Lumos Video Store
This page provides a list of educational videos related to Adding and Subtracting Polynomials. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Adding and Subtracting Polynomials.
Adding and Subtracting Polynomials (Simplifying Math)
By Eric Buffington
A short lesson on adding and subtracting Polynomials. This video emphasizes the importance of adding and subtracting like terms.
Example 4: Adding and subtracting polynomials | Algebra I | Khan Academy
By Khan Academy
This video is from Khan Academy. It demonstrates the proper method of adding and subtracting polynomials
Polynomials: Adding and Subtracting
By PatrickJMT
In this video, the instructor defines polynomials, then gives some examples of how to add and subtract polynomials. He works through the steps of example problems to explain how to work add and subject polynomials. His explanations are clear and thorough and it would be easy to follow along as he explains.
Adding and subtracting polynomials | Algebra Basics | Khan Academy
By Khan Academy
This video from Khan Academy features an example problem on simplifying an algebraic expression by subtracting two polynomials.
Monomials and adding or subtracting polynomials
By MathPlanetVideos
Add the two polynomials (x2+3x+8)+(3x2−2x+4)
Adding and Subtracting Polynomials | MathHelp.com
By MathHelp.com
In this example, notice that each of our variables, x, y, and z, appears in all three equations. To solve this system, we use the addition method. In other words, let’s start with our first two equations, x + y + z = 4, and x – y + z = 2. Notice that if we add these equations together, the +y and –y will cancel out, and we have 2x + 2z = 6. So, in our new equation, 2x + 2z = 6, we’ve eliminated the variable y. Unfortunately, we still haven’t solved for any of our variables. However, if we can create another equation with just x and z in it, then we’ll have a system of equations in two variables, which we can use to solve for x and z. To create another equation with just x and z in it, we need to eliminate y. We can’t add the first and second equations together, because we’ve already done that. However, notice that if we add the first and third equations together, the first equation has a +y and the third equation has a –y, so we’ll be able to eliminate the y. So we have our first equation, x + y + z = 4, and our third equation, x – y – z = 0, and adding them together, notice that the +y – y cancels out, and, as a bonus, the +z – z also cancels out, so we have 2x = 4, and dividing both sides by 2, x = 2. Now, since we know that x = 2, notice that if we plug a 2 in for x in the equation that we created earlier, we can solve for z. And we have 2(2) + 2z = 6, or 4 + 2z = 6, and subtracting 4 from both sides, we have 2z = 2, and dividing both sides by 2, z = 1. So x = 2 and z = 1, and to find the value of y, we simply plug our values of x and z into any of the equations in the original system. Let’s use the first equation, x + y + z = 4. Since x = 2 and z = 1, we plug a 2 in for x and a 1 in for z, and we have 2 + y + 1 = 4, or 3 + y = 4, and subtracting 3 from both sides, y = 1. So x = 2, y = 1, and z = 1, and finally, we write our answer as the ordered triple, x, y, z, or (2, 1, 1).
More examples of addition and subtraction of polynomials | Algebra II | Khan Academy
By Khan Academy
This instructor in this video, Sal Khan, discusses adding and subtracting polynomials. In an easy, conversational tone, the instructor explains processes clearly. Mr. Khan uses the Paint Program (with different colors) to illustrate his points. Sal Khan is the recipient of the 2009 Microsoft Tech Award in Education. The student or educator may want to open the video to 'full screen' as the instructor is using a black background and the writing is small.
10 - The Remainder Theorem of Synthetic Division & Polynomial Long Division - Part 1
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
08 - Learn Synthetic Division of Polynomials - Part 1
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
ALL OF GRADE 9 MATH IN 60 MINUTES!!! (exam review part 1)
By Lumos Learning
Here is a great exam review video reviewing all of the main concepts you would have learned in the MPM1D grade 9 academic math course. The video is divided in to 3 parts. This is part 1: Algebra. The main topics in this section are exponent laws, polynomials, distributive property, and solving first degree equations. Please watch part 2 and 3 for a review of linear relations and geometry. If you watch all 3 parts, you will have reviewed all of grade 9 math in 60 minutes. Enjoy! Visit jensenmath.ca for more videos and course materials.
20 - The Rational Root Theorem, Part 1 (Rational Roots of Polynomials)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
05 - Polynomial Long Division - Part 1 (Division of Polynomials Explained)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
Work Word Problems | MathHelp.com
By MathHelp.com
To solve a polynomial inequality, like the one shown here, our first step is to write the corresponding equation. In other words, we simply change the inequality sign to an equals sign, and we have x^2 – 3 = 9 – x. Next, we solve the equation. Since we have a squared term, we first set the equation equal to 0. So we move the 9 – x to the left side by subtracting 9 and adding x to both sides of the equation. This gives us x^2 + x – 12 = 0. Next, we factor the left side as the product of two binomials. Since the factors of negative 12 that add to positive 1 are positive 4 and negative 3, we have x + 4 times x – 3 = 0. So either x + 4 = 0 or x – 3 = 0, and solving each equation from here, we have x = -4, and x = 3. Now, it’s important to understand that the solutions to the equation, -4 and 3, represent what are called the “critical values” of the inequality, and we plot these critical values on a number line. However, notice that our original inequality uses a greater than sign, rather than greater than or equal to sign, so we use open dots on our critical values of -4 and positive 3. Remember that ‘greater than’ or ‘less than’ means open dot, and ‘greater than or equal to’ or ‘less than or equal to’ means closed dot. Now, we can see that our critical values have divided the number line into three separate intervals: less than -4, between -4 and 3, and greater than 3. And here’s the important part. Our next step is to test a value from each of the intervals by plugging the value back into the original inequality to see if it gives us a true statement. So let’s first test a value from the “less than -4” interval, such as -5. If we plug a -5 back in for both x’s in the original inequality, we have -5 squared – 3 greater than 9 minus a -5, which simplifies to 25 – 3 greater than 9 + 5, or 22 greater than 14. Since 22 greater than 14 is a true statement, this means that all values in the interval we’re testing are solutions to inequality, so we shade the interval. Next, we test a value from the “between -4 and 3” interval, such as 0. If we plug a 0 back in for both x’s in the original inequality, we have 0 squared – 3 greater than 9 – 0, which simplifies to 0 – 3 greater than 9, or -3 greater than 9. Since -3 greater than 9 is a false statement, this means that all values in the interval we’re testing are not solutions to inequality, so we don’t shade the interval. Next, we test a value from the “greater than 3” interval, such as 4. If we plug a 4 back in for both x’s in the original inequality, we have 4 squared – 3 greater than 9 – 4, which simplifies to 16 – 3 greater than 5, or 13 greater than 5. Since 13 greater than 5 is a true statement, this means that all values in the interval we’re testing are solutions to inequality, so we shade the interval. Finally, we write the answer that’s shown on our graph in set notation. The set of all x’s such that x is less than -4 or x is greater than 3.
14 - The Discriminant of a Quadratic, Part 1 (Quadratic Formula Problems)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
02 - Solve Perfect Square Quadratic Equations Part 1
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!
04 - Solving Logarithmic Equations - Part 1 - Equations with Log(x)
By Math and Science
Quality Math And Science Videos that feature step-by-step example problems!