# Dividing complex numbers

Sal divides (6+3i) by (7-5i).

# Divide polynomials by monomials with remainders

Sal divides (7x^6+x^3+2x+1) by X^2, and writes the solution as q(x)+r(x)/x^2, where the degree of the remainder, r(x), is less than the degree of x^2.

# [5.NF.7c-1.1] Word Problems: Division

## By Front Row

0:26 video shows how to divide 1/2 kg of rice among 6 people. Not much explanation but does show how to set up the problem.

# Customary Unit Conversions | MathHelp.com

## By MathHelp.com

This lesson covers complex numbers. Students learn that a complex number is the sum or difference of a real number and an imaginary number and can be written in a + bi form. For example, 1 + 2i and -- 5 - i root 7 are complex numbers. Students then learn to add, subtract, multiply, and divide complex numbers that do not contain radicals, such as (5 + 3i) / (6 - 2i). To divide (5 + 3i) / (6 - 2i), the first step is to multiply both the numerator and denominator of the fraction by the conjugate of the denominator, which is (6 + 2i), then FOIL in both the numerator and denominator, and combine like terms.

# Dividing numbers: long division example | 4th grade | Khan Academy

Have a go at this one on your own before listening to the solution. You're doing great and we believe in you!

# Dividing numbers: intro to long division | 4th grade | Khan Academy

Division isn't magic. It's perfectly logical. In this example we'll do a long division problem together and find the resulting answer (without a remainder).

# Grade 5 Math - Division of Whole Numbers

## By Lumos Learning

Using the Lumos Study Programs, parents and educators can reinforce the classroom learning experience for children and help them succeed at school and on the standardized tests. Lumos books, dvd, eLearning and tutoring are used by leading schools, libraries and thousands of parents to supplement classroom learning and improve student achievement in the standardized tests.

# Synthetic Division | MathHelp.com

## By MathHelp.com

In this example, it’s tempting to divide x squared + 5x – 6 by x + 1 by first factoring x squared + 5x – 6. The factors of -6 that add to positive 5 are +6 and -1, so we have x + 6 times x – 1 over x + 1. Notice, however, that nothing cancels. In this situation, we need a different method of dividing the polynomials, so we use long division. In other words, we rewrite x squared + 5x – 6 divided by x + 1 as x + 1 divided into x squared + 5x – 6. Now, our first step in the long division is to determine how many times x goes into x squared. Since x goes into x squared x times, we write an x above the x squared, just like we do with regular long division. Next, we multiply the x times the x + 1 in the divisor to get x squared + x, and we write the x squared + x underneath the x squared + 5x. Next, we subtract x squared + x from x squared + 5x. And watch out for this step: it’s an area where most of the common mistakes in these types of problems are made. Instead of subtracting, I would change the sign of each term in x squared + x, so we have negative x squared + negative x, then add the columns. So we have x squared + negative x squared, which cancels out, and positive 5x + negative x, which is positive 4x. Next, we bring down the -6, in regular long division. Now, we need to determine how many times x goes into 4x. Since x goes into 4x 4 times, we write a positive 4 in our answer. Next, we multiply positive 4 times x + 1 to get 4x + 4, and we write the 4x + 4 underneath the 4x – 6. Next, we subtract 4x + 4 from 4x – 6. In other words, we change the signs on 4x + 4 to -4x + -4, and we add. 4x + -4x cancels out, and -6 + -4 is -10. And since there are no other numbers to bring down, we have a remainder of -10. Finally, remember from the previous example that we add the remainder over the divisor to the quotient. In other words, we add -10 over x + 1 to x + 4, and we have x + 4 + -10 over x + 1. So x squared + 5x – 6 divided by x + 1 simplifies to x + 4 + -10 over x + 1.

# Dividing numbers: long division with remainders | Arithmetic | Khan Academy

Here we go with more long division practice. Ever wonder why we call it long division? What's long about it, anyway?

# Ms. Chang 4th Grade- Divide with partial quotients

## By Ms Chang

Find whole-number quotients and remainders with up to four-digit dividends and one-digit divisors, using strategies based on place value, the properties of operations, and/or the relationship between multiplication and division

# Division by 2 digits

Here's another practice example where you divide by two digits.

# Division by 2 digits

There's a little bit of an art to dividing numbers by two or more digits. Let us show you...

# Dividing numbers: long division with remainders

Here we go with more long division practice. Ever wonder why we call it "long" division? What's "long" about it anyway?

# Dividing Whole Numbers and Applications 4

This video lecture series on Developmental Math by Khan Academy provides developmental math examples from the Monterey Institute. These start pretty basic and would prepare a student for the Worked Examples in Algebra course lectures.....

# Grade 6 Math - Division of Fractions 2

## By Lumos Learning

Using the Lumos Study Programs, parents and educators can reinforce the classroom learning experience for children and help them succeed at school and on the standardized tests. Lumos books, dvd, eLearning and tutoring are used by leading schools, libraries and thousands of parents to supplement classroom learning and improve student achievement in the standardized tests.

# Dividing numbers: intro to remainders | Multiplication and division | Arithmetic | Khan Academy

Learn how a remainder is what's left over in a division problem.

# Dividing numbers: example with remainders | Multiplication and division | Arithmetic | Khan Academy

Let's work this division problem together. Our division is getting longer as the numbers get bigger, but that won't be a problem for you! Watch for the remainder.

# One-step equations with multiplication and division

This equation can be simplified through a single step to solve for the variable. Can you help?