Surface Area of a Rectangular Pyramid | Math with Mr. J - By Math with Mr. J
Transcript
00:0-1 | Welcome to Math with MR . J . In this | |
00:04 | video , I'm going to cover how to find the | |
00:06 | surface area of a rectangular pyramid . And remember surface | |
00:11 | area is the total area of the outside or surface | |
00:14 | of a three dimensional shape . When it comes to | |
00:18 | rectangular pyramids , we have five total faces , The | |
00:22 | base and four lateral faces . The lateral faces are | |
00:26 | the triangular faces going around the pyramid , so to | |
00:29 | speak . We need to find the area of all | |
00:32 | of these and then add them together to get the | |
00:35 | total surface area . So let's jump into our example | |
00:39 | . And start by writing out surface area equals the | |
00:45 | area of the base plus the lateral area . Then | |
00:51 | we need to plug in our information so we need | |
00:54 | to calculate the area of the base and all of | |
00:57 | the lateral faces . Then add them together . Let's | |
01:01 | use the net on the right side of the screen | |
01:04 | to help us do this . You can think of | |
01:06 | a net as an unfolded three D . Shape . | |
01:09 | It shows us all of the parts , so to | |
01:11 | speak . Let's start with the area of the base | |
01:15 | . So we have a rectangular base so we can | |
01:18 | use the formula area equals length times . With Now | |
01:23 | I'm going to use the bottom portion of the screen | |
01:26 | to show all my work as far as where I'm | |
01:29 | going to calculate the areas . So let's come to | |
01:32 | the bottom left area equals length times . With . | |
01:38 | Now we plug in so our base has a length | |
01:43 | of nine m and a width of five m . | |
01:48 | So nine times five . Now , if you use | |
01:53 | five for the length and nine for the with that | |
01:56 | would work as well . Don't get too held up | |
01:58 | on which one is length or with , because nine | |
02:01 | times five is the same as five times nine . | |
02:04 | Both will give you the correct area . So the | |
02:08 | area of our rectangular base is 45 square meters . | |
02:16 | I'm going to put a capital B above that . | |
02:19 | So we know that that is the area of the | |
02:21 | base . Now that we have the area of the | |
02:24 | base , we can move to the lateral faces . | |
02:27 | And since we do not have a regular base , | |
02:31 | regular means all of the sides are the same and | |
02:34 | this is not the case . This means that we | |
02:36 | will have two different slant heights and therefore to different | |
02:40 | areas for our lateral faces . These will have the | |
02:44 | same area , the top and bottom of the net | |
02:48 | because they have the same base nine m and same | |
02:51 | height eight and 38/100 metres . The left and right | |
02:58 | . We'll have the same area because they have the | |
03:01 | same base of five m and same height of nine | |
03:05 | and 18/100 metres . So let's calculate the top and | |
03:10 | bottom lateral faces of the net . First these would | |
03:13 | be the front and back lateral faces of the three | |
03:17 | D . Shape on the left hand side of the | |
03:19 | screen . Now since we're working with triangles we can | |
03:23 | use the formula area equals one half times the base | |
03:27 | times the height . So area equals one half times | |
03:33 | the base times the height . Now you can also | |
03:37 | use base times height divided by two for triangles , | |
03:40 | multiplying by a half or dividing by two . They | |
03:43 | will get you the same answer . So whatever formula | |
03:46 | works best for you , that's what you can use | |
03:49 | for finding the area of these triangles . Now we | |
03:52 | plug in so again we're going to do the top | |
03:55 | and bottom from the net first so one half times | |
03:59 | the base while these have a base of nine m | |
04:05 | . So let's plug in nine times the height Of | |
04:12 | 8:38 . And now we're ready to calculate . So | |
04:18 | the area of those lateral faces is going to be | |
04:22 | 37 and 71/100 . And this is square meters . | |
04:32 | Now I'm going to label this with one star above | |
04:35 | it . So we know that it is the top | |
04:38 | and bottom lateral faces of that net so we can | |
04:42 | move to the left and right lateral faces now And | |
04:46 | we have triangles . So we will write out our | |
04:50 | formula area equals 1/2 times base times height . And | |
04:55 | now we plug in so 1/2 and these lateral faces | |
04:59 | have bases of five m . So let's plug in | |
05:04 | five And a height of nine and 1800s m . | |
05:10 | So nine in 18 hundreds . Now we calculate , | |
05:15 | So that's going to give us an area of 22 | |
05:21 | And 9500 m2 . And I'm going to label this | |
05:29 | with two stars . So we know which lateral faces | |
05:34 | Have the area of 22 and 9500 m2 . So | |
05:40 | once we have all of the areas calculated for our | |
05:44 | faces , we can fill in our net to show | |
05:47 | exactly which areas go where and it will help us | |
05:51 | stay organized . So we know that the area of | |
05:54 | the base was 45 m2 . So let's Plug that | |
06:01 | in there . And then our one star lateral faces | |
06:07 | . 37 and 71:00 m2 . So let's label those | |
06:17 | . And I'll put this one on the outside here | |
06:21 | . So 37 and 71,000 m2 . And this goes | |
06:26 | right here . And now we have the two star | |
06:30 | lateral faces , the left and the right . 22 | |
06:34 | and 9500s . So let's squeeze this in here . | |
06:38 | 22 In 9500s m2 . And then 22 In 9500s | |
06:48 | m2 . Goes right here . So we again have | |
06:53 | the areas for all of our faces , the base | |
06:57 | and then the lateral faces . So now it's time | |
07:01 | to add everything up to calculate that total surface area | |
07:05 | . Now let's come back up top and add these | |
07:08 | . So we have surface area equals the area of | |
07:12 | the base 45 Plus . Now we have all of | |
07:17 | our lateral faces . Let's start with the top and | |
07:20 | bottom . So 37 and 71/100 plus 37 71/100 . | |
07:28 | Now , I'm going to have to go below here | |
07:30 | in order to squeeze everything in . And now we | |
07:32 | have the left and right . So 22 in 95/100 | |
07:37 | plus 22 95/100 . So you can see that we | |
07:42 | added five numbers together . Five areas those represent our | |
07:47 | five faces . Now it's time to calculate . So | |
07:51 | the total surface area equals 166 And 32:00 m2 . | |
08:03 | And that is our final answer . So there you | |
08:09 | have it . There is how you find the surface | |
08:12 | area of a rectangular pyramid . I hope that helped | |
08:15 | . Thanks so much for watching until next time . | |
08:19 | Peace . Yeah , yeah , yeah . |
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