01 - Direct Variation and Proportion in Algebra - Part 1 (Constant of Variation & More) - By Math and Science
Transcript
00:01 | Hello . Welcome back to algebra . The title of | |
00:02 | this lesson is direct variation and proportion . This is | |
00:06 | part one of two lessons . So we're talking about | |
00:09 | in this case the concept of direct variation . Now | |
00:12 | this is going to be in contrast , a couple | |
00:14 | of lessons down the road , we're gonna talk about | |
00:16 | inverse variation . So in the back of your mind | |
00:18 | , when we talk about direct variation , just keep | |
00:20 | in mind that we also have kind of a cousin | |
00:23 | of this which is called inverse variation , which will | |
00:25 | they will kind of go hand in hand together . | |
00:27 | But in this case we're gonna be talking about direct | |
00:29 | variation in a nutshell , when you have two variables | |
00:33 | that are related to one another , right ? Then | |
00:36 | oftentimes we say that they vary directly with respect to | |
00:40 | one another . And what direct variation means in this | |
00:42 | case , when you have two variables that have a | |
00:44 | direct variation relationship between them all , it means is | |
00:48 | very simple to understand is that when you increase one | |
00:51 | of the variables , the other variable also increases , | |
00:54 | so they increase in direct correspondence to one another . | |
00:57 | Right ? Alternatively , if one variable goes down then | |
01:00 | the kind of like the partner variable goes down with | |
01:03 | it . So when you have two variables that both | |
01:06 | go up together or both go down together , we | |
01:08 | call it direct variation and we're gonna find out in | |
01:11 | several lessons down the road . The inverse variation is | |
01:14 | when one variable might go up while that would cause | |
01:17 | the other variable to go down so they go opposite | |
01:19 | of each other . That's what we call inverse variation | |
01:21 | . So in math terms we want to talk about | |
01:23 | when we talk about direct variation is the following thing | |
01:27 | . And let me tell you right now , it's | |
01:28 | very easy to understand because we've learned so much about | |
01:31 | lines and you're going to see in a second that | |
01:33 | this is all related to the equation of a line | |
01:35 | . So , direct variation . And the other thing | |
01:38 | I'll say before we get started is we talk about | |
01:41 | direct variation so much in algebra , because there are | |
01:44 | many , many equations in physics and chemistry and engineering | |
01:48 | that have a direct variation relationship . So I'm gonna | |
01:51 | actually show you some of them in just a second | |
01:53 | . But just keep in mind that this is actually | |
01:54 | useful because a lot of the physical laws we have | |
01:57 | in the universe actually obey a direct variation kind of | |
02:00 | kind of relationship . So what does direct variation means | |
02:03 | ? It means we have two variables . I'm gonna | |
02:05 | call one of them X and I'm going to call | |
02:07 | the other one why ? And their related to one | |
02:09 | another , right ? There's lots of lots of variables | |
02:12 | and I'll give you examples in a second that are | |
02:14 | related to one another . So a direct variation means | |
02:16 | that as the variable X increases , that's what the | |
02:19 | up arrow means . If it goes up up up | |
02:21 | up up up up then a direct variation means that's | |
02:25 | what this this little arrow means . It means as | |
02:27 | X goes up , it means that the variable Y | |
02:29 | also goes up now , it does not mean that | |
02:33 | X and Y have to go up at the exact | |
02:35 | same rate . Okay ? You could have X going | |
02:37 | up really , really fast and you could have why | |
02:39 | going up in a slower fashion or you could have | |
02:42 | X going up really , really slow and why going | |
02:44 | up even faster ? A faster variation . So they | |
02:48 | don't have to go at the same speed up , | |
02:50 | but they both have to go the same direction . | |
02:52 | So what it means is that as X goes up | |
02:54 | why must also go up ? All right . And | |
02:57 | in the case of inverse variation , we'll talk about | |
02:59 | later as X goes up , the variable Y goes | |
03:01 | down in the opposite way . So , um what | |
03:05 | this means is that when you when you boil it | |
03:08 | down and start graphing pairs of X and Y points | |
03:10 | and you see that as X goes up implies that | |
03:12 | why goes up , then what it basically means is | |
03:15 | the variable Y is equal to some number M . | |
03:19 | Which we're using a letter in because it's going to | |
03:21 | end up being the slope of the line times X | |
03:24 | . So you might look at this and say wait | |
03:26 | a minute , doesn't this look familiar ? Y equals | |
03:28 | mx Because we talked about lines a whole lot mx | |
03:31 | plus B , right , M was the slope of | |
03:33 | the line and B is the Y intercept . So | |
03:37 | when we talk about direct variation , literally , it | |
03:40 | is the exact same stuff that we learned and we | |
03:42 | talk about the equation of a line . But uh | |
03:45 | the Y intercept B is always set equal to zero | |
03:49 | and you'll see why in just a second . But | |
03:51 | what this means is that X go up , Why | |
03:53 | goes up in in terms of this relationship , notice | |
03:57 | how the equation is set up , even if M | |
03:59 | was no matter what M . Is , let's say | |
04:01 | M . Is equal to to let the slope of | |
04:03 | this uh line here as X goes up . If | |
04:07 | you make X one and two and three and four | |
04:09 | , when you multiply by M , then why must | |
04:11 | also go up ? So this is the form of | |
04:13 | a direct variation . And we say in words that | |
04:17 | why varies directly as X . And what this wording | |
04:26 | means is when X goes up , why goes up | |
04:29 | , that's what it means . And this is what | |
04:30 | the equation tells you , even if M . Is | |
04:31 | one half . Uh If X increases from 1 to | |
04:35 | 2 to three of the four , then why must | |
04:38 | also be increased by whatever the numbers are . You | |
04:41 | just multiply what M . Is and you're gonna get | |
04:43 | larger and larger values of why ? Now we have | |
04:45 | a special name for this . By the way . | |
04:48 | You might also see this in your textbook . You | |
04:51 | might see this , I'll do this , you might | |
04:54 | see uh why is equal to K . X . | |
04:57 | So some books don't use the letter M . They | |
05:00 | use the letter K . This uh variables , this | |
05:03 | uh entity , him the M . Here . Or | |
05:06 | if you see it in a book as K . | |
05:07 | Whatever you label it there , that thing uh In | |
05:10 | this case I'm using them . So I'm gonna say | |
05:12 | M . Is equal to the constant of variation . | |
05:21 | So M . Can be whatever you want it to | |
05:22 | be , depending on the problem or depending on the | |
05:24 | equation that you're looking at . But this thing M | |
05:26 | . Is equal to a constant is called a constant | |
05:29 | variation . So if M were equal to one for | |
05:32 | instance , then you just have one here . Then | |
05:35 | as X goes up 1234 then you multiply by one | |
05:38 | . Why would be going up 1234 ? But if | |
05:40 | M were to , let's say then every time I | |
05:43 | increase X and I'm multiplying by two . So you | |
05:46 | see why is actually would be increasing faster than X | |
05:49 | . Because if M is one , I multiplied by | |
05:52 | two . I'll give me too . If if X | |
05:55 | is too , I multiplied by two , I would | |
05:56 | get four . If X would be three , I | |
05:58 | multiplied by two , I get six . So you | |
06:00 | see the constant variation determines the exact relationship between X | |
06:05 | and Y . But in all cases when X goes | |
06:08 | up , why must go up ? But the constant | |
06:10 | variation determines how fast why goes up when I increase | |
06:14 | X , how much faster is why increasing ? Remember | |
06:17 | I told you why can be going up faster than | |
06:19 | X ? Or why can be going up slower than | |
06:22 | X . But they must be going in the same | |
06:23 | direction and what determines how fast they move with respect | |
06:26 | to one another is called the constant variation . Now | |
06:29 | you might see this as K . So , in | |
06:31 | your textbook you might see K is the constant variation | |
06:34 | . So you might see or K little bit lower | |
06:37 | case . K would be the constant variation . All | |
06:40 | right . So , we've done a little bit of | |
06:41 | theory here , and it's a little bit abstract . | |
06:43 | So , I want to talk to you about some | |
06:44 | real examples of direct variation . So , examples . | |
06:50 | And these are examples that you all know Right ? | |
06:52 | I like giving examples that you all know . So | |
06:54 | let's take a famous example . What about this equation | |
06:57 | ? Do you recognize this ? Whoops . C is | |
07:00 | equal to pi times deep . I think you recognize | |
07:04 | that from fifth grade right ? The circumference of the | |
07:06 | circle is equal to pi times the diameter of the | |
07:10 | circle . So notice the way this thing is set | |
07:12 | up . It isn't exactly the same form as this | |
07:15 | equation . Have a variable equal to a constant notice | |
07:19 | it's a constant , this is not a variable . | |
07:21 | It's a constant variation means it's just a number , | |
07:24 | Pi is just a numbers 3.14159 it goes on and | |
07:27 | on with non repeating decimals and then time some other | |
07:31 | variable . So notice that as the diameter of the | |
07:33 | circle increases you make the circle larger , you multiply | |
07:37 | by pi . The circumference also gets larger . So | |
07:39 | as the diameter increases , the circumference also increases , | |
07:43 | which is exactly what we said . The relationship has | |
07:45 | to be here . Pie , Is that special number | |
07:49 | that governs how much the circumference increases when the diameter | |
07:53 | also increases ? It's the constant variation . You might | |
07:56 | also see it as something called the constant of proportionality | |
07:59 | . So this the title of this lesson is direct | |
08:01 | variation in proportion . So this is a direct variation | |
08:04 | relationship . But you can see that the reason we | |
08:07 | use the word proportional is that the diameter of the | |
08:09 | circle and its circumference are proportional to one another . | |
08:12 | And proportion just means that as one goes up then | |
08:15 | the other variable goes up as well . The constant | |
08:17 | of proportionality are also called . The constant variation just | |
08:20 | determines how much that other variable goes up . All | |
08:25 | right , What are some other examples ? This one | |
08:27 | you might or might not know , but it's one | |
08:29 | of the most famous equations in all of physics . | |
08:31 | F is equal to M . A . So this | |
08:34 | is force is equal to mass times acceleration . This | |
08:38 | means if I take a baseball or anything with some | |
08:42 | mass , the mass of the ball is constant , | |
08:44 | right ? It's just a fixed thing . The mass | |
08:46 | of the ball doesn't change . So even though it | |
08:48 | looks like a variable here , the mass is really | |
08:50 | the constant of variation here , and you can see | |
08:53 | that the acceleration in the force on that ball have | |
08:55 | to be there related directly as the acceleration on the | |
08:58 | ball goes up . In other words , I have | |
09:00 | to throw the ball with some force in order to | |
09:02 | accelerate , I have to push the ball with some | |
09:05 | uh some force in order to get it to accelerate | |
09:07 | to go faster and faster . But you can see | |
09:10 | that as the acceleration is bigger , bigger , bigger | |
09:12 | , bigger , bigger . The force applied to the | |
09:14 | ball must also be bigger , bigger , bigger , | |
09:15 | bigger , bigger . And the mass is that special | |
09:18 | quantity that governs how how the force and the acceleration | |
09:23 | are linked . Because you all know that if you | |
09:25 | have a bowling ball it's much harder to accelerate a | |
09:28 | bowling ball with the same force , right ? If | |
09:30 | I apply the same force to a ping pong ball | |
09:34 | and a bowling ball , same force , the acceleration | |
09:37 | will be different . We call it inertia , right | |
09:38 | . Things are harder to push harder to get going | |
09:41 | . So the masses , that thing that governs and | |
09:43 | links the force and the acceleration together . It's the | |
09:46 | constant of variation . So you can see as acceleration | |
09:48 | goes up , mass goes up . What's one more | |
09:52 | ? We'll talk in physics , we'll talk about something | |
09:54 | called the potential energy of something . The potential energy | |
09:57 | is equal to M . Times G . Times H | |
10:00 | . So this is a fancy sounding thing but it's | |
10:02 | it's not fancy . What it basically means is the | |
10:05 | energy when you the potential energy when you hold something | |
10:08 | above the ground is equal to the mass of the | |
10:11 | thing . Like a bowling ball times G , which | |
10:13 | is the gravity on Earth 9.8 m per second . | |
10:16 | It's a gravitational acceleration 9.8 m per second squared times | |
10:21 | the height above the ground . The height above the | |
10:22 | ground is the most important thing . As I raise | |
10:25 | the thing higher above the ground , we say has | |
10:26 | more potential energy . If you climb to the top | |
10:29 | of a building , you have a lot more potential | |
10:31 | energy than if you're on a step ladder . If | |
10:34 | I jump off the step ladder , it's not gonna | |
10:35 | be a problem . But if I jump off the | |
10:37 | building , that potential energy makes you go split into | |
10:41 | the ground . So you have a lot more potential | |
10:42 | energy , the higher you are . So you see | |
10:44 | , the higher you go above the ground , the | |
10:46 | more energy you have . And these are directly related | |
10:49 | . Now , you might say , well , wait | |
10:50 | a minute . There's two things listed here and here | |
10:53 | . I only had one constant variation . But really | |
10:55 | the mass of the ball is never changes and the | |
10:59 | and the acceleration of earth never changes . So , | |
11:02 | these things multiplied together , they become like one constant | |
11:05 | . These are like , like one constant when you | |
11:08 | multiply there just one number , right ? The mass | |
11:10 | of the ball times gravity is one number . So | |
11:12 | , this is really the constant variation . These two | |
11:14 | things kind of multiplied together , and you can see | |
11:16 | they govern how much energy you get when you go | |
11:19 | higher and higher off the ground . All right . | |
11:22 | So those are some examples of what a direct variation | |
11:27 | is , and that's why I told you in the | |
11:28 | beginning , it's so very important . These are just | |
11:30 | three equations . Um They look so simple , but | |
11:34 | it turns out you can solve a lot of problems | |
11:36 | with these kinds of equations . So this direct variation | |
11:38 | is extremely important . Now let's dive a little bit | |
11:41 | deeper into what direct variation is . It looks like | |
11:45 | the equation of the line . However , the plus | |
11:49 | B is gone . Now let's go and investigate exactly | |
11:52 | why that's the case . Let's go and look what | |
11:54 | I want to do this . I think I want | |
11:56 | to do it on the next board over here . | |
11:58 | All right . What I want to get the same | |
12:00 | , get across to you is this is the same | |
12:04 | as what you've already learned before . Why is equal | |
12:07 | to M X plus B ? However we're saying that | |
12:12 | B is equal to zero , the y intercept is | |
12:13 | equal to zero . Why is that the case ? | |
12:15 | Let's just take a look at an example . Let | |
12:17 | me draw a little graph here , right ? Um | |
12:21 | This is X . And this is uh why now | |
12:25 | here I've given examples of what I could use here | |
12:28 | . Force I could use circumference and diameter , I | |
12:30 | can use potential energy or whatever . But I'm gonna | |
12:32 | give you an example that I think even easier to | |
12:34 | understand , imagine that you're swimming in a pool , | |
12:37 | you jump under the water and you start to swim | |
12:40 | down under the surface of the water . You immediately | |
12:43 | start feeling pressure on your ear when you're near the | |
12:46 | surface , like right under the surface . You don't | |
12:48 | feel much , You could say the pressure is really | |
12:50 | zero , right at the surface , but if you | |
12:52 | go one m down you feel quite a bit of | |
12:55 | pressure pushing on you . And if you go 10 | |
12:58 | m down you're gonna it's gonna be very very painful | |
13:02 | . And if you go really really really really far | |
13:03 | down you can actually get hurt by swimming so deep | |
13:06 | down because the pressure of the water is pushing on | |
13:08 | you . So you see as you go deeper , | |
13:10 | deeper , deeper , deeper deeper the pressure goes up | |
13:13 | up up up up so five m below the surface | |
13:15 | means more pressure . 10 m below the surface means | |
13:18 | more pressure . But right at the surface there's really | |
13:21 | no pressure at all . So you can kind of | |
13:24 | imagine this being a line , right ? That goes | |
13:27 | through the origin here . Something like this , A | |
13:30 | straight line . I know it's not perfect , but | |
13:32 | that's my best guess at a straight line and here | |
13:35 | on the X axis , I'm gonna call this the | |
13:37 | dive depth in meters right ? So this is going | |
13:43 | deeper and deeper and deeper under the water . And | |
13:45 | as that happens this is the water pressure . And | |
13:52 | it goes of course up here . So you see | |
13:54 | as the dive depth goes deeper , deeper , deeper | |
13:57 | , more and more meters under the water then the | |
13:59 | pressure gets more and more and more and more . | |
14:01 | And that's why this thing looks like a line . | |
14:02 | Right ? So you can see that this direct variation | |
14:06 | , it looks like a line with B is equal | |
14:08 | to zero . And that's an exact in words this | |
14:11 | in terms of a graph , that's exactly what we're | |
14:13 | seeing here . We have a direct variation . It | |
14:15 | is a line that goes through the origin here . | |
14:18 | Why does it go through the origin ? Well it's | |
14:20 | because when you're at the surface and the depth of | |
14:23 | zero there's no pressure , the pressure zero . So | |
14:26 | these direct variation problems go through the origin because at | |
14:30 | zero there's no there's no there's no change in the | |
14:34 | other variable . It's the same thing here with the | |
14:36 | circle . If I have zero diameter , my circumference | |
14:38 | is zero . So it goes through the origin . | |
14:40 | If I have zero acceleration , my force must have | |
14:43 | been zero . The things not even moving at all | |
14:45 | . If I'm zero m above the ground , I | |
14:47 | have no energy at all . All of these things | |
14:49 | go through zero when the variable is set to zero | |
14:52 | . And so the same thing here with the pressure | |
14:53 | here . Now you can imagine there being two points | |
14:58 | on this line here . In fact there's an infinite | |
15:01 | number of points . I can go one m 2 | |
15:03 | m three m and so on . But let me | |
15:05 | just pick a random point right here and I'll pick | |
15:07 | another random point right there , right ? This point | |
15:10 | is that X one comma Y one . It could | |
15:13 | be like five m down and like three uh atmospheres | |
15:17 | of pressure or whatever . I have to give you | |
15:18 | the units of pressure . I don't want to get | |
15:20 | into units of pressure right now . But this could | |
15:22 | be however many meters down and whatever the pressure is | |
15:25 | kind of reading off the graph here and then this | |
15:27 | is X two more meters down . In other words | |
15:30 | , and I have some higher value of the pressure | |
15:33 | . Y two . I would just read it right | |
15:34 | off of the graph all right now , because this | |
15:38 | is a line that goes through the origin , that | |
15:40 | means the Y intercept is zero . So it's Y | |
15:43 | equals mx plus B but B a zero , right | |
15:45 | ? Because it goes through the origin like this , | |
15:47 | then all of the points on this line , you | |
15:50 | know , you can calculate the slope of any line | |
15:52 | by looking at any two points and the slope of | |
15:55 | the line never changes . So no matter what points | |
15:57 | I pick anywhere on this line , I'm gonna get | |
15:59 | the same slope because the slope never ever changes for | |
16:03 | a line . Right ? So what I want to | |
16:06 | do is I want to say , let me calculate | |
16:08 | the slope of kind of this line segment between this | |
16:11 | this guy in zero here . So what would be | |
16:13 | the slope of this line ? The constant variation is | |
16:16 | what I'm trying to calculate . I'm trying to show | |
16:18 | you here , what is the slope of the line | |
16:19 | ? Well , it's y tu minus 11 divided by | |
16:23 | X two minus x one . So what I have | |
16:24 | here is this y value here is why one minus | |
16:28 | zero . I'm going to use these two points . | |
16:30 | So here is zero comma zero and here's X . | |
16:33 | One comma Y one . So it's the subtraction of | |
16:35 | the Y values . Uh The subtraction of the X | |
16:38 | values X . Is X . One and then zero | |
16:40 | right here . So what do I get if I | |
16:42 | calculate the slope there is just Y one over X | |
16:46 | . One , that's going to be what it is | |
16:47 | . So the slope of the line , in other | |
16:49 | words is just the ratio of Y two X . | |
16:52 | That's all it is . Now let's calculate the slope | |
16:56 | using this point and let's let's go calculated between this | |
16:59 | point and also zero . Right ? Because we know | |
17:02 | the slope is gonna be the same everywhere . Right | |
17:04 | ? So let's calculate the slope there . It's gonna | |
17:07 | be y two minus at this point which is the | |
17:10 | Y . Value is zero and then X two minus | |
17:13 | the X point here is zero . So what do | |
17:15 | I get if I calculate the slope there ? Why | |
17:17 | two divided by X two . So you see what's | |
17:21 | interesting is we know it's a line , but if | |
17:23 | I use this point in the origin , I have | |
17:26 | two points . I get a slope . Here's what | |
17:27 | it is . If I use this point and calculate | |
17:31 | the slope of the origin , I get this . | |
17:33 | So the slope here is equal to this . The | |
17:36 | slope calculated over here is equal to this . But | |
17:38 | we know that these slopes have to be the same | |
17:40 | thing . They are because the slope of the line | |
17:43 | is always the same . It never changes no matter | |
17:45 | what points you use to figure out the slope . | |
17:48 | So why am I doing all this ? Because I | |
17:50 | can set these things equal to one another . Set | |
17:54 | equal and what you get out of that is something | |
17:58 | you will see in your textbook and that's the following | |
18:00 | why one over X one . We know it's equal | |
18:03 | to end , but that's also equal to this . | |
18:05 | So that's going to be equal to Y two over | |
18:08 | X two . So this is useful to solve direct | |
18:16 | variation . That's devi direct variation problems . So what | |
18:21 | I could have done is I could have said , | |
18:23 | hey guys , this thing is called direct variation . | |
18:25 | This is what the equation is . I could have | |
18:27 | not even given you any examples at all . I | |
18:29 | could have not even drawn this thing on the board | |
18:31 | . And I could have said , this is what | |
18:32 | you do here . It's with any two points , | |
18:34 | it's Y over X . Y two over X and | |
18:37 | then go for and solve your problems . But you | |
18:39 | would have no idea . How did he know this | |
18:40 | was the case ? Well , how could he do | |
18:42 | that ? All this is telling you , is that | |
18:45 | the points X one and Y . One and X | |
18:48 | . Two and Y to their related to one another | |
18:51 | . Specifically the ratio of the Y values that to | |
18:54 | the X . Value at one point is equal to | |
18:56 | the ratio of the Y . Value to the X | |
18:58 | . Value at the other point . And the reason | |
19:00 | that's the case is because of the slope of the | |
19:02 | line is calculated using those points and because the line | |
19:05 | always goes through the origin for direct variation , problems | |
19:08 | like this . Okay , so we can say that | |
19:11 | why here is directly proportional to X . And you | |
19:15 | can use this in here as the constant of proportionality | |
19:18 | or the constant variation . Mhm . Both terms are | |
19:22 | used now . That's enough I think theory , right | |
19:26 | . I've tried to illustrate what a direct variation is | |
19:28 | and all that but we really need to do a | |
19:29 | problem or two for you to understand how to do | |
19:32 | these things and they're not hard . So , problem | |
19:34 | number one says something like this . If why varies | |
19:41 | directly , you have to have that word directly as | |
19:45 | X . If why varies directly as X . And | |
19:50 | Why is equal to six when X is equal to | |
19:55 | 15 ? Find no why when X is equal to | |
20:03 | 25 . So this looks really difficult at first because | |
20:06 | there's a lot of weird wording in it . Why | |
20:08 | varies directly as X . And then you're given a | |
20:10 | Y value and then you're given two X values . | |
20:12 | And a lot of times students will look at it | |
20:14 | and they'll all get jumbled and they won't have any | |
20:16 | idea like what do I multiply these do ? I | |
20:18 | divide these ? And then usually you'll start jumping back | |
20:21 | and getting this and start putting things in . But | |
20:23 | you won't really know because you really didn't know where | |
20:25 | the formula came from , you don't really know what | |
20:27 | to do . So what we're gonna do is we | |
20:30 | are going to translate this . First of all you | |
20:32 | look and you say why varies directly as X . | |
20:35 | That means that it has to be of the form | |
20:38 | . Um It has to be of the form . | |
20:41 | Why is equal to some constant variation times X . | |
20:44 | That's what the word directly is later on when we | |
20:47 | learn about inverse variation . If it were to say | |
20:49 | inversely , if it varies inversely , then the equation | |
20:52 | is completely different . So that word tells you it's | |
20:54 | direct variation problem . Right ? And the other parts | |
20:58 | of it is just telling you that why is 61 | |
21:02 | X . Is 15 . So the easiest way to | |
21:04 | do this is to draw a little sketch . So | |
21:06 | let's draw a little xy graph . And it's telling | |
21:09 | us that why is 61 X . Is equal to | |
21:11 | 15 ? So I don't know , I don't have | |
21:14 | any scale here . I don't need to put tick | |
21:15 | marks , I don't need to be exact . But | |
21:17 | what I want to do is I'm just gonna put | |
21:18 | a point , maybe I'll do it more like this | |
21:23 | like this . So what I know is that let's | |
21:27 | see when X is . Let me do it like | |
21:29 | this over here over here , X is equal to | |
21:33 | 15 . Why is equal to six ? So this | |
21:35 | point right here is 15 comma six , right ? | |
21:39 | That's all I know . It's telling me that when | |
21:41 | why is equal to 61 X is equal to 15 | |
21:44 | . But it's asking me to find why when X | |
21:46 | is 25 . Now , if this is 15 and | |
21:48 | 25 is somewhere over here , I don't know exactly | |
21:50 | where but I know that this has to be a | |
21:52 | line . So I can draw through this point and | |
21:55 | through the origin of this straight line and that tells | |
21:58 | me right there at this point here must be up | |
22:01 | here At X . is equal to 25 . And | |
22:04 | why is equal to something ? I don't know what | |
22:06 | it is . I can put I can put why | |
22:09 | there I guess . But I think it's better to | |
22:11 | put a question mark . Let's put a question mark | |
22:12 | right there . So here's the translation of what the | |
22:15 | problem is telling you . It's basically telling you another | |
22:17 | way I could have done it is I could have | |
22:18 | said you have a line going through the origin . | |
22:20 | One point on the line is 15 comma six . | |
22:23 | The other point on the line is 25 comma something | |
22:26 | . Find the value of why that goes with 25 | |
22:29 | . That's all you have to do . Right ? | |
22:31 | So you don't have to make it more complicated than | |
22:33 | it is . So there's there's two ways to do | |
22:35 | it . I'm gonna call , I'm gonna do both | |
22:37 | ways for your method . What you know this thing | |
22:41 | is direct variation . So you know that y . | |
22:43 | Is equal to mx if you know what M . | |
22:48 | Is , then all I would have to do is | |
22:49 | put the 25 for X . In . Multiply by | |
22:51 | the M . And I would get the value of | |
22:53 | Y out but I don't know what M . Is | |
22:55 | . However , I can find what M . Is | |
22:58 | because I have another point on the line . And | |
23:00 | I also know that all of these things go through | |
23:02 | zero comma zero . So I can find the slope | |
23:06 | of this thing by saying that uh it's going to | |
23:10 | basically be y tu minus Y one over X two | |
23:15 | minus x one . And I'm gonna use this point | |
23:17 | in the zero point to figure it out . So | |
23:19 | six is the Y value six minus zero . Because | |
23:22 | I'm going to this point here and then 15 minus | |
23:26 | zero . So it's six divided by 15 . 6/15 | |
23:30 | . And when you simplify that I can divide the | |
23:32 | top by three . And that's gonna give me to | |
23:34 | divide the bottom by three and that's gonna give me | |
23:35 | five . So now I know that the slope is | |
23:37 | 2/5 . I didn't know that when the problem started | |
23:40 | but now I know that this direct variation form looks | |
23:44 | like this . In other words , this line is | |
23:48 | 2/5 X . So think about mx plus B . | |
23:51 | Right ? If I told you graph 2/5 X plus | |
23:54 | B , you would say why intercept is zero and | |
23:57 | the slope is to over five so rise over run | |
23:59 | , that's what's happening . And these points both go | |
24:02 | through this line . But now that I know what | |
24:05 | the line is , I'll just take the x value | |
24:07 | of 25 and stick it in here . So why | |
24:10 | is 2/5 times 25 Right now ? Of course I | |
24:15 | have . Let me mark it up separately to 5th | |
24:19 | 25 . I can say I defy divided by five | |
24:24 | is 1 , 25 by five is five . So | |
24:27 | what I really have is two times five . And | |
24:29 | so what I'm going to have is why is equal | |
24:32 | to 10 . So the question says , find the | |
24:35 | value of why when X is 25 . So what | |
24:38 | you have to do is use the other point , | |
24:40 | they give you to find the slope . You always | |
24:42 | have to know for direct variation . That it always | |
24:45 | goes through zero comma zero through the origin . That's | |
24:48 | what allowed us to find the slope . Once we | |
24:51 | know the slope we know direct variation always looks like | |
24:54 | this . Why is equal to some constant variation times | |
24:57 | X . Once we know that we put in the | |
24:59 | other point and calculate the corresponding value of Why ? | |
25:03 | Now that's the way I like to do it because | |
25:06 | that makes sense to me . But a lot of | |
25:08 | students , uh a lot of teachers try to push | |
25:11 | the formulas that come out of the book . So | |
25:13 | notice what we did is we we found what this | |
25:16 | relationship was by looking at two points on the line | |
25:19 | . We know it also goes through zero finding a | |
25:21 | slope from one point down to zero and the other | |
25:23 | point down to zero , setting people equal . And | |
25:25 | we know this relationship is valid why one over X | |
25:29 | . One , Y two over X . Two . | |
25:32 | So I'm gonna do it that way for you , | |
25:34 | but I'm gonna show you that you're gonna get the | |
25:37 | same thing . So what we get is why um | |
25:40 | you just double check myself why one over X . | |
25:42 | One Y . Two over X . Two . So | |
25:47 | what you give here is you go back to the | |
25:50 | problem statement , you gotta find the pairs of variables | |
25:53 | that go together . So we know that . Why | |
25:55 | is 61 X . Is 15 those go together . | |
25:58 | So why is 61 X . Is 15 ? That | |
26:01 | corresponds to this one here , The other one here | |
26:04 | we're trying to find the value of Y when X | |
26:07 | . Is 25 . So we'll call it why 20/25 | |
26:10 | . So you see what happens , you just fill | |
26:12 | in the blanks here and this is what a lot | |
26:13 | of teachers try to do and it works . It's | |
26:16 | just you don't often know what you're doing , you're | |
26:17 | just plugging stuff and I don't really like that too | |
26:19 | much . But how would you solve this ? Um | |
26:22 | well you multiply both sides by 25 to get why | |
26:24 | by itself . So what you would have is why | |
26:28 | would be 25 Times 6/15 ? Right ? Um You | |
26:37 | have 25 times 6/15 . All I've done is multiply | |
26:40 | 25 on both sides . Now , let's simplify those | |
26:43 | . Uh Let's simplify it by I'm trying to think | |
26:46 | of the best way to do it , let's do | |
26:47 | it this way . Let's leave the 25 alone for | |
26:49 | now . And the 6/15 , I'm gonna simplify this | |
26:52 | fraction divided by two is gonna give me I'm sorry | |
26:55 | , divide by three is gonna give me two divided | |
26:56 | by three , is gonna give me five . Right | |
26:59 | ? But then I see right here , let me | |
27:01 | go in . Right , one more time . 25 | |
27:03 | times 2/5 5555 is 1 , 25 divided by five | |
27:07 | is five . And so I end up with five | |
27:09 | times two , which gives me 10 . That's exactly | |
27:11 | the same thing I got here . But I want | |
27:13 | you to really understand what you've done here by using | |
27:16 | this formula is exactly the same math that we did | |
27:18 | with Method one , which I actually think makes more | |
27:21 | sense finding the slope of the line and then using | |
27:23 | that to solve the thing . Because when you plug | |
27:26 | all the values in here , notice what you're done | |
27:28 | . You're basically saying 6/15 times 25 . But notice | |
27:32 | what we did over here . We did 2/5 times | |
27:34 | 25 . But the 6/15 actually is 2/5 times 25 | |
27:39 | . So all we did in the first way was | |
27:41 | find the slope , simplify it and then put it | |
27:43 | in , multiplied by 25 got the answer here , | |
27:46 | we put it into our equation . We end up | |
27:47 | with exactly the same math 25 times here . This | |
27:51 | is 2/5 when you simplify . So you actually get | |
27:53 | the exactly the same answer . I prefer using method | |
27:56 | one because it makes more sense and it leads to | |
27:59 | less errors when you know what you're doing . All | |
28:01 | right , So we have one more here . I | |
28:03 | want to do with you uh with direct variation and | |
28:06 | it's gonna be a similar format . Most of these | |
28:08 | are all the same . And it goes like this | |
28:10 | if P is directly proportional to the variable Q . | |
28:24 | And uh P is equal to nine , that is | |
28:29 | not a Q . That's a nine P is equal | |
28:31 | to nine win Q . It's a bad looking Q | |
28:36 | . Sorry , seven point when Q is equal to | |
28:37 | 75 find Q when P is equal to 24 . | |
28:46 | So again you've got lots of numbers mixed together and | |
28:48 | all this other kind of stuff . So we're not | |
28:49 | going to draw a picture this time . But I | |
28:52 | do want you to keep in mind the picture that | |
28:54 | we use in the last lesson . There is a | |
28:56 | line , it's a direct variation line , it goes | |
28:58 | through the origin and we have two points on the | |
29:00 | line . I'm given one of the points on the | |
29:02 | problem completely . The other point I've only given I've | |
29:04 | only been given part of that's what you have to | |
29:07 | keep in the back of your mind , that's what | |
29:09 | you're really doing . So I know that this is | |
29:11 | a direct direct variation between P and Q . It | |
29:13 | says P is directly proportional to queue . So I | |
29:16 | then know right away that P is equal to directly | |
29:18 | proportional two Q . Some constant variation times Q . | |
29:23 | Right ? Um And it's asking me find Q . | |
29:28 | When P is equal to 24 right ? Um And | |
29:32 | it's also telling me that P . Is equal to | |
29:35 | nine when Q . Is equal to 75 . So | |
29:37 | if I knew what M . Was , if I | |
29:39 | knew what M . Was , all I would have | |
29:41 | to do is put the P value in here , | |
29:44 | I would know the M . Value and I would | |
29:45 | find the Q . Value . But the problem is | |
29:47 | I don't know what he is , but they give | |
29:49 | me another point on the line . I know That | |
29:52 | P is nine when Q . is seven .5 . | |
29:54 | So I can put in nine , that's not a | |
29:57 | Q . That's a nine in times the Q . | |
30:00 | Which is 75 And from this I just calculate the | |
30:02 | slope , I could have calculated the slope , You | |
30:05 | know uh separately differently like I did back before over | |
30:09 | here , of course I can calculate the slope between | |
30:12 | this point and the origin . I'm showing you kind | |
30:13 | of an alternative way of doing it when you know | |
30:16 | one point on this line and you know the equation | |
30:18 | on the line here , I can just put the | |
30:19 | two values and nine and 7.5 . And then when | |
30:22 | I'm gonna get is nine divided by 7.5 . And | |
30:24 | so the value of the slope is going to be | |
30:28 | one too for the slope . And then once I | |
30:32 | know the slope , I know that they are directly | |
30:34 | proportional or they very directly with respect to one another | |
30:38 | . So I know that P is equal to MQ | |
30:41 | . But I now know what the slope is . | |
30:44 | It's 1.2 times Q . So now I have the | |
30:46 | equation . It would be very simple if I gave | |
30:48 | you this line and I said , hey find Q | |
30:50 | . When P is 24 you would know that how | |
30:53 | to do that . But we had to find the | |
30:54 | slope first . So then we put a P . | |
30:57 | Of 24 in 1.2 times cute . And then Q | |
31:02 | . is 24 divided by one point , sorry 1.2 | |
31:08 | . And so then Q . When you take 24-5 | |
31:11 | x 1.2 you get 20 . Yes . So if | |
31:14 | we were to draw this line through the origin , | |
31:17 | we would see that the 0.9 comma 7.5 was on | |
31:22 | the line and we would also see that become a | |
31:24 | QP being 24 And Q being 20 would also be | |
31:29 | on the line . This pair points would also be | |
31:31 | on the line because we calculated the value of this | |
31:33 | point using this line . Now just for giggles , | |
31:37 | we're going to go back and do the other do | |
31:38 | it the other way in case you want to use | |
31:41 | the equation given in the book . And that's that | |
31:43 | if you have two points very directly , why one | |
31:46 | over X one is Y . Two is equal to | |
31:49 | Y . Two over X . Two . Now the | |
31:52 | pair of points I'm given uh in this case actually | |
31:55 | why why an X . Are really not in the | |
31:57 | problem statement . So it's going to be useful for | |
31:59 | you to say instead of that say Q one , | |
32:01 | P . One . Q two . P . Two | |
32:06 | . Right ? And what are what are Q 1 | |
32:09 | ? Q 2 ? So we know that uh P | |
32:13 | . is nine when Q is 7.5 . So what | |
32:15 | we can say is we can say 7.5 is Q1 | |
32:21 | , P . Is nine because these points go together | |
32:24 | and then the other Q . Is what I'm trying | |
32:26 | to find . So I'm gonna leave it as Q | |
32:28 | . Two . And that p when that happens is | |
32:30 | 24 . So all I've done is put all these | |
32:32 | values in . Look what I'm going to get . | |
32:33 | Q . two is equal to this fraction . I'm | |
32:36 | gonna multiply by the 24 . So I'm gonna say | |
32:38 | 24 times 7.5 over What's not over Q . over | |
32:43 | nine like this . And when you go in your | |
32:46 | calculator type 24 times 7.5 divided by nine . What | |
32:50 | you're gonna get is Q two is equal to 20 | |
32:55 | Which is exactly what you get now . Why do | |
32:57 | you think it's the same thing ? Look at the | |
32:58 | math you actually did when you plugged it all in | |
33:00 | and you got it you took 24 and you multiply | |
33:02 | by a fraction . The fraction was 7.5 over nine | |
33:06 | . Look what we did here and you can see | |
33:08 | that that's basically what you were doing before . We | |
33:10 | calculated Cube by taking 24 and divided by 1.2 . | |
33:13 | But the 1.2 was the slope which was a fraction | |
33:16 | . So you can kind of think of this fraction | |
33:17 | being on the bottom , you flip it over , | |
33:19 | it's gonna be 24 times 7.5 divided by nine , | |
33:22 | which is exactly what we got there . I'm not | |
33:24 | trying to throw a bunch of different ways that you | |
33:26 | to do things to confuse you . I'm trying to | |
33:28 | show you that there's always more than one way to | |
33:30 | get the answer to a problem . Personally I like | |
33:33 | the more logical way of doing it . I don't | |
33:35 | like grabbing a formula out of a book and throwing | |
33:37 | it in there . All I need to know is | |
33:39 | that these things very directly Soapy has got to be | |
33:41 | equal to m times Q . I'm given to one | |
33:44 | point on the line in its entirety which lets me | |
33:46 | find the slope . Once I know the slope I | |
33:49 | can then put it in for the value of the | |
33:50 | slope and then I can use this equation of the | |
33:52 | line to find any other point I want . In | |
33:54 | this case I was given the p value here , | |
33:56 | so then I go backwards and find the Q value | |
33:59 | . Um not rocket science but extremely important because direct | |
34:03 | variation pops up everywhere . As I said , potential | |
34:08 | energy and physics , force and acceleration , even geometry | |
34:11 | and I could go on , I can have a | |
34:12 | whole lesson in direct variation . So for now just | |
34:15 | make sure you solve these problems yourself and you understand | |
34:17 | them . Then follow me on to the next lesson | |
34:19 | . We'll get a little more practice with direct variation | |
34:21 | before moving into kind of the opposite of that , | |
34:23 | which we call inverse variation in algebra . |
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