomials

Algebra Basics: Exponents In Algebra - Math Antics

Example 4: Adding and subtracting polynomials | Algebra I | Khan Academy

By Khan Academy

This video is from Khan Academy. It demonstrates the proper method of adding and subtracting polynomials

Algebra trick for multiplying polynomials

18 - Descartes Rule of Signs, Part 1 (Find Roots of Polynomials)

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Quality Math And Science Videos that feature step-by-step example problems!

16 - Conjugate Root Theorem, Part 1 (Roots of Polynomials, Solving Polynomials & Conjugate Roots)

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Quality Math And Science Videos that feature step-by-step example problems!

Synthetic Division | MathHelp.com

08 - Learn Synthetic Division of Polynomials - Part 1

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Quality Math And Science Videos that feature step-by-step example problems!

ALL OF GRADE 9 MATH IN 60 MINUTES!!! (exam review part 1)

Here is a great exam review video reviewing all of the main concepts you would have learned in the MPM1D grade 9 academic math course. The video is divided in to 3 parts. This is part 1: Algebra. The main topics in this section are exponent laws, polynomials, distributive property, and solving first degree equations. Please watch part 2 and 3 for a review of linear relations and geometry. If you watch all 3 parts, you will have reviewed all of grade 9 math in 60 minutes. Enjoy! Visit jensenmath.ca for more videos and course materials.

Evaluating Logarithms | MathHelp.com

By MathHelp.com

In this example, notice that we have a polynomial divided by a binomial, and our binomial is in the form of an x term minus a constant term, or x – c. In this situation, instead of having to use long division, like we did in the previous lesson, we can divide the polynomials using synthetic division, which is a much more efficient method. Here’s how it works. We start by finding the value of c. Since –c = -3, we know that c = 3. Next, we put the value of c inside a box, so we put the 3 inside a box. It’s very important to understand that the number that goes inside the box always uses the opposite sign as the constant term in the binomial. In other words, since the constant term in the binomial is -3, the number that goes inside the box, is positive 3. Next, we write the coefficients of the dividend, which are 2, -7, 4, and 5. Be very careful with your signs. Now, we’re ready to start our synthetic division. First, we bring down the 2. Next, we multiply the 3 in the box times 2 to get 6, and we put the 6 under the -7. Next, we add -7 + 6 to get -1. Next, we multiply the 3 in the box times -1 to get -3, and we put the -3 under the 4. Next, we add 4 + -3 to get 1. Next, we multiply the 3 in the box times 1 to get 3, and we put the 3 under the 5. Finally, we add 5 + 3 to get 8. Now, notice that we have a 2, -1, 1, and 8 in the bottom row of our synthetic division. These values will give us our answer: the first 3 numbers represent the coefficients of the quotient, and the last number is the remainder. And it’s important to understand that our answer will be one degree less than the dividend. In other words, since our dividend starts with x cubed, and we’re dividing by x, our answer will start with x squared. So our answer is 2x squared – 1x + 1 + 8 over x – 3. Notice that we always use descending order of powers in our quotient. In this case x squared, x, and the constant. Finally, remember that we add the remainder over the divisor, just like we did in the previous lesson on long division, and we have our answer. It’s important to understand that we’ll get the same answer whether we use synthetic division or long division. However, synthetic division is much faster.