Divisibility and Factors Videos - Free Educational Videos for Students in K - 12

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This page provides a list of educational videos related to Divisibility and Factors. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Divisibility and Factors.


Understand Division as an Unknown Factor Problem


By Hoodamath tutorials

division problems with unknown factors

Understand Division as Unknown Factor Problems


By EducateNF

division problems with unknown factors

Division Of Algebraic Expressions / Factorization / Maths Algebra


By We Teach Academy Maths

Chapter : Factorization Lesson : Division Of Algebraic Expressions

3.OA.6 - Meaning of Division (Singapore Math)


By MathwithMrAlmeda

Mr. Almeida explains the meaning of division as an "unknown factor problem." This illustrates 3.OA.6 in the grade 3 Common Core Standards for Mathematics.

Finding Factors of a Number


By Khan Academy

To find the factors of a number means to find all the whole numbers that the number in question is divisible by. Can you help us find the factors in this example?

Identifying factors and multiples


By Khan Academy

To find the factors of a number means to find all the whole numbers that the number in question is divisible by. Can you help us find the factors in this example?

Finding factors of a number | Factors and multiples | Pre-Algebra | Khan Academy


By Khan Academy

To find the factors of a number means to find all the whole numbers that the number in question is divisible by. Can you help us find the factors in this example?

Factor pairs


By Khan Academy

To find the factors of a number means to find all the whole numbers that the number in question is divisible by. Can you help us find the factors in this example?

Finding Factors of a Number


By Khan,Academy

To find the factors of a number means to find all the whole numbers that the number in question is divisible by. Can you help us find the factors in this example?

Basic Math: Lesson 5 - Factors, Multiples & Divisibility


By

This lesson consists of giving you the necessary

Meaning of Division


By MathwithMrAlmeida

In this video, Mr. Almeida explains the meaning of division as an "unknown factor problem." This illustrates 3.OA.6 in the grade 3 Common Core Standards for Mathematics.

Finding all the Zeros of a Polynomial - Example 2 - YouTube


By PatrickJMT

Finding all the Zeros of a Polynomial - Example 2. In this video, I use the rational roots test to find all possible rational roots; after finding one I use long division to factor, and then repeat! Very fun!

Algebra 2: Remainder and Factor Theorems


By Educator

This video shows the remainder theorem and how to use synthetic division.

12 - The Factor Theorem, Part 1 (Factoring Polynomials in Algebra)


By Math and Science

Quality Math And Science Videos that feature step-by-step example problems!

Complex Numbers - Multiplying and Dividing


By PatrickJMT

This video lesson contains a few example problems on multiplying and dividing complex numbers. For multiplication, the FOIL method is discussed, and for division, the idea of complex conjugates is discussed.

Synthetic Division | MathHelp.com


By MathHelp.com

In this example, it’s tempting to divide x squared + 5x – 6 by x + 1 by first factoring x squared + 5x – 6. The factors of -6 that add to positive 5 are +6 and -1, so we have x + 6 times x – 1 over x + 1. Notice, however, that nothing cancels. In this situation, we need a different method of dividing the polynomials, so we use long division. In other words, we rewrite x squared + 5x – 6 divided by x + 1 as x + 1 divided into x squared + 5x – 6. Now, our first step in the long division is to determine how many times x goes into x squared. Since x goes into x squared x times, we write an x above the x squared, just like we do with regular long division. Next, we multiply the x times the x + 1 in the divisor to get x squared + x, and we write the x squared + x underneath the x squared + 5x. Next, we subtract x squared + x from x squared + 5x. And watch out for this step: it’s an area where most of the common mistakes in these types of problems are made. Instead of subtracting, I would change the sign of each term in x squared + x, so we have negative x squared + negative x, then add the columns. So we have x squared + negative x squared, which cancels out, and positive 5x + negative x, which is positive 4x. Next, we bring down the -6, in regular long division. Now, we need to determine how many times x goes into 4x. Since x goes into 4x 4 times, we write a positive 4 in our answer. Next, we multiply positive 4 times x + 1 to get 4x + 4, and we write the 4x + 4 underneath the 4x – 6. Next, we subtract 4x + 4 from 4x – 6. In other words, we change the signs on 4x + 4 to -4x + -4, and we add. 4x + -4x cancels out, and -6 + -4 is -10. And since there are no other numbers to bring down, we have a remainder of -10. Finally, remember from the previous example that we add the remainder over the divisor to the quotient. In other words, we add -10 over x + 1 to x + 4, and we have x + 4 + -10 over x + 1. So x squared + 5x – 6 divided by x + 1 simplifies to x + 4 + -10 over x + 1.