Multiplying With Exponents Videos - Free Educational Videos for Students in K - 12

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This page provides a list of educational videos related to Multiplying With Exponents. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Multiplying With Exponents.


Exponents: Multiplying Variables with Rational Exponents – Basic Ex 2


By PatrickJMT

Exponents: Multiplying Variables with Rational Exponents – Basic Ex 2

Exponents: Multiplying Variables with Rational Exponents – Basic Ex 1


By PatrickJMT

Exponents: Multiplying Variables with Rational Exponents – Basic Ex 1

DEPRECATED Simplifying expressions with exponents


By Khan Academy

When multiplying numbers with common base, add exponents

Exponents


By Khan Academy

Taking an exponent is basically the act of repeated multiplication. You know how to multiply, right? If so, understanding exponents is completely within your grasp!

GRE Math Test Prep | MathHelp.com


By MathHelp.com

This lesson covers the product rule. Students learn the product rule, which states that when multiplying two powers that have the same base, add the exponents. For example, x^4 times x^3 = x^7. To multiply 6s^3 times 3s^6, multiply the coefficients and add the exponents, to get 18s^9. If there is no exponent on the variable, it can be given an exponent of 1. For example, x can be thought of as x^1.

Exponent Rules Song – Learn Algebra – Learning Upgrade


By Learning Upgrade

Learn exponent rules through music! Video shows how to multiply and divide numbers with exponents find the number when you have an exponent of an exponent and to find the number when you have a negative exponent. Video is good quality and good for all students as a review or initial learning of the topic.

Powers of fractions


By Khan Academy

Just like whole numbers with exponents, fractions are repeatedly multiplied. If you know how to multiply factions, you're over half way there.

Unit conversion within the metric system


By Khan Academy

This video lecture series on Pre-algebra from Khan Academy includes Order of Operations Adding and Subtracting Negative Numbers Multiplying and Dividing Negative Numbers Adding and Subtracting Fractions Multiplying and Dividing Fractions Exponents Exponent Rules Simplifying Radicals Introduction to Logarithms Unit Conversion Speed translation.....

Introduction to logarithm properties | Logarithms | Algebra II | Khan Academy


By Khan Academy

This video lecture series on Pre-algebra from Khan Academy includes Order of Operations, Adding and Subtracting Negative Numbers, Multiplying and Dividing Negative Numbers, Adding and Subtracting Fractions, Multiplying and Dividing Fractions, Exponents, Exponent Rules, Simplifying Radicals, Introduction to Logarithms, Unit Conversion, Speed translation.....

Simplifying radicals | Exponents, radicals, and scientific notation | Pre-Algebra | Khan Academy


By Khan Academy

This video lecture series on Pre-algebra from Khan Academy includes Order of Operations, Adding and Subtracting Negative Numbers, Multiplying and Dividing Negative Numbers, Adding and Subtracting Fractions, Multiplying and Dividing Fractions, Exponents, Exponent Rules, Simplifying Radicals, Introduction to Logarithms, Unit Conversion, Speed translation.

[5.NBT.2-1.0] Multiplying/Dividing by 10 - Common Core Standard - Practice Problem


By Front Row

Explain patterns in the number of zeros of the product when multiplying a number by powers of 10, use whole-number exponents to denote powers of 10

Dividing Scientific Notation | MathHelp.com


By MathHelp.com

To multiply numbers that are in written in scientific notation, such as 1.4 x 10 to the -2nd times 5.3 times 10 to the 6th, we first multiply the decimals, in this case 1.4 times 5.3, to get 7.42. Next, we multiply the powers of 10, in this case 10 to the -2nd times 10 to the 6th. Notice that we’re multiplying two powers that have like bases, so we add the exponents and leave the base the same, to get 10 to the -2 + 6, or 10 to the 4th. So we have 7.42 times 10 to the 4th. Finally, we’re asked to write our answer in scientific notation. Notice, however, that 7.42 times 10 to the -4th is already written in scientific notation, because we have a decimal between 1 and 10 that is multiplied by a power of 10. So we have our answer.

Rational Exponents | MathHelp.com


By MathHelp.com

In this example, we’re asked to write “a” to the negative 3rd squared in simplest form without negative or zero exponents. Remember that the power rule tells us that when we have a power taken to another power, such as a to the negative 3rd squared, we multiply the exponents. So we have a to the -3 times 2, or a to the negative 6th. Finally, remember from our study of negative exponents that a to the negative 6th can be written as 1 over a to the positive 6th. So a to the negative 3rd squared simplifies to 1 over a to the 6th.

Product Rule | Adding Exponents | MathHelp.com


By MathHelp.com

This lesson covers multiplying integers. Students learn to multiply integers using the following rules. A positive times a positive equals a positive. For example, +3 x +5 = +15. A positive times a negative equals a negative. For example, +3 x -5 = -15. A negative times a positive equals a negative. For example, -3 x +5 = -15. And a negative times a negative equals a positive. For example, -3 x -5 = +15. In other words, if the signs are the same, the product is positive, and if the signs are different, the product is negative.

Negative Exponents | MathHelp.com


By MathHelp.com

In this example, we’re given the functions f(x) = 3x – 2 (read as “f of x equals…”) and g(x) = root x, and we’re asked to find the composite functions f(g(9)) (read as “f of g of 9”) and g(f(9). To find f(g(9)), we first find g(9). Since g(x) = root x, we can find g(9) by substituting a 9 in for the x in the function, to get g(9) = root 9, and the square root of 9 is 3, so g(9) = 3. Now, since g(9) = 3, f(g(9)) is the same thing as f(3), so our next step is to find f(3). And remember that f(x) = 3x – 2, so to find f(3), we substitute a 3 in for the x in the function, and we have f(3) = 3 times 3 minus 2. Notice that I always use parentheses when substituting a value into a function, in this case 3. Finally, 3 times 3 minus 2 simplifies to 9 minus 2, or 7, so f(3) = 7. Therefore, f(g(9)) = 7. Next, to find g(f(9), we first find f(9). Since f(x) = 3x - 2, we find f(9) by substituting a 9 in for the x in the function, to get f(9) = 3 times 9 minus 2, which simplifies to 27 – 2, or 25, so f(9) = 25. Now, since f(9) = 25, g(f(9)) is the same thing as g(25), so our next step is to find g(25). And remember that g(x) = root x, so to find g(25), we substitute a 25 in for the x in the function, to get g(25) = root 25. Finally, the square root of 25 is 5, so g(25) = 5. Therefore, g(f(9)) = 5. It’s important to recognize that