01 - Direct Variation and Proportion in Algebra - Part 1 (Constant of Variation & More) - Free Educational videos for Students in K-12 | Lumos Learning

01 - Direct Variation and Proportion in Algebra - Part 1 (Constant of Variation & More) - Free Educational videos for Students in k-12


01 - Direct Variation and Proportion in Algebra - Part 1 (Constant of Variation & More) - By Math and Science



Transcript
00:01 Hello . Welcome back to algebra . The title of
00:02 this lesson is direct variation and proportion . This is
00:06 part one of two lessons . So we're talking about
00:09 in this case the concept of direct variation . Now
00:12 this is going to be in contrast , a couple
00:14 of lessons down the road , we're gonna talk about
00:16 inverse variation . So in the back of your mind
00:18 , when we talk about direct variation , just keep
00:20 in mind that we also have kind of a cousin
00:23 of this which is called inverse variation , which will
00:25 they will kind of go hand in hand together .
00:27 But in this case we're gonna be talking about direct
00:29 variation in a nutshell , when you have two variables
00:33 that are related to one another , right ? Then
00:36 oftentimes we say that they vary directly with respect to
00:40 one another . And what direct variation means in this
00:42 case , when you have two variables that have a
00:44 direct variation relationship between them all , it means is
00:48 very simple to understand is that when you increase one
00:51 of the variables , the other variable also increases ,
00:54 so they increase in direct correspondence to one another .
00:57 Right ? Alternatively , if one variable goes down then
01:00 the kind of like the partner variable goes down with
01:03 it . So when you have two variables that both
01:06 go up together or both go down together , we
01:08 call it direct variation and we're gonna find out in
01:11 several lessons down the road . The inverse variation is
01:14 when one variable might go up while that would cause
01:17 the other variable to go down so they go opposite
01:19 of each other . That's what we call inverse variation
01:21 . So in math terms we want to talk about
01:23 when we talk about direct variation is the following thing
01:27 . And let me tell you right now , it's
01:28 very easy to understand because we've learned so much about
01:31 lines and you're going to see in a second that
01:33 this is all related to the equation of a line
01:35 . So , direct variation . And the other thing
01:38 I'll say before we get started is we talk about
01:41 direct variation so much in algebra , because there are
01:44 many , many equations in physics and chemistry and engineering
01:48 that have a direct variation relationship . So I'm gonna
01:51 actually show you some of them in just a second
01:53 . But just keep in mind that this is actually
01:54 useful because a lot of the physical laws we have
01:57 in the universe actually obey a direct variation kind of
02:00 kind of relationship . So what does direct variation means
02:03 ? It means we have two variables . I'm gonna
02:05 call one of them X and I'm going to call
02:07 the other one why ? And their related to one
02:09 another , right ? There's lots of lots of variables
02:12 and I'll give you examples in a second that are
02:14 related to one another . So a direct variation means
02:16 that as the variable X increases , that's what the
02:19 up arrow means . If it goes up up up
02:21 up up up up then a direct variation means that's
02:25 what this this little arrow means . It means as
02:27 X goes up , it means that the variable Y
02:29 also goes up now , it does not mean that
02:33 X and Y have to go up at the exact
02:35 same rate . Okay ? You could have X going
02:37 up really , really fast and you could have why
02:39 going up in a slower fashion or you could have
02:42 X going up really , really slow and why going
02:44 up even faster ? A faster variation . So they
02:48 don't have to go at the same speed up ,
02:50 but they both have to go the same direction .
02:52 So what it means is that as X goes up
02:54 why must also go up ? All right . And
02:57 in the case of inverse variation , we'll talk about
02:59 later as X goes up , the variable Y goes
03:01 down in the opposite way . So , um what
03:05 this means is that when you when you boil it
03:08 down and start graphing pairs of X and Y points
03:10 and you see that as X goes up implies that
03:12 why goes up , then what it basically means is
03:15 the variable Y is equal to some number M .
03:19 Which we're using a letter in because it's going to
03:21 end up being the slope of the line times X
03:24 . So you might look at this and say wait
03:26 a minute , doesn't this look familiar ? Y equals
03:28 mx Because we talked about lines a whole lot mx
03:31 plus B , right , M was the slope of
03:33 the line and B is the Y intercept . So
03:37 when we talk about direct variation , literally , it
03:40 is the exact same stuff that we learned and we
03:42 talk about the equation of a line . But uh
03:45 the Y intercept B is always set equal to zero
03:49 and you'll see why in just a second . But
03:51 what this means is that X go up , Why
03:53 goes up in in terms of this relationship , notice
03:57 how the equation is set up , even if M
03:59 was no matter what M . Is , let's say
04:01 M . Is equal to to let the slope of
04:03 this uh line here as X goes up . If
04:07 you make X one and two and three and four
04:09 , when you multiply by M , then why must
04:11 also go up ? So this is the form of
04:13 a direct variation . And we say in words that
04:17 why varies directly as X . And what this wording
04:26 means is when X goes up , why goes up
04:29 , that's what it means . And this is what
04:30 the equation tells you , even if M . Is
04:31 one half . Uh If X increases from 1 to
04:35 2 to three of the four , then why must
04:38 also be increased by whatever the numbers are . You
04:41 just multiply what M . Is and you're gonna get
04:43 larger and larger values of why ? Now we have
04:45 a special name for this . By the way .
04:48 You might also see this in your textbook . You
04:51 might see this , I'll do this , you might
04:54 see uh why is equal to K . X .
04:57 So some books don't use the letter M . They
05:00 use the letter K . This uh variables , this
05:03 uh entity , him the M . Here . Or
05:06 if you see it in a book as K .
05:07 Whatever you label it there , that thing uh In
05:10 this case I'm using them . So I'm gonna say
05:12 M . Is equal to the constant of variation .
05:21 So M . Can be whatever you want it to
05:22 be , depending on the problem or depending on the
05:24 equation that you're looking at . But this thing M
05:26 . Is equal to a constant is called a constant
05:29 variation . So if M were equal to one for
05:32 instance , then you just have one here . Then
05:35 as X goes up 1234 then you multiply by one
05:38 . Why would be going up 1234 ? But if
05:40 M were to , let's say then every time I
05:43 increase X and I'm multiplying by two . So you
05:46 see why is actually would be increasing faster than X
05:49 . Because if M is one , I multiplied by
05:52 two . I'll give me too . If if X
05:55 is too , I multiplied by two , I would
05:56 get four . If X would be three , I
05:58 multiplied by two , I get six . So you
06:00 see the constant variation determines the exact relationship between X
06:05 and Y . But in all cases when X goes
06:08 up , why must go up ? But the constant
06:10 variation determines how fast why goes up when I increase
06:14 X , how much faster is why increasing ? Remember
06:17 I told you why can be going up faster than
06:19 X ? Or why can be going up slower than
06:22 X . But they must be going in the same
06:23 direction and what determines how fast they move with respect
06:26 to one another is called the constant variation . Now
06:29 you might see this as K . So , in
06:31 your textbook you might see K is the constant variation
06:34 . So you might see or K little bit lower
06:37 case . K would be the constant variation . All
06:40 right . So , we've done a little bit of
06:41 theory here , and it's a little bit abstract .
06:43 So , I want to talk to you about some
06:44 real examples of direct variation . So , examples .
06:50 And these are examples that you all know Right ?
06:52 I like giving examples that you all know . So
06:54 let's take a famous example . What about this equation
06:57 ? Do you recognize this ? Whoops . C is
07:00 equal to pi times deep . I think you recognize
07:04 that from fifth grade right ? The circumference of the
07:06 circle is equal to pi times the diameter of the
07:10 circle . So notice the way this thing is set
07:12 up . It isn't exactly the same form as this
07:15 equation . Have a variable equal to a constant notice
07:19 it's a constant , this is not a variable .
07:21 It's a constant variation means it's just a number ,
07:24 Pi is just a numbers 3.14159 it goes on and
07:27 on with non repeating decimals and then time some other
07:31 variable . So notice that as the diameter of the
07:33 circle increases you make the circle larger , you multiply
07:37 by pi . The circumference also gets larger . So
07:39 as the diameter increases , the circumference also increases ,
07:43 which is exactly what we said . The relationship has
07:45 to be here . Pie , Is that special number
07:49 that governs how much the circumference increases when the diameter
07:53 also increases ? It's the constant variation . You might
07:56 also see it as something called the constant of proportionality
07:59 . So this the title of this lesson is direct
08:01 variation in proportion . So this is a direct variation
08:04 relationship . But you can see that the reason we
08:07 use the word proportional is that the diameter of the
08:09 circle and its circumference are proportional to one another .
08:12 And proportion just means that as one goes up then
08:15 the other variable goes up as well . The constant
08:17 of proportionality are also called . The constant variation just
08:20 determines how much that other variable goes up . All
08:25 right , What are some other examples ? This one
08:27 you might or might not know , but it's one
08:29 of the most famous equations in all of physics .
08:31 F is equal to M . A . So this
08:34 is force is equal to mass times acceleration . This
08:38 means if I take a baseball or anything with some
08:42 mass , the mass of the ball is constant ,
08:44 right ? It's just a fixed thing . The mass
08:46 of the ball doesn't change . So even though it
08:48 looks like a variable here , the mass is really
08:50 the constant of variation here , and you can see
08:53 that the acceleration in the force on that ball have
08:55 to be there related directly as the acceleration on the
08:58 ball goes up . In other words , I have
09:00 to throw the ball with some force in order to
09:02 accelerate , I have to push the ball with some
09:05 uh some force in order to get it to accelerate
09:07 to go faster and faster . But you can see
09:10 that as the acceleration is bigger , bigger , bigger
09:12 , bigger , bigger . The force applied to the
09:14 ball must also be bigger , bigger , bigger ,
09:15 bigger , bigger . And the mass is that special
09:18 quantity that governs how how the force and the acceleration
09:23 are linked . Because you all know that if you
09:25 have a bowling ball it's much harder to accelerate a
09:28 bowling ball with the same force , right ? If
09:30 I apply the same force to a ping pong ball
09:34 and a bowling ball , same force , the acceleration
09:37 will be different . We call it inertia , right
09:38 . Things are harder to push harder to get going
09:41 . So the masses , that thing that governs and
09:43 links the force and the acceleration together . It's the
09:46 constant of variation . So you can see as acceleration
09:48 goes up , mass goes up . What's one more
09:52 ? We'll talk in physics , we'll talk about something
09:54 called the potential energy of something . The potential energy
09:57 is equal to M . Times G . Times H
10:00 . So this is a fancy sounding thing but it's
10:02 it's not fancy . What it basically means is the
10:05 energy when you the potential energy when you hold something
10:08 above the ground is equal to the mass of the
10:11 thing . Like a bowling ball times G , which
10:13 is the gravity on Earth 9.8 m per second .
10:16 It's a gravitational acceleration 9.8 m per second squared times
10:21 the height above the ground . The height above the
10:22 ground is the most important thing . As I raise
10:25 the thing higher above the ground , we say has
10:26 more potential energy . If you climb to the top
10:29 of a building , you have a lot more potential
10:31 energy than if you're on a step ladder . If
10:34 I jump off the step ladder , it's not gonna
10:35 be a problem . But if I jump off the
10:37 building , that potential energy makes you go split into
10:41 the ground . So you have a lot more potential
10:42 energy , the higher you are . So you see
10:44 , the higher you go above the ground , the
10:46 more energy you have . And these are directly related
10:49 . Now , you might say , well , wait
10:50 a minute . There's two things listed here and here
10:53 . I only had one constant variation . But really
10:55 the mass of the ball is never changes and the
10:59 and the acceleration of earth never changes . So ,
11:02 these things multiplied together , they become like one constant
11:05 . These are like , like one constant when you
11:08 multiply there just one number , right ? The mass
11:10 of the ball times gravity is one number . So
11:12 , this is really the constant variation . These two
11:14 things kind of multiplied together , and you can see
11:16 they govern how much energy you get when you go
11:19 higher and higher off the ground . All right .
11:22 So those are some examples of what a direct variation
11:27 is , and that's why I told you in the
11:28 beginning , it's so very important . These are just
11:30 three equations . Um They look so simple , but
11:34 it turns out you can solve a lot of problems
11:36 with these kinds of equations . So this direct variation
11:38 is extremely important . Now let's dive a little bit
11:41 deeper into what direct variation is . It looks like
11:45 the equation of the line . However , the plus
11:49 B is gone . Now let's go and investigate exactly
11:52 why that's the case . Let's go and look what
11:54 I want to do this . I think I want
11:56 to do it on the next board over here .
11:58 All right . What I want to get the same
12:00 , get across to you is this is the same
12:04 as what you've already learned before . Why is equal
12:07 to M X plus B ? However we're saying that
12:12 B is equal to zero , the y intercept is
12:13 equal to zero . Why is that the case ?
12:15 Let's just take a look at an example . Let
12:17 me draw a little graph here , right ? Um
12:21 This is X . And this is uh why now
12:25 here I've given examples of what I could use here
12:28 . Force I could use circumference and diameter , I
12:30 can use potential energy or whatever . But I'm gonna
12:32 give you an example that I think even easier to
12:34 understand , imagine that you're swimming in a pool ,
12:37 you jump under the water and you start to swim
12:40 down under the surface of the water . You immediately
12:43 start feeling pressure on your ear when you're near the
12:46 surface , like right under the surface . You don't
12:48 feel much , You could say the pressure is really
12:50 zero , right at the surface , but if you
12:52 go one m down you feel quite a bit of
12:55 pressure pushing on you . And if you go 10
12:58 m down you're gonna it's gonna be very very painful
13:02 . And if you go really really really really far
13:03 down you can actually get hurt by swimming so deep
13:06 down because the pressure of the water is pushing on
13:08 you . So you see as you go deeper ,
13:10 deeper , deeper , deeper deeper the pressure goes up
13:13 up up up up so five m below the surface
13:15 means more pressure . 10 m below the surface means
13:18 more pressure . But right at the surface there's really
13:21 no pressure at all . So you can kind of
13:24 imagine this being a line , right ? That goes
13:27 through the origin here . Something like this , A
13:30 straight line . I know it's not perfect , but
13:32 that's my best guess at a straight line and here
13:35 on the X axis , I'm gonna call this the
13:37 dive depth in meters right ? So this is going
13:43 deeper and deeper and deeper under the water . And
13:45 as that happens this is the water pressure . And
13:52 it goes of course up here . So you see
13:54 as the dive depth goes deeper , deeper , deeper
13:57 , more and more meters under the water then the
13:59 pressure gets more and more and more and more .
14:01 And that's why this thing looks like a line .
14:02 Right ? So you can see that this direct variation
14:06 , it looks like a line with B is equal
14:08 to zero . And that's an exact in words this
14:11 in terms of a graph , that's exactly what we're
14:13 seeing here . We have a direct variation . It
14:15 is a line that goes through the origin here .
14:18 Why does it go through the origin ? Well it's
14:20 because when you're at the surface and the depth of
14:23 zero there's no pressure , the pressure zero . So
14:26 these direct variation problems go through the origin because at
14:30 zero there's no there's no there's no change in the
14:34 other variable . It's the same thing here with the
14:36 circle . If I have zero diameter , my circumference
14:38 is zero . So it goes through the origin .
14:40 If I have zero acceleration , my force must have
14:43 been zero . The things not even moving at all
14:45 . If I'm zero m above the ground , I
14:47 have no energy at all . All of these things
14:49 go through zero when the variable is set to zero
14:52 . And so the same thing here with the pressure
14:53 here . Now you can imagine there being two points
14:58 on this line here . In fact there's an infinite
15:01 number of points . I can go one m 2
15:03 m three m and so on . But let me
15:05 just pick a random point right here and I'll pick
15:07 another random point right there , right ? This point
15:10 is that X one comma Y one . It could
15:13 be like five m down and like three uh atmospheres
15:17 of pressure or whatever . I have to give you
15:18 the units of pressure . I don't want to get
15:20 into units of pressure right now . But this could
15:22 be however many meters down and whatever the pressure is
15:25 kind of reading off the graph here and then this
15:27 is X two more meters down . In other words
15:30 , and I have some higher value of the pressure
15:33 . Y two . I would just read it right
15:34 off of the graph all right now , because this
15:38 is a line that goes through the origin , that
15:40 means the Y intercept is zero . So it's Y
15:43 equals mx plus B but B a zero , right
15:45 ? Because it goes through the origin like this ,
15:47 then all of the points on this line , you
15:50 know , you can calculate the slope of any line
15:52 by looking at any two points and the slope of
15:55 the line never changes . So no matter what points
15:57 I pick anywhere on this line , I'm gonna get
15:59 the same slope because the slope never ever changes for
16:03 a line . Right ? So what I want to
16:06 do is I want to say , let me calculate
16:08 the slope of kind of this line segment between this
16:11 this guy in zero here . So what would be
16:13 the slope of this line ? The constant variation is
16:16 what I'm trying to calculate . I'm trying to show
16:18 you here , what is the slope of the line
16:19 ? Well , it's y tu minus 11 divided by
16:23 X two minus x one . So what I have
16:24 here is this y value here is why one minus
16:28 zero . I'm going to use these two points .
16:30 So here is zero comma zero and here's X .
16:33 One comma Y one . So it's the subtraction of
16:35 the Y values . Uh The subtraction of the X
16:38 values X . Is X . One and then zero
16:40 right here . So what do I get if I
16:42 calculate the slope there is just Y one over X
16:46 . One , that's going to be what it is
16:47 . So the slope of the line , in other
16:49 words is just the ratio of Y two X .
16:52 That's all it is . Now let's calculate the slope
16:56 using this point and let's let's go calculated between this
16:59 point and also zero . Right ? Because we know
17:02 the slope is gonna be the same everywhere . Right
17:04 ? So let's calculate the slope there . It's gonna
17:07 be y two minus at this point which is the
17:10 Y . Value is zero and then X two minus
17:13 the X point here is zero . So what do
17:15 I get if I calculate the slope there ? Why
17:17 two divided by X two . So you see what's
17:21 interesting is we know it's a line , but if
17:23 I use this point in the origin , I have
17:26 two points . I get a slope . Here's what
17:27 it is . If I use this point and calculate
17:31 the slope of the origin , I get this .
17:33 So the slope here is equal to this . The
17:36 slope calculated over here is equal to this . But
17:38 we know that these slopes have to be the same
17:40 thing . They are because the slope of the line
17:43 is always the same . It never changes no matter
17:45 what points you use to figure out the slope .
17:48 So why am I doing all this ? Because I
17:50 can set these things equal to one another . Set
17:54 equal and what you get out of that is something
17:58 you will see in your textbook and that's the following
18:00 why one over X one . We know it's equal
18:03 to end , but that's also equal to this .
18:05 So that's going to be equal to Y two over
18:08 X two . So this is useful to solve direct
18:16 variation . That's devi direct variation problems . So what
18:21 I could have done is I could have said ,
18:23 hey guys , this thing is called direct variation .
18:25 This is what the equation is . I could have
18:27 not even given you any examples at all . I
18:29 could have not even drawn this thing on the board
18:31 . And I could have said , this is what
18:32 you do here . It's with any two points ,
18:34 it's Y over X . Y two over X and
18:37 then go for and solve your problems . But you
18:39 would have no idea . How did he know this
18:40 was the case ? Well , how could he do
18:42 that ? All this is telling you , is that
18:45 the points X one and Y . One and X
18:48 . Two and Y to their related to one another
18:51 . Specifically the ratio of the Y values that to
18:54 the X . Value at one point is equal to
18:56 the ratio of the Y . Value to the X
18:58 . Value at the other point . And the reason
19:00 that's the case is because of the slope of the
19:02 line is calculated using those points and because the line
19:05 always goes through the origin for direct variation , problems
19:08 like this . Okay , so we can say that
19:11 why here is directly proportional to X . And you
19:15 can use this in here as the constant of proportionality
19:18 or the constant variation . Mhm . Both terms are
19:22 used now . That's enough I think theory , right
19:26 . I've tried to illustrate what a direct variation is
19:28 and all that but we really need to do a
19:29 problem or two for you to understand how to do
19:32 these things and they're not hard . So , problem
19:34 number one says something like this . If why varies
19:41 directly , you have to have that word directly as
19:45 X . If why varies directly as X . And
19:50 Why is equal to six when X is equal to
19:55 15 ? Find no why when X is equal to
20:03 25 . So this looks really difficult at first because
20:06 there's a lot of weird wording in it . Why
20:08 varies directly as X . And then you're given a
20:10 Y value and then you're given two X values .
20:12 And a lot of times students will look at it
20:14 and they'll all get jumbled and they won't have any
20:16 idea like what do I multiply these do ? I
20:18 divide these ? And then usually you'll start jumping back
20:21 and getting this and start putting things in . But
20:23 you won't really know because you really didn't know where
20:25 the formula came from , you don't really know what
20:27 to do . So what we're gonna do is we
20:30 are going to translate this . First of all you
20:32 look and you say why varies directly as X .
20:35 That means that it has to be of the form
20:38 . Um It has to be of the form .
20:41 Why is equal to some constant variation times X .
20:44 That's what the word directly is later on when we
20:47 learn about inverse variation . If it were to say
20:49 inversely , if it varies inversely , then the equation
20:52 is completely different . So that word tells you it's
20:54 direct variation problem . Right ? And the other parts
20:58 of it is just telling you that why is 61
21:02 X . Is 15 . So the easiest way to
21:04 do this is to draw a little sketch . So
21:06 let's draw a little xy graph . And it's telling
21:09 us that why is 61 X . Is equal to
21:11 15 ? So I don't know , I don't have
21:14 any scale here . I don't need to put tick
21:15 marks , I don't need to be exact . But
21:17 what I want to do is I'm just gonna put
21:18 a point , maybe I'll do it more like this
21:23 like this . So what I know is that let's
21:27 see when X is . Let me do it like
21:29 this over here over here , X is equal to
21:33 15 . Why is equal to six ? So this
21:35 point right here is 15 comma six , right ?
21:39 That's all I know . It's telling me that when
21:41 why is equal to 61 X is equal to 15
21:44 . But it's asking me to find why when X
21:46 is 25 . Now , if this is 15 and
21:48 25 is somewhere over here , I don't know exactly
21:50 where but I know that this has to be a
21:52 line . So I can draw through this point and
21:55 through the origin of this straight line and that tells
21:58 me right there at this point here must be up
22:01 here At X . is equal to 25 . And
22:04 why is equal to something ? I don't know what
22:06 it is . I can put I can put why
22:09 there I guess . But I think it's better to
22:11 put a question mark . Let's put a question mark
22:12 right there . So here's the translation of what the
22:15 problem is telling you . It's basically telling you another
22:17 way I could have done it is I could have
22:18 said you have a line going through the origin .
22:20 One point on the line is 15 comma six .
22:23 The other point on the line is 25 comma something
22:26 . Find the value of why that goes with 25
22:29 . That's all you have to do . Right ?
22:31 So you don't have to make it more complicated than
22:33 it is . So there's there's two ways to do
22:35 it . I'm gonna call , I'm gonna do both
22:37 ways for your method . What you know this thing
22:41 is direct variation . So you know that y .
22:43 Is equal to mx if you know what M .
22:48 Is , then all I would have to do is
22:49 put the 25 for X . In . Multiply by
22:51 the M . And I would get the value of
22:53 Y out but I don't know what M . Is
22:55 . However , I can find what M . Is
22:58 because I have another point on the line . And
23:00 I also know that all of these things go through
23:02 zero comma zero . So I can find the slope
23:06 of this thing by saying that uh it's going to
23:10 basically be y tu minus Y one over X two
23:15 minus x one . And I'm gonna use this point
23:17 in the zero point to figure it out . So
23:19 six is the Y value six minus zero . Because
23:22 I'm going to this point here and then 15 minus
23:26 zero . So it's six divided by 15 . 6/15
23:30 . And when you simplify that I can divide the
23:32 top by three . And that's gonna give me to
23:34 divide the bottom by three and that's gonna give me
23:35 five . So now I know that the slope is
23:37 2/5 . I didn't know that when the problem started
23:40 but now I know that this direct variation form looks
23:44 like this . In other words , this line is
23:48 2/5 X . So think about mx plus B .
23:51 Right ? If I told you graph 2/5 X plus
23:54 B , you would say why intercept is zero and
23:57 the slope is to over five so rise over run
23:59 , that's what's happening . And these points both go
24:02 through this line . But now that I know what
24:05 the line is , I'll just take the x value
24:07 of 25 and stick it in here . So why
24:10 is 2/5 times 25 Right now ? Of course I
24:15 have . Let me mark it up separately to 5th
24:19 25 . I can say I defy divided by five
24:24 is 1 , 25 by five is five . So
24:27 what I really have is two times five . And
24:29 so what I'm going to have is why is equal
24:32 to 10 . So the question says , find the
24:35 value of why when X is 25 . So what
24:38 you have to do is use the other point ,
24:40 they give you to find the slope . You always
24:42 have to know for direct variation . That it always
24:45 goes through zero comma zero through the origin . That's
24:48 what allowed us to find the slope . Once we
24:51 know the slope we know direct variation always looks like
24:54 this . Why is equal to some constant variation times
24:57 X . Once we know that we put in the
24:59 other point and calculate the corresponding value of Why ?
25:03 Now that's the way I like to do it because
25:06 that makes sense to me . But a lot of
25:08 students , uh a lot of teachers try to push
25:11 the formulas that come out of the book . So
25:13 notice what we did is we we found what this
25:16 relationship was by looking at two points on the line
25:19 . We know it also goes through zero finding a
25:21 slope from one point down to zero and the other
25:23 point down to zero , setting people equal . And
25:25 we know this relationship is valid why one over X
25:29 . One , Y two over X . Two .
25:32 So I'm gonna do it that way for you ,
25:34 but I'm gonna show you that you're gonna get the
25:37 same thing . So what we get is why um
25:40 you just double check myself why one over X .
25:42 One Y . Two over X . Two . So
25:47 what you give here is you go back to the
25:50 problem statement , you gotta find the pairs of variables
25:53 that go together . So we know that . Why
25:55 is 61 X . Is 15 those go together .
25:58 So why is 61 X . Is 15 ? That
26:01 corresponds to this one here , The other one here
26:04 we're trying to find the value of Y when X
26:07 . Is 25 . So we'll call it why 20/25
26:10 . So you see what happens , you just fill
26:12 in the blanks here and this is what a lot
26:13 of teachers try to do and it works . It's
26:16 just you don't often know what you're doing , you're
26:17 just plugging stuff and I don't really like that too
26:19 much . But how would you solve this ? Um
26:22 well you multiply both sides by 25 to get why
26:24 by itself . So what you would have is why
26:28 would be 25 Times 6/15 ? Right ? Um You
26:37 have 25 times 6/15 . All I've done is multiply
26:40 25 on both sides . Now , let's simplify those
26:43 . Uh Let's simplify it by I'm trying to think
26:46 of the best way to do it , let's do
26:47 it this way . Let's leave the 25 alone for
26:49 now . And the 6/15 , I'm gonna simplify this
26:52 fraction divided by two is gonna give me I'm sorry
26:55 , divide by three is gonna give me two divided
26:56 by three , is gonna give me five . Right
26:59 ? But then I see right here , let me
27:01 go in . Right , one more time . 25
27:03 times 2/5 5555 is 1 , 25 divided by five
27:07 is five . And so I end up with five
27:09 times two , which gives me 10 . That's exactly
27:11 the same thing I got here . But I want
27:13 you to really understand what you've done here by using
27:16 this formula is exactly the same math that we did
27:18 with Method one , which I actually think makes more
27:21 sense finding the slope of the line and then using
27:23 that to solve the thing . Because when you plug
27:26 all the values in here , notice what you're done
27:28 . You're basically saying 6/15 times 25 . But notice
27:32 what we did over here . We did 2/5 times
27:34 25 . But the 6/15 actually is 2/5 times 25
27:39 . So all we did in the first way was
27:41 find the slope , simplify it and then put it
27:43 in , multiplied by 25 got the answer here ,
27:46 we put it into our equation . We end up
27:47 with exactly the same math 25 times here . This
27:51 is 2/5 when you simplify . So you actually get
27:53 the exactly the same answer . I prefer using method
27:56 one because it makes more sense and it leads to
27:59 less errors when you know what you're doing . All
28:01 right , So we have one more here . I
28:03 want to do with you uh with direct variation and
28:06 it's gonna be a similar format . Most of these
28:08 are all the same . And it goes like this
28:10 if P is directly proportional to the variable Q .
28:24 And uh P is equal to nine , that is
28:29 not a Q . That's a nine P is equal
28:31 to nine win Q . It's a bad looking Q
28:36 . Sorry , seven point when Q is equal to
28:37 75 find Q when P is equal to 24 .
28:46 So again you've got lots of numbers mixed together and
28:48 all this other kind of stuff . So we're not
28:49 going to draw a picture this time . But I
28:52 do want you to keep in mind the picture that
28:54 we use in the last lesson . There is a
28:56 line , it's a direct variation line , it goes
28:58 through the origin and we have two points on the
29:00 line . I'm given one of the points on the
29:02 problem completely . The other point I've only given I've
29:04 only been given part of that's what you have to
29:07 keep in the back of your mind , that's what
29:09 you're really doing . So I know that this is
29:11 a direct direct variation between P and Q . It
29:13 says P is directly proportional to queue . So I
29:16 then know right away that P is equal to directly
29:18 proportional two Q . Some constant variation times Q .
29:23 Right ? Um And it's asking me find Q .
29:28 When P is equal to 24 right ? Um And
29:32 it's also telling me that P . Is equal to
29:35 nine when Q . Is equal to 75 . So
29:37 if I knew what M . Was , if I
29:39 knew what M . Was , all I would have
29:41 to do is put the P value in here ,
29:44 I would know the M . Value and I would
29:45 find the Q . Value . But the problem is
29:47 I don't know what he is , but they give
29:49 me another point on the line . I know That
29:52 P is nine when Q . is seven .5 .
29:54 So I can put in nine , that's not a
29:57 Q . That's a nine in times the Q .
30:00 Which is 75 And from this I just calculate the
30:02 slope , I could have calculated the slope , You
30:05 know uh separately differently like I did back before over
30:09 here , of course I can calculate the slope between
30:12 this point and the origin . I'm showing you kind
30:13 of an alternative way of doing it when you know
30:16 one point on this line and you know the equation
30:18 on the line here , I can just put the
30:19 two values and nine and 7.5 . And then when
30:22 I'm gonna get is nine divided by 7.5 . And
30:24 so the value of the slope is going to be
30:28 one too for the slope . And then once I
30:32 know the slope , I know that they are directly
30:34 proportional or they very directly with respect to one another
30:38 . So I know that P is equal to MQ
30:41 . But I now know what the slope is .
30:44 It's 1.2 times Q . So now I have the
30:46 equation . It would be very simple if I gave
30:48 you this line and I said , hey find Q
30:50 . When P is 24 you would know that how
30:53 to do that . But we had to find the
30:54 slope first . So then we put a P .
30:57 Of 24 in 1.2 times cute . And then Q
31:02 . is 24 divided by one point , sorry 1.2
31:08 . And so then Q . When you take 24-5
31:11 x 1.2 you get 20 . Yes . So if
31:14 we were to draw this line through the origin ,
31:17 we would see that the 0.9 comma 7.5 was on
31:22 the line and we would also see that become a
31:24 QP being 24 And Q being 20 would also be
31:29 on the line . This pair points would also be
31:31 on the line because we calculated the value of this
31:33 point using this line . Now just for giggles ,
31:37 we're going to go back and do the other do
31:38 it the other way in case you want to use
31:41 the equation given in the book . And that's that
31:43 if you have two points very directly , why one
31:46 over X one is Y . Two is equal to
31:49 Y . Two over X . Two . Now the
31:52 pair of points I'm given uh in this case actually
31:55 why why an X . Are really not in the
31:57 problem statement . So it's going to be useful for
31:59 you to say instead of that say Q one ,
32:01 P . One . Q two . P . Two
32:06 . Right ? And what are what are Q 1
32:09 ? Q 2 ? So we know that uh P
32:13 . is nine when Q is 7.5 . So what
32:15 we can say is we can say 7.5 is Q1
32:21 , P . Is nine because these points go together
32:24 and then the other Q . Is what I'm trying
32:26 to find . So I'm gonna leave it as Q
32:28 . Two . And that p when that happens is
32:30 24 . So all I've done is put all these
32:32 values in . Look what I'm going to get .
32:33 Q . two is equal to this fraction . I'm
32:36 gonna multiply by the 24 . So I'm gonna say
32:38 24 times 7.5 over What's not over Q . over
32:43 nine like this . And when you go in your
32:46 calculator type 24 times 7.5 divided by nine . What
32:50 you're gonna get is Q two is equal to 20
32:55 Which is exactly what you get now . Why do
32:57 you think it's the same thing ? Look at the
32:58 math you actually did when you plugged it all in
33:00 and you got it you took 24 and you multiply
33:02 by a fraction . The fraction was 7.5 over nine
33:06 . Look what we did here and you can see
33:08 that that's basically what you were doing before . We
33:10 calculated Cube by taking 24 and divided by 1.2 .
33:13 But the 1.2 was the slope which was a fraction
33:16 . So you can kind of think of this fraction
33:17 being on the bottom , you flip it over ,
33:19 it's gonna be 24 times 7.5 divided by nine ,
33:22 which is exactly what we got there . I'm not
33:24 trying to throw a bunch of different ways that you
33:26 to do things to confuse you . I'm trying to
33:28 show you that there's always more than one way to
33:30 get the answer to a problem . Personally I like
33:33 the more logical way of doing it . I don't
33:35 like grabbing a formula out of a book and throwing
33:37 it in there . All I need to know is
33:39 that these things very directly Soapy has got to be
33:41 equal to m times Q . I'm given to one
33:44 point on the line in its entirety which lets me
33:46 find the slope . Once I know the slope I
33:49 can then put it in for the value of the
33:50 slope and then I can use this equation of the
33:52 line to find any other point I want . In
33:54 this case I was given the p value here ,
33:56 so then I go backwards and find the Q value
33:59 . Um not rocket science but extremely important because direct
34:03 variation pops up everywhere . As I said , potential
34:08 energy and physics , force and acceleration , even geometry
34:11 and I could go on , I can have a
34:12 whole lesson in direct variation . So for now just
34:15 make sure you solve these problems yourself and you understand
34:17 them . Then follow me on to the next lesson
34:19 . We'll get a little more practice with direct variation
34:21 before moving into kind of the opposite of that ,
34:23 which we call inverse variation in algebra .
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