Exploring Circuits - Free Educational videos for Students in K-12 | Lumos Learning

Exploring Circuits - Free Educational videos for Students in k-12


Exploring Circuits - By MITK12Videos



Transcript
00:05 In today's lesson , we're going to explore some simple
00:08 electric circuits . Circuits can be found in every corner
00:11 of your house , but how do they work ?
00:13 And what tools the engineers used to design them .
00:15 Engineers use pictures called circuit diagrams to visualize electric circuits
00:20 . This diagram shows a simple circuit in which a
00:22 battery provides a potential that drives an electric current through
00:26 a resistor . Recall that OEMs Law relates the important
00:30 circuit properties , potential current and resistance . The potential
00:34 drop across the resistor is equal to the current flowing
00:37 through that resistor times the value of the resistor .
00:42 This water experiment provides an analogy where we can better
00:45 visualize potential current and resistance in a circuit here ,
00:51 electric potential is related to the height of the water
00:54 . The water starts at the top of the funnel
00:57 And drops 18" to the flask at the bottom .
01:00 This is a potential drop of 18" . Electric current
01:05 is related to the flow of the water through this
01:07 circuit We start with 100 mL of water at the
01:11 top and it all drains to the bottom in 20
01:13 seconds . This is a current Of five mm/s .
01:18 The resistance is related to the number of loops .
01:22 The more loops you have , the more resistance .
01:26 Now let's look at potential current and resistance in an
01:29 electric circuit . Our battery provides 9V of potential to
01:33 drive current through resistor 1500 homes . Pause this video
01:37 and try using arms law in these circuit parameters to
01:40 calculate the current when you come back . We'll measure
01:43 it using a meter . Engineers use a tool called
01:47 a digital multi meter to measure current and potential and
01:49 electric circuits to measure current . The meter must be
01:53 set up in current mode . This means placing the
01:55 red lead into the current slot and turning the dial
01:58 to a for amps . Let's look at our circuit
02:01 diagram to see where the meter goes in order to
02:04 measure current . You must first break the circuit And
02:08 place the meter such that the current flows from the
02:10 battery through the meter and then three year resistor .
02:15 The meter shows that the current is 0.5 amps .
02:18 How does this compare to your calculated value from OMs
02:21 law ? It should be pretty close to measure potential
02:24 using a digital multi meter , the media must be
02:27 set up in potential mode . This means moving the
02:29 red lead to the potential slot and turning the knob
02:32 to V . For volts . Let's look at our
02:34 circuit diagram to see where the meter goes . We
02:37 measure potential . We must measure it across a circuit
02:39 element . This means placing the red lead of the
02:41 meter on one side of the element and the black
02:44 lead on the other . Our meter shows the potential
02:47 drop across the resistor is 8.93V . This is very
02:51 close to the battery potential of 9V . Let's move
02:55 on to explore some more complicated circuits . Series circuits
02:59 consist of elements that appear one after another , where
03:02 parallel circuits elements appear side by side . Let's investigate
03:07 how potential and current properties differ between these two circuit
03:10 types . The diagram on the left represents a series
03:13 circuit where a battery supplies current that flows through two
03:17 resistors , placed one after another . On the right
03:20 are the series circuit properties . The first talks about
03:23 potential . The potential supplied by the battery must drop
03:26 over the sum of the two resistors , part over
03:29 the first and the remainder over the second . The
03:32 second property talks about current current flows through each resistor
03:36 , one after the other . That means the same
03:39 current that flows through the first resistor must flow through
03:41 the second . The total resistance in a series circuit
03:45 is the sum of the two resistance is , let's
03:48 return to our water experiments . We can better understand
03:50 potential and current in a series circuit , water starts
03:53 in the funnel at the top and must travel through
03:55 each of the loops on the way to the bottom
03:58 , one after the other notice that there's two distinct
04:02 potential drops in the circuit , from 28 to 14
04:05 inches across the first set of loops and from 14
04:08 to 0 inches across the second set . For a
04:11 total potential drop of 28 inches , 100 ml of
04:15 water starts at the top And it all drains to
04:17 the flask at the bottom in 25 seconds . A
04:20 current of four ml/s . The water experiences more resistance
04:25 in the circuit . Therefore , the current is smaller
04:30 . In our series electric circuit , a nine volt
04:33 battery supplies current that flows through two resistors each of
04:36 1500 homes . To measure the current in the circuit
04:39 , I broke the circuit here and place the meter
04:41 within it . Our meter reads three million amps .
04:45 This is the current within our circuit and it's the
04:47 same regardless of where we measure it because there's only
04:50 one path for the current to take . I've rearranged
04:53 the meters to measure potential in the series circuit .
04:56 This meter reads potential drop across resistor one , which
05:00 is about 4.5V . This meter reaches potential drop across
05:05 resistor to which is also 4.5V Add these two values
05:09 together and you get the battery potential 9V . The
05:13 diagram on the left represents a parallel circuit where a
05:16 battery supplies current that flows through two resistors placed side
05:19 by side . The parallel circuit properties are on the
05:22 right . The first talks about current . The current
05:25 supply by the battery has a choice as it splits
05:28 between a path through are one and the path through
05:31 our two . The second property talks about potential .
05:35 The potential supply by the battery is the same potential
05:38 that drops across our one and is also the same
05:41 potential that drops across our two . The total resistance
05:45 in a parallel circuit is given by this expression and
05:48 is less than that is seen in a series circuit
05:51 . Let's return to our water experiment one more time
05:53 . So we can better understand potential and current .
05:55 In a parallel circuit , water starts in the funnel
05:58 at the top and can take one of two paths
06:00 to the flasks at the bottom , either through the
06:02 left loops or the right loops . Notice that the
06:05 potential drop is 18" , regardless of which path the
06:08 water takes . We start with 100 mL of water
06:12 at the top and approximately 50 ml ends up in
06:15 each of the flask at the bottom . It takes
06:17 about 12 seconds . This means that the current in
06:21 each path is about four mm/s , Adding these together
06:25 . We get eight per second for a total current
06:30 . You should expect the current to be higher in
06:32 a parallel circuit . This is because there are two
06:35 distinct paths for the water to flow . Therefore the
06:38 water sees less resistance and is able to flow faster
06:41 through the circuit . In our parallel electric circuit ,
06:44 a nine volt battery supplies current that flows through to
06:47 1500 ohm resistors placed side by side to measure the
06:51 total current in the circuit . I broke it here
06:54 . The meter reads 12 million amps . How to
06:56 measure the current flowing through our two , I broke
06:59 the circuit here . This current is six million amps
07:02 , which is less than the total because the remainder
07:05 must flow through our one . I've rearranged the meters
07:09 to measure potential in a parallel circuit . This meter
07:13 measures the potential drop across resistor one And it's about
07:16 9V . This meter reads a potential dropped across R
07:21 two is also 9V . Notice that the potential drop
07:25 across both resistors and the parallel circuit is equal to
07:28 that of the battery . Now it's your job to
07:33 keep exploring challenge yourself by investigating voltage in current .
07:36 More complicated circuits , like if you change the values
07:39 of resistance or if you add a third resistor or
07:42 even if you can buy in series and parallel circuits
07:44 to form a big mega circuit .
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