Exploring Circuits - By MITK12Videos
Transcript
00:05 | In today's lesson , we're going to explore some simple | |
00:08 | electric circuits . Circuits can be found in every corner | |
00:11 | of your house , but how do they work ? | |
00:13 | And what tools the engineers used to design them . | |
00:15 | Engineers use pictures called circuit diagrams to visualize electric circuits | |
00:20 | . This diagram shows a simple circuit in which a | |
00:22 | battery provides a potential that drives an electric current through | |
00:26 | a resistor . Recall that OEMs Law relates the important | |
00:30 | circuit properties , potential current and resistance . The potential | |
00:34 | drop across the resistor is equal to the current flowing | |
00:37 | through that resistor times the value of the resistor . | |
00:42 | This water experiment provides an analogy where we can better | |
00:45 | visualize potential current and resistance in a circuit here , | |
00:51 | electric potential is related to the height of the water | |
00:54 | . The water starts at the top of the funnel | |
00:57 | And drops 18" to the flask at the bottom . | |
01:00 | This is a potential drop of 18" . Electric current | |
01:05 | is related to the flow of the water through this | |
01:07 | circuit We start with 100 mL of water at the | |
01:11 | top and it all drains to the bottom in 20 | |
01:13 | seconds . This is a current Of five mm/s . | |
01:18 | The resistance is related to the number of loops . | |
01:22 | The more loops you have , the more resistance . | |
01:26 | Now let's look at potential current and resistance in an | |
01:29 | electric circuit . Our battery provides 9V of potential to | |
01:33 | drive current through resistor 1500 homes . Pause this video | |
01:37 | and try using arms law in these circuit parameters to | |
01:40 | calculate the current when you come back . We'll measure | |
01:43 | it using a meter . Engineers use a tool called | |
01:47 | a digital multi meter to measure current and potential and | |
01:49 | electric circuits to measure current . The meter must be | |
01:53 | set up in current mode . This means placing the | |
01:55 | red lead into the current slot and turning the dial | |
01:58 | to a for amps . Let's look at our circuit | |
02:01 | diagram to see where the meter goes in order to | |
02:04 | measure current . You must first break the circuit And | |
02:08 | place the meter such that the current flows from the | |
02:10 | battery through the meter and then three year resistor . | |
02:15 | The meter shows that the current is 0.5 amps . | |
02:18 | How does this compare to your calculated value from OMs | |
02:21 | law ? It should be pretty close to measure potential | |
02:24 | using a digital multi meter , the media must be | |
02:27 | set up in potential mode . This means moving the | |
02:29 | red lead to the potential slot and turning the knob | |
02:32 | to V . For volts . Let's look at our | |
02:34 | circuit diagram to see where the meter goes . We | |
02:37 | measure potential . We must measure it across a circuit | |
02:39 | element . This means placing the red lead of the | |
02:41 | meter on one side of the element and the black | |
02:44 | lead on the other . Our meter shows the potential | |
02:47 | drop across the resistor is 8.93V . This is very | |
02:51 | close to the battery potential of 9V . Let's move | |
02:55 | on to explore some more complicated circuits . Series circuits | |
02:59 | consist of elements that appear one after another , where | |
03:02 | parallel circuits elements appear side by side . Let's investigate | |
03:07 | how potential and current properties differ between these two circuit | |
03:10 | types . The diagram on the left represents a series | |
03:13 | circuit where a battery supplies current that flows through two | |
03:17 | resistors , placed one after another . On the right | |
03:20 | are the series circuit properties . The first talks about | |
03:23 | potential . The potential supplied by the battery must drop | |
03:26 | over the sum of the two resistors , part over | |
03:29 | the first and the remainder over the second . The | |
03:32 | second property talks about current current flows through each resistor | |
03:36 | , one after the other . That means the same | |
03:39 | current that flows through the first resistor must flow through | |
03:41 | the second . The total resistance in a series circuit | |
03:45 | is the sum of the two resistance is , let's | |
03:48 | return to our water experiments . We can better understand | |
03:50 | potential and current in a series circuit , water starts | |
03:53 | in the funnel at the top and must travel through | |
03:55 | each of the loops on the way to the bottom | |
03:58 | , one after the other notice that there's two distinct | |
04:02 | potential drops in the circuit , from 28 to 14 | |
04:05 | inches across the first set of loops and from 14 | |
04:08 | to 0 inches across the second set . For a | |
04:11 | total potential drop of 28 inches , 100 ml of | |
04:15 | water starts at the top And it all drains to | |
04:17 | the flask at the bottom in 25 seconds . A | |
04:20 | current of four ml/s . The water experiences more resistance | |
04:25 | in the circuit . Therefore , the current is smaller | |
04:30 | . In our series electric circuit , a nine volt | |
04:33 | battery supplies current that flows through two resistors each of | |
04:36 | 1500 homes . To measure the current in the circuit | |
04:39 | , I broke the circuit here and place the meter | |
04:41 | within it . Our meter reads three million amps . | |
04:45 | This is the current within our circuit and it's the | |
04:47 | same regardless of where we measure it because there's only | |
04:50 | one path for the current to take . I've rearranged | |
04:53 | the meters to measure potential in the series circuit . | |
04:56 | This meter reads potential drop across resistor one , which | |
05:00 | is about 4.5V . This meter reaches potential drop across | |
05:05 | resistor to which is also 4.5V Add these two values | |
05:09 | together and you get the battery potential 9V . The | |
05:13 | diagram on the left represents a parallel circuit where a | |
05:16 | battery supplies current that flows through two resistors placed side | |
05:19 | by side . The parallel circuit properties are on the | |
05:22 | right . The first talks about current . The current | |
05:25 | supply by the battery has a choice as it splits | |
05:28 | between a path through are one and the path through | |
05:31 | our two . The second property talks about potential . | |
05:35 | The potential supply by the battery is the same potential | |
05:38 | that drops across our one and is also the same | |
05:41 | potential that drops across our two . The total resistance | |
05:45 | in a parallel circuit is given by this expression and | |
05:48 | is less than that is seen in a series circuit | |
05:51 | . Let's return to our water experiment one more time | |
05:53 | . So we can better understand potential and current . | |
05:55 | In a parallel circuit , water starts in the funnel | |
05:58 | at the top and can take one of two paths | |
06:00 | to the flasks at the bottom , either through the | |
06:02 | left loops or the right loops . Notice that the | |
06:05 | potential drop is 18" , regardless of which path the | |
06:08 | water takes . We start with 100 mL of water | |
06:12 | at the top and approximately 50 ml ends up in | |
06:15 | each of the flask at the bottom . It takes | |
06:17 | about 12 seconds . This means that the current in | |
06:21 | each path is about four mm/s , Adding these together | |
06:25 | . We get eight per second for a total current | |
06:30 | . You should expect the current to be higher in | |
06:32 | a parallel circuit . This is because there are two | |
06:35 | distinct paths for the water to flow . Therefore the | |
06:38 | water sees less resistance and is able to flow faster | |
06:41 | through the circuit . In our parallel electric circuit , | |
06:44 | a nine volt battery supplies current that flows through to | |
06:47 | 1500 ohm resistors placed side by side to measure the | |
06:51 | total current in the circuit . I broke it here | |
06:54 | . The meter reads 12 million amps . How to | |
06:56 | measure the current flowing through our two , I broke | |
06:59 | the circuit here . This current is six million amps | |
07:02 | , which is less than the total because the remainder | |
07:05 | must flow through our one . I've rearranged the meters | |
07:09 | to measure potential in a parallel circuit . This meter | |
07:13 | measures the potential drop across resistor one And it's about | |
07:16 | 9V . This meter reads a potential dropped across R | |
07:21 | two is also 9V . Notice that the potential drop | |
07:25 | across both resistors and the parallel circuit is equal to | |
07:28 | that of the battery . Now it's your job to | |
07:33 | keep exploring challenge yourself by investigating voltage in current . | |
07:36 | More complicated circuits , like if you change the values | |
07:39 | of resistance or if you add a third resistor or | |
07:42 | even if you can buy in series and parallel circuits | |
07:44 | to form a big mega circuit . |
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Exploring Circuits is a free educational video by MITK12Videos.
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