Learn to Divide Decimals (Long Division with Decimals) - [19] - By Math and Science
Transcript
00:00 | Hello . Welcome back . The title of this lesson | |
00:02 | is called dividing decimals . This is part one . | |
00:04 | It's a long lesson . We have a lot of | |
00:06 | problems here but it's a very , very important skill | |
00:09 | to master . So we're going to get a lot | |
00:10 | of practice now before you have before you conquer this | |
00:14 | , I really would like you to do two things | |
00:15 | first . I'd like you to watch the previous lessons | |
00:18 | on understanding what a decimal division is using pictures . | |
00:21 | So in the back of your mind I want you | |
00:23 | to have the picture a picture of what's going on | |
00:25 | as we do our problems . Second of all , | |
00:27 | you really need to be pretty good at long division | |
00:30 | already . Long division of whole numbers . We've done | |
00:32 | that many , many times in the past . Many | |
00:34 | , many , many problems . If you are fuzzy | |
00:35 | on how to do long division , please stop and | |
00:38 | go do that right now . So once we have | |
00:41 | those two things out of the way , what we | |
00:42 | want to do is divide a decimal by another decimal | |
00:45 | . So for instance , let's say we have the | |
00:47 | decimal 20.4 , we have 20 whole sandwiches and .4 | |
00:52 | of another , which is a little bit less than | |
00:54 | half of another sandwich . And we want to divide | |
00:56 | it by 1.7 . So we have a decimal divided | |
01:01 | by another decimal . Now in the picture model that | |
01:03 | we had in the last lesson we could draw a | |
01:05 | picture of 20 whole things and then .4 of a | |
01:09 | of a fraction of another thing . And then we | |
01:11 | can divide by 1.7 , we could draw a picture | |
01:13 | of that and we could see how many times 1.7 | |
01:16 | is going to fit in there . How many times | |
01:18 | will it fit in To 20.4 ? That would work | |
01:21 | . But that's not going to be a great way | |
01:23 | to solve a lot of problems . So what I | |
01:25 | want to do is I'm gonna show you how to | |
01:26 | do this , you will have some questions the first | |
01:28 | time you'll be like why ? Why can we do | |
01:30 | that ? How do we do that ? Why is | |
01:31 | that ? Okay ? I want you to kind of | |
01:33 | keep your questions but let me cycle through the first | |
01:36 | couple of problems so I can cycle through all of | |
01:38 | your questions and then at the end you'll understand everything | |
01:41 | . Now , dividing by 1.7 in long form is | |
01:45 | difficult to do . So what we're actually going to | |
01:47 | do is we're going to change this problem a little | |
01:50 | bit . What we want to divide by on the | |
01:53 | outside , we always wanted to be a whole number | |
01:56 | . It just makes the math easier . So what | |
01:58 | we want to do is take this nasty little decimal | |
02:00 | point and we want to move it over here . | |
02:02 | But if we move the decimal spot , one position | |
02:05 | over this way then we must also move what is | |
02:08 | under the the the division symbol ? Uh one spot | |
02:13 | as well . So we move the decimal one spot | |
02:15 | this way and then one spot that way you might | |
02:17 | say why are you allowed to move decimals ? Just | |
02:19 | hold your questions . I will explain why we are | |
02:21 | allowed to move decimals in just a second But for | |
02:24 | now just know that we want a whole number out | |
02:26 | here . So we move at one spot and if | |
02:28 | we move at one spot out here then we must | |
02:30 | also move this one spot as well . So then | |
02:33 | what happens is we're not going to solve this problem | |
02:36 | . What we really will do is solve a very | |
02:38 | closely-related problem which is 20 , I'm sorry 204 Divided | |
02:43 | by 17 . You see the original decimal was here | |
02:47 | and we moved it one spot to the right , | |
02:49 | so now we have 17 , the original decimal was | |
02:51 | here and we moved it also one spot to the | |
02:54 | right , which means we have a decimal point here | |
02:56 | and now a decimal point here exactly as we've shown | |
02:58 | here . So what we're saying is now we're going | |
03:01 | to solve the problem . 204 divided by 17 . | |
03:05 | We already know how to solve that problem . You | |
03:07 | already know how to do that right ? Um the | |
03:11 | only trick is knowing that we're not trick , but | |
03:13 | the only thing we have to know is that we | |
03:15 | have we want a whole number on the outside of | |
03:17 | the division symbol . So we have one spot . | |
03:20 | One spot . Now let's solve this problem . The | |
03:22 | answer that we get to this problem , whatever we | |
03:24 | get is the answer is the same answer as what | |
03:28 | we would get . If we just drew a picture | |
03:29 | and divided this , it just so happens that this | |
03:32 | is much easier to do and it gives us the | |
03:34 | same answer again . I will explain why we're moving | |
03:36 | the decimal in just a minute . Let me finish | |
03:38 | the problem . All right . How do we do | |
03:41 | ? Long Division 17 divided into two . It can't | |
03:44 | go it's it's not too is not big enough . | |
03:46 | So consider 17 , dividing into 20 . It can | |
03:49 | only go one time 17 is very close to 20 | |
03:52 | . So we'll put anyone right here and we put | |
03:54 | it over the zero because we're dividing into the 20 | |
03:58 | . The next step is one time 17 . We | |
04:00 | just put the 17 here and subtract . Now . | |
04:02 | You can do the borrowing and all that to subtract | |
04:05 | or you can just think that you're subtracting 20-17 . | |
04:09 | You can start at 17 and count up to 20 | |
04:12 | to do the subtraction . If you want to go | |
04:14 | subtract 2019 , 17 on the side , that's fine | |
04:16 | . Or you can count up from 17 18 1920 | |
04:20 | . There's only three units between 17 and 20 . | |
04:24 | So we can just put a three down here to | |
04:28 | do it long form we have to borrow here and | |
04:30 | all this stuff and that will make it cluttered . | |
04:31 | So we know the answer is three After we subtract | |
04:35 | , grab the next digit , bring it down . | |
04:38 | Now what do we do ? We have to figure | |
04:40 | out 17 times something is 34 . We know that | |
04:43 | 17 times one is 17 . What is 17 times | |
04:46 | two , 17 times to seven times 2 is 14 | |
04:51 | and two times one is two plus one is 3 | |
04:54 | , 17 times two is exactly 34 . So this | |
04:57 | has to be a 22 times 17 is 34 . | |
05:00 | Subtract 34 minutes , 34 0 . And so we | |
05:05 | grabbed the next digit but there is no next digit | |
05:07 | , so we're basically done and the remainder is zero | |
05:10 | . So what have we figured out here ? We | |
05:12 | figured out that if we take 204 and divided by | |
05:16 | 17 we get 12 times it fits in there exactly | |
05:20 | 12 times . So the answer to this problem is | |
05:24 | 12 . The answer is this problem as 12 and | |
05:28 | that is exactly the same answer As we get when | |
05:31 | we take 20.4 and divide by 1.7 we convert it | |
05:35 | to this because when we don't have nasty decimals here | |
05:38 | on the outside , it makes doing the long division | |
05:41 | process easier . So what we're going to do every | |
05:44 | single time is when we're dividing by a decimal , | |
05:47 | we're going to move the decimal as many spots as | |
05:50 | it takes , so that we only have a whole | |
05:52 | number out here and however many spots we move it | |
05:55 | , we must also move the inner decimal the same | |
05:58 | number of spots because if you Move one but not | |
06:02 | the other than you've changed the problem , but if | |
06:05 | you move one of them and then also move another | |
06:07 | one then they're the same . Let me give you | |
06:10 | a couple of a couple of reasons why it's okay | |
06:13 | to do this picture , you have a teeter totter | |
06:16 | or a seesaw right , and you have , it's | |
06:19 | balanced in the middle , you have one person on | |
06:21 | this side and one person on this side and it's | |
06:23 | perfectly balanced , it's not moving , it's perfectly flat | |
06:27 | . Now if I put a bag of sand on | |
06:29 | one side of course it's going to do this , | |
06:31 | but I can keep it balanced by also putting another | |
06:34 | bag of sand on the other side , and then | |
06:36 | I can keep the exact balancing the same of the | |
06:39 | seesaw . If I take one bag of sand off | |
06:42 | its course is gonna move , but if I take | |
06:44 | both sands off at the same time , then the | |
06:47 | Children are still there and the seesaw is still exactly | |
06:50 | balanced . If we move one of these decimals by | |
06:53 | itself , then we've unbalanced everything and changed everything , | |
06:56 | but if we move both of these decimals the same | |
06:59 | , then the problem looks different , but actually gives | |
07:02 | exactly the same answer as if we do this . | |
07:05 | So that's one way of thinking about it . Let | |
07:08 | me tell you another way , a better way of | |
07:09 | thinking about it when we do division like this , | |
07:12 | you really need to start thinking about division as being | |
07:16 | kind of like a fraction , it is a fraction | |
07:17 | fractions and divisions are basically the same thing . So | |
07:20 | , what we have here is the fraction uh to | |
07:25 | let me do it , yeah , I'll do it | |
07:26 | here 20.4 Divided by 1.7 . 20.4 , divided by | |
07:33 | 1.7 . I know that you may not be thinking | |
07:37 | of fractions in terms of division yet , because we | |
07:40 | talk about fractions as parts of a whole , but | |
07:43 | as we go more and more into fractions , you | |
07:45 | need to start thinking about fractions as being division . | |
07:47 | The fraction bar is basically a division symbol actually the | |
07:51 | bar here with something on top and something on the | |
07:53 | bottom doesn't look a whole lot like this . A | |
07:55 | bar with something on the top and something on the | |
07:57 | bottom . A bar with something on the top and | |
07:59 | something on the bottom . So a fraction is division | |
08:02 | . It's the top thing , divided by the bottom | |
08:05 | thing . Now we're dividing taking this and dividing by | |
08:08 | this . Now remember we said that when we deal | |
08:11 | with fractions we can multiply or divide the top and | |
08:15 | the bottom by the fraction Of the fraction by any | |
08:17 | number we want . That's how we simplify fractions . | |
08:20 | Remember we can divide the top by two and the | |
08:22 | bottom by two . We can divide the top by | |
08:24 | four in the bottom by four . I can divide | |
08:26 | the top by 10 and the bottom by 10 . | |
08:29 | As long as I do it to the to both | |
08:31 | the top and the bottom . I have not changed | |
08:33 | the fraction . The same thing is true of multiplication | |
08:36 | . I can multiply a fraction by two or three | |
08:38 | or four as long as I do it to the | |
08:40 | top and the bottom at the same time . So | |
08:43 | let's see what happens since I can do whatever I | |
08:46 | want . What would happen if let me extend this | |
08:49 | fraction bar here . What would happen if I multiply | |
08:52 | the top of this fraction and the bottom of this | |
08:54 | fraction by 10 Multiply the top and the bottom of | |
08:58 | the fraction by 10 multiplying by the same number does | |
09:01 | not change the fraction . It just changed the way | |
09:03 | the fraction looks . And then what would we have | |
09:07 | , Remember we talked about what happens when you multiply | |
09:10 | by 10 ? All that happens is you move the | |
09:12 | decimal Right ? So when you multiply by 10 , | |
09:15 | you move the decimal to the right , making it | |
09:18 | 10 times bigger . And when you divide by 10 | |
09:20 | you move the decimal . The other way we talked | |
09:22 | about that before , so 20.4 times 10 is 204 | |
09:27 | and 1.7 times 10 is 17 . So what we're | |
09:30 | saying here is that this fraction , 204 over 17 | |
09:35 | looks different than 20.4 divided by over 1.7 . But | |
09:39 | it's the same fraction because we multiplied the fraction top | |
09:43 | and bottom by 10 and all that does is move | |
09:45 | the decimal . So this is why I can take | |
09:47 | 204 and divide by 17 . And it gives me | |
09:50 | the same answer because this thing is the same exact | |
09:55 | thing as this thing . It means the same thing | |
09:58 | . We multiply top and bottom by 10 . When | |
10:01 | I tell you to move the decimal , all you're | |
10:03 | doing is multiplying this one by 10 and multiplying this | |
10:05 | one by 10 which you already know that you can | |
10:08 | do that for fractions . But most of the time | |
10:10 | in , in in learning division , the teacher doesn't | |
10:13 | tell you what you're doing . They just tell you | |
10:15 | move the decimal , move the decimal on the inside | |
10:18 | and on the outside and you don't know why it's | |
10:20 | because this is really a fraction and multiplying top and | |
10:24 | bottom by the same thing is okay , and so | |
10:26 | when you move that decimal here and here in lockstep | |
10:29 | at the same time , it's just doing this , | |
10:32 | so this is exactly the same thing as doing this | |
10:36 | . So for the future problems we're not going to | |
10:38 | do so much thinking about it , I wanted to | |
10:40 | just tell you what you're doing but what we are | |
10:43 | in practice going to do is move the outside uh | |
10:46 | decimal point to the right to give us a whole | |
10:49 | number and then we'll move the inside decimal point , | |
10:51 | the same amount of places that is going to give | |
10:54 | us the right answer in all situations . Mhm . | |
10:58 | Now , with all that talking out of the way | |
11:00 | , we can finally work more problems , let's say | |
11:04 | that we have the problem . Uh we're going to | |
11:06 | divide the number 1.85 and we'll divide it by 0.5 | |
11:13 | . Now what we want to do is we want | |
11:14 | to move the outside decimal point one spot to the | |
11:19 | right and then one spot to the right , that | |
11:21 | is like multiplying this by 10 and then multiplying this | |
11:24 | by 10 . And so you haven't changed the problem | |
11:26 | . But really we're going to kind of work a | |
11:28 | related problem which since we move the decimal here , | |
11:31 | it'll be 18.5 and we'll divide that by move the | |
11:36 | decimal over here , it's just going to be five | |
11:38 | . The zero won't matter at all . 05 you | |
11:41 | don't need the zero there . So what we're doing | |
11:42 | really is we're going to be solving this division problem | |
11:45 | , We want a whole number on the outside . | |
11:48 | Just like we wanted to get to a whole number | |
11:50 | on the outside here . Now when we do it | |
11:52 | , get it here , we ended up with a | |
11:54 | whole number on the inside to hear . We ended | |
11:57 | up with a still a decimal on the inside . | |
11:59 | That's okay . The very first thing you want to | |
12:02 | do when you do these division problems , if you | |
12:04 | still have a decimal on the inside the decimal point | |
12:06 | and the answer , it just floats right above . | |
12:09 | You don't have to count positions , you don't have | |
12:11 | to to do it like we did for multiplication or | |
12:14 | anything . All you have to do is look at | |
12:16 | where the decimal is in the final decimal is there | |
12:19 | ? Look here the decimal point invisible was here . | |
12:22 | Now we have an invisible decimal directly . Can kind | |
12:24 | of put a little dot there if you want right | |
12:25 | there . So the same rule is happening here . | |
12:28 | So the decimal we already have now , we can | |
12:31 | just solve the rest of the problem . Normally five | |
12:34 | divided by going into one , doesn't work five going | |
12:38 | into 18 , 5 times three is 15 , 5 | |
12:40 | times four is 20 . That's too big . So | |
12:42 | it has to be five times 3 15 . What | |
12:46 | is 18 minus 15 ? Or you can think of | |
12:48 | eight minus five is 30 minus 00 After we subtract | |
12:53 | , Grab the next digit down , we have 35 | |
12:56 | Now , five times what is 35 ? five times | |
12:59 | 7 is 35 . So multiply subtracting zero , grabbed | |
13:04 | the next digit , there is no next digit , | |
13:06 | so we're done the remainder here . When we get | |
13:08 | down to a zero here , we're done and the | |
13:10 | answer that we get is 3.7 . So the answer | |
13:13 | to the whole problem that we're doing here Is we'll | |
13:15 | just say the answer is 3.7 , this is the | |
13:19 | final answer . So in the first problem we did | |
13:22 | the division and we got an answer of 12 . | |
13:24 | A whole number . That just means that if we | |
13:26 | drew this out and divided it into 20.4 , it | |
13:29 | would go 12 whole times , exact amount of division | |
13:33 | going in there . When we do 185 divided by | |
13:36 | five or the same one , divided by five . | |
13:40 | When you draw it out , what's going to happen | |
13:42 | is it's going to fit three whole times , but | |
13:45 | it's not going to fit a four time , it's | |
13:48 | only going to fit a portion passed that it's not | |
13:50 | gonna fit quite four times . You'll have some left | |
13:53 | over , it will be able to go in a | |
13:55 | little bit more , but not all the way four | |
13:57 | times , it's only going to go 3.7 Because remember | |
14:00 | if we get to 3.8 and 3.9 we'll get closer | |
14:03 | and closer then we'll roll over to 4.0 so when | |
14:06 | we get an answer of 3.7 it means it divides | |
14:09 | in three whole times in almost four but not quite | |
14:13 | . So it wasn't able to go another full time | |
14:15 | in . All right . I know it's a little | |
14:19 | weird in the beginning but I promise it will become | |
14:21 | clearer as we work more problems . We're gonna move | |
14:24 | that decimal point every single time on the outside . | |
14:27 | Let's take the next problem . Let's say that we | |
14:30 | really want to divide 16.72 and divide that by 3.8 | |
14:38 | . Yeah , so the very first step is to | |
14:39 | look on the outside , we have a decimal point | |
14:41 | here , we do not want decimals on the outside | |
14:43 | , we want whole numbers , we move one position | |
14:46 | there . Therefore we must move one position there which | |
14:49 | is keeping it balanced . But also this is like | |
14:51 | multiplying by 10 and multiplying by 10 . So we | |
14:53 | keep everything balanced . So the related problem that we're | |
14:57 | actually going to solve , We'll move the decimal one | |
15:00 | position over is 167.2 and we'll divide that by 38 | |
15:08 | . 38 . All right . 38 . So what | |
15:12 | we want to do is we want to figure out | |
15:16 | this problem here is going to give us an answer | |
15:19 | which will be the exact same answer as what we | |
15:21 | have started with here . Now , question for you | |
15:25 | , How many times can 38 go into one ? | |
15:27 | Actually one thing 1st . Before you do anything else | |
15:30 | , the decimal point of the answer just floats right | |
15:33 | above . You can even do that is the first | |
15:34 | step . All right . 38 goes into um one | |
15:40 | . How many times ? Well , zero times because | |
15:43 | one is too small . How many times can you | |
15:45 | go into 16 ? Well , doesn't really go at | |
15:48 | all because 16 is too small . So we have | |
15:49 | to consider 167 . I'm not sure how many times | |
15:53 | it can go in . So I may have to | |
15:54 | go off to the side and start multiplying . Let | |
15:56 | me start multiplying 38 times four . eight times 4 | |
16:00 | is 32 , Three times four is 12 . Then | |
16:04 | we go up 13 , And we get an answer | |
16:07 | of 152 . 152 is as close as I'm going | |
16:11 | to get to 1 67 . If I multiply by | |
16:14 | five , I'm confident I'm gonna blow it because I'm | |
16:17 | already very , very close . So it goes four | |
16:20 | times . So put a four here . It goes | |
16:22 | four times into 1 67 . When I multiply that | |
16:25 | I get 152 . We just did that . And | |
16:28 | so now I can subtract 7 -2 is five . | |
16:31 | 6 -5 is 1 . -1 is zero . But | |
16:35 | I don't have to put leading Zeros . And then | |
16:38 | finally after I do the subtraction , I grabbed the | |
16:40 | next digit which is a two and a two goes | |
16:42 | down there . Now How many times do I go | |
16:46 | into this ? 38 times something is 152 but we | |
16:49 | already know it's exactly four . So 38 times four | |
16:53 | when we multiply is 152 and we subtract we get | |
16:57 | zero and there are no more digits to bring down | |
17:00 | . So the process is done and the answer that | |
17:03 | we got was 4.4 . The decimal just come straight | |
17:06 | . It floats right above there . And so the | |
17:09 | answer that we get for this problem is 4.4 . | |
17:12 | So what does this actually mean ? It means if | |
17:15 | I have $16.72 and $3.80 I can float another zero | |
17:21 | there if I want and I divide in there , | |
17:23 | then what's going to happen is this can go into | |
17:25 | 16.7 to 4 whole times , But it can't go | |
17:30 | five times . It goes a little bit more than | |
17:32 | four . I'll have some leftover that it can go | |
17:35 | a little bit more , but not a whole time | |
17:37 | . Not even a half of if it were 4.5 | |
17:39 | , it would go exactly 4.5 times . It's a | |
17:43 | little less than that . So it's a little less | |
17:44 | than 4.5 is what that division is . All right | |
17:50 | . I know it's a lot . I do . | |
17:51 | But really when you get the hang of it you | |
17:53 | realize there's really only one more step in the beginning | |
17:56 | and that is moving the decimal point . Let's take | |
17:58 | a look at the problem . 28 .86 . And | |
18:03 | we'll divide that by 7.4 . Yeah . All right | |
18:08 | . So we want a whole number on the outside | |
18:10 | . So we move the decimal one position here and | |
18:13 | in order to keep it balanced , we move one | |
18:15 | position there . In other words , multiplying by 10 | |
18:18 | and multiplying by 10 keeps everything balanced . So we | |
18:21 | want to rewrite the problem and do the related problem | |
18:24 | . It's going to be 288 point six And we'll | |
18:29 | then divide that by 74 . That's what we actually | |
18:34 | have to do . Yeah . All right . So | |
18:37 | first step we take a look at what we have | |
18:39 | , we have a decimal point here in the decimal | |
18:41 | point . In the answer will float directly above . | |
18:44 | Alright , next 74 can't go into two is too | |
18:48 | small , 74 . Can't go into 28 . That's | |
18:50 | too small , 74 can go into 2 88 . | |
18:53 | How many times ? I don't really know . So | |
18:56 | let's try multiplying by three . Three times four is | |
19:01 | 12 carry seven times three is 21 . 1 more | |
19:04 | is 22 . So when I multiply by three I | |
19:08 | get 222 and I'm trying to get as close as | |
19:11 | I can to to 88 . I can multiply by | |
19:14 | four . You can multiply by four if you want | |
19:16 | but you're definitely going to blow past 288 . It's | |
19:19 | not gonna work . It's gonna be too high . | |
19:21 | The 222 if you add 74 more is going to | |
19:24 | be too high . In fact we can just do | |
19:25 | it real quick , 74 times four . Four times | |
19:29 | four is 16 , 7 times four is 28 . | |
19:32 | 1 more is 29 . So 296 is too big | |
19:35 | , so that's too big . So it has to | |
19:37 | go only three times . So the three goes here | |
19:39 | and we just said three times that is 222 . | |
19:43 | And so we then subtract 8 -2 is six . | |
19:49 | 8 -2 again is six and 2 -2 is zero | |
19:52 | . I don't really need to put that . After | |
19:54 | I subtract I dragged the next digit down and so | |
19:57 | I have 666 down there . All right . Now | |
20:01 | , the next question is 74 times what is 666 | |
20:04 | ? Now , I know that 74 times 10 is | |
20:08 | just 740 . When you multiply by 10 , you're | |
20:10 | just adding a zero So that's too big . So | |
20:13 | let's try multiplying times nine instead Will do 74 times | |
20:18 | nine nine times four is 36 carry the three and | |
20:23 | then nine times 7 63 64 65 66 . Oh | |
20:27 | , look at exactly is equal to 6666 . So | |
20:31 | it can go nine times nine times 74 is 666 | |
20:36 | which gives me a leftover of zero . And so | |
20:39 | the answer that we get is 3.9 . So I | |
20:42 | can either just circle this or I could just write | |
20:45 | the answer down anywhere else . I guess I'll just | |
20:46 | circle it up here Just so you can kind of | |
20:48 | see that this is the final answer is 3.9 . | |
20:51 | So if I were to take 28.86 of something and | |
20:56 | divided by 7.4 and see how many times it can | |
20:59 | fit in . It's telling me that it can fit | |
21:02 | three whole times And not quite four times but very | |
21:06 | close to four times . Because the .9 is telling | |
21:08 | me it almost goes four times but not quite it's | |
21:11 | not quite enough extra to go 1/4 time . But | |
21:15 | it's very close because it's at 3.9 . Yeah . | |
21:19 | All right . Making good progress . Let's take a | |
21:23 | look at problem number five , we want to divide | |
21:26 | the following numbers 8.47 Want to divide it by 0.2 | |
21:33 | to 0.22 Now here we have a decimal here and | |
21:37 | we have two digits . We do not want any | |
21:39 | whole numbers whereas before we only have to move one | |
21:42 | position here , we actually have to move the outside | |
21:45 | digit decimal .2 positions . And if we do it | |
21:49 | to positions on the outside then we must move the | |
21:52 | inside decimal two positions also . So you might say | |
21:55 | what would be happening here ? If we multiply by | |
21:58 | 10 , it would move at one position . If | |
22:00 | we multiply by 10 again it moves it another position | |
22:03 | . So it's like multiplying this by 100 to move | |
22:06 | the decimal point . But we also move this one | |
22:09 | , multiplying by 100 . So it moves the decimal | |
22:11 | , the same amount , putting bags of sand on | |
22:13 | the seesaw , multiplied by 10 , multiplied by 10 | |
22:16 | . As long as I'm doing it to both , | |
22:19 | uh the inside and the outside or the top and | |
22:22 | the bottom of the fraction . I'm not changing anything | |
22:25 | . So what I really want to do is solve | |
22:28 | the related problem . The related problem is 847 because | |
22:32 | we move the decimal two times divided by 22 and | |
22:37 | it doesn't even look like there's any real decimal points | |
22:39 | on the problem . But if you remember there's an | |
22:41 | invisible decimal after the whole number . So there's like | |
22:44 | an invisible decimal right there . We don't usually write | |
22:46 | it but we can still put it there . All | |
22:49 | right , 22 cannot go into 82 small , 22 | |
22:54 | can go into 84 . How many times ? I'm | |
22:56 | not sure . So let me try to go over | |
22:58 | here and say 22 . Let's start by multiplying by | |
23:01 | 32 times three is 62 times three is six . | |
23:04 | Alright , that's pretty close . Let's try to go | |
23:06 | a little higher . 22 times four , two times | |
23:10 | four is 82 times four is eight . This is | |
23:12 | actually too high . So it only actually can go | |
23:15 | three times three times and three times 22 we just | |
23:19 | said was 66 we subtract now here is where you | |
23:24 | know we have to do a little thinking because what | |
23:26 | we have to do is 84 minus 66 . It's | |
23:29 | difficult to do that in our head and we have | |
23:31 | to do borrowing here but the four minus six it's | |
23:35 | going to look ugly if we do it under here | |
23:36 | . So what I'd really rather you do is come | |
23:38 | over to the side . What we wanna do is | |
23:40 | 84 minus 66 And we cannot do 4 -6 so | |
23:47 | we'll change this to a 14 and we'll borrow making | |
23:49 | that seven . Mhm . 14 going down by six | |
23:54 | is 13 12 11 10 98 14 minus six is | |
23:59 | eight and seven minus six is one . So the | |
24:01 | answer is 18 84 minus 66 is 18 . After | |
24:06 | we subtract we pull the next digit down . We | |
24:09 | have 187 there . 187 . I'm not really sure | |
24:13 | . Um Exactly 22 times something has to be 187 | |
24:17 | . I'm not totally sure . But I know that | |
24:20 | it's going to be times six times seven times eight | |
24:23 | or whatever . I'm not really totally sure . So | |
24:24 | you have to kind of play with a little bit | |
24:26 | . So let's go over here and see what 22 | |
24:29 | times eight is 22 times 88 times two is 16 | |
24:33 | , carry the 18 times two is 16 . 1 | |
24:35 | more is 17 . So that's 176 . If I | |
24:39 | go times nine I'm going to blow it , I'm | |
24:42 | going to go past 187 . So it has to | |
24:45 | be times eight . And if you want to go | |
24:48 | times nine and prove it to yourself and of course | |
24:50 | you can do that . So we're going to say | |
24:52 | it goes eight times so it goes eight times here | |
24:54 | in eight times 22 . We just said is 1 | |
24:56 | 76 And we subtract 7 -6 is 1 8 -7 | |
25:02 | is also 1 1 -1 . I don't have to | |
25:05 | write now . Here is the point where I turn | |
25:08 | around and I have to teach you something really important | |
25:10 | . When we're dividing decimals , our goal is to | |
25:13 | get down to where the remainder is zero , notice | |
25:15 | how the remainder was zero . So we knew we | |
25:17 | were done here , the remainder was zero . So | |
25:20 | we knew we were done here , the remainder was | |
25:21 | zero . So we knew we were done . I | |
25:23 | can keep going back to the other problems . The | |
25:25 | remainder was always zero . So we knew we were | |
25:26 | done . But now when we subtract it looks like | |
25:30 | there's no other digit here so it looks like we | |
25:32 | have a remainder of 11 and you think you're gonna | |
25:34 | put remainder 11 Our 11 . We don't do that | |
25:37 | with decimals . We do that for the other division | |
25:40 | . The whole number division that we have learned in | |
25:42 | the beginning but when we have decimal division we really | |
25:45 | want the remainder to be zero down here if possible | |
25:47 | . Hear the remainder is 11 so we need to | |
25:50 | keep going in the process but we don't have any | |
25:52 | more digits . So what we have to do is | |
25:54 | add some digits Right ? Because what's going on here | |
25:58 | is even though we're dividing 847 divided by this , | |
26:01 | there's an invisible decimal here . And as you know | |
26:04 | we can add Zeros after a decimal point . As | |
26:07 | many as we need to add to make the process | |
26:10 | work out . So since I was able to add | |
26:13 | a zero there now the the the I do have | |
26:18 | another digit to drag down which is a zero . | |
26:21 | Remember what we did was we subtracted , we get | |
26:24 | an 11 and we always try to grab the next | |
26:26 | digit but we didn't have another digit so we had | |
26:28 | to add after the decimal zero . So we would | |
26:31 | have something to grab to come down . Now we | |
26:35 | have 110 down here , two times what is 110 | |
26:40 | ? I'm not sure . So we're going to try | |
26:42 | to go 22 times five and let's see what we | |
26:46 | get two times five is 10 , carry the 12 | |
26:48 | times five is 10 plus one is 11 , so | |
26:51 | 22 times five is 110 . 22 times five multiply | |
26:57 | Is 110 Subtract now we get a remainder of zero | |
27:01 | . Now we know we can stop . So the | |
27:03 | answer to this problem is 38.5 . So when we | |
27:08 | take this number and divided by .22 it can go | |
27:12 | in and fit inside 38 whole times plus another half | |
27:16 | . It can't go another whole time , it can | |
27:17 | go a half . I need a Kind of talk | |
27:20 | about this a little bit before we go on . | |
27:22 | The process works . The same for this problem is | |
27:24 | for the other problems but in the other problems we | |
27:26 | got a remainder of zero . So we stopped , | |
27:28 | we got a remainder of zero , so we stopped | |
27:29 | , we got a remainder of zero so we stop | |
27:31 | . But here we had a remainder of 11 and | |
27:35 | we thought we should stop but when we divide decimals | |
27:37 | we always want to get to a remainder of zero | |
27:40 | . And so we had to add and put the | |
27:43 | decimal point that we know is there and add a | |
27:45 | zero . Which does not change the number . It | |
27:47 | doesn't change anything but it allows us to continue the | |
27:50 | process to get down to a remainder of zero . | |
27:52 | So we have to keep an eye out for that | |
27:54 | . Sometimes we will have to do that . All | |
27:57 | right , Moving right along problem # six , Let's | |
28:02 | say we have the problem 3.36 . And we want | |
28:07 | to divide that by 2.1 , 2.1 . So on | |
28:13 | the outside we have a decimal here . We don't | |
28:15 | want any decimal . So we move one position so | |
28:18 | we move this decimal one position also . So that | |
28:21 | means really we're going to solve the related problem over | |
28:24 | here of 333.6 and we'll divide it by 21 . | |
28:31 | Move the decimal one position one position in this problem | |
28:34 | will be the same as the previous problem . So | |
28:37 | now we then look at the decimal point , we | |
28:39 | can float the decimal up into the final answer and | |
28:42 | now we say , how many times can 21 go | |
28:44 | into three ? We can't go into three . How | |
28:47 | many times can 21 go into 33 ? It can | |
28:49 | only go once because we know that you know , | |
28:51 | you can kind of think of it as being close | |
28:53 | to 20 times to would be 40 that would be | |
28:56 | too much . So it really can only go one | |
28:58 | time . one times . 21 is 21 . subtract | |
29:03 | three minus one is two and three minus two is | |
29:06 | one . After subtract . The next step is to | |
29:08 | grab the next digit which is a six and remember | |
29:11 | we're looking for a remainder of zero before we stop | |
29:14 | this process , So we have 126 down here . | |
29:18 | And what do we do next ? 21 times something | |
29:21 | is 126 . I'm not sure uh what to pick | |
29:25 | . I know it's not gonna be it's gonna be | |
29:26 | kind of a big number , but I'm not sure | |
29:28 | . So let's go off to the side 21 times | |
29:30 | six . Six times 166 times two is 12 . | |
29:35 | And I get 126 . I kind of guessed here | |
29:37 | . You might start with five or seven . Eventually | |
29:40 | you'll figure out the closest you can get is six | |
29:42 | . So , it can go six times For 126 | |
29:46 | , subtracting at zero . Now the remainder is zero | |
29:49 | and there are no more digits to drag down . | |
29:51 | Now . We know the process can be stopped and | |
29:54 | the answer to this is 1.6 16 Final answer . | |
30:01 | All right , we're almost done actually . I know | |
30:04 | these are kind of long , but we just need | |
30:06 | to really get a lot of good practice to make | |
30:08 | sure that we're on the same page . Let's take | |
30:10 | a look at the problem 6.56 . And we'll divide | |
30:15 | it by 0.02 . So on the outside I have | |
30:22 | two digits after the decimal . I want to move | |
30:24 | this decimal one position to positions to get a whole | |
30:27 | number . That means to keep it balanced , I | |
30:29 | have to move one position to positions to keep it | |
30:31 | balanced on the inside . So really I'm going to | |
30:34 | then solve the related problem of 656 and I'll divide | |
30:39 | that by Once . I move the decimal , I | |
30:41 | only have two on the outside the leading Zeros . | |
30:44 | You can throw away once you move the decimal . | |
30:46 | This is what I want to solve . 656x2 . | |
30:50 | Now , I know there's an invisible decimal here so | |
30:53 | there's basically an invisible decimal that floats right above . | |
30:55 | I don't have to put that but you know I | |
30:57 | can . Alright next , what do we have ? | |
31:01 | Two times what is six ? Two times three is | |
31:03 | six ? So multiply and subtract , I get a | |
31:06 | zero drag the next digit down which is then five | |
31:10 | . Two times what is five ? Two times two | |
31:13 | is four . That's as close as I can get | |
31:15 | two times to being four . Subtract , I get | |
31:17 | a one and I then after subtraction , dragged the | |
31:20 | next digit down . Now I have 16 . two | |
31:23 | times what is 16 ? two times 8 is exactly | |
31:26 | 16 and I get a zero now I have a | |
31:29 | remainder of zero . I don't have any more digits | |
31:32 | . Of course I can keep adding zeros but I | |
31:33 | don't need to because I already got to a remainder | |
31:35 | of zero . So the answer we get this 328 | |
31:39 | the . really doesn't doesn't really do much because you | |
31:42 | can put a decimal zero after if you like . | |
31:45 | So what I'm going to do is just say that | |
31:47 | the answer is 328 . That was a whole number | |
31:50 | answer . Alright , next problem . Let's go ahead | |
31:55 | and give ourselves some room . We're gonna solve the | |
31:57 | next problem down here . Let's say we're solving the | |
32:00 | problem . 0.91 and one divide that by 0.65 . | |
32:08 | All right . First thing we look on the outside | |
32:10 | , we have to move this decimal one position to | |
32:12 | positions . That means we have to move this 11 | |
32:14 | position to positions also to keep it balanced . So | |
32:18 | we're really going to solve a related problem . We | |
32:21 | move the decimal , it'll be 91 on the inside | |
32:24 | and we'll divide it by 65 on the outside , | |
32:28 | 65 on the outside . Alright , next thing we | |
32:32 | want to notice is that just as always we have | |
32:35 | an invisible decimal right here . Let me get rid | |
32:37 | of this real quick . We have an invisible decimal | |
32:39 | here . So the answer will have an invisible decimal | |
32:41 | right there as well . Give myself a little bit | |
32:43 | more room here . I just kind of come more | |
32:46 | like over here . All right . Um and so | |
32:50 | then we want to start by looking at saying alright | |
32:52 | 65 can go how many times into nine ? Well | |
32:55 | it can't go at all into nine . Too small | |
32:58 | . How many times can you go into 91 ? | |
33:00 | Well I know it can go one time and I | |
33:02 | know that it cannot go to times because if you | |
33:04 | think about this is being pretty close to 66 times | |
33:07 | two is 12 , So 60 times two is 120 | |
33:10 | . If you multiply this you're going to get something | |
33:12 | way bigger than 91 . So it has to go | |
33:15 | only one time right here . So put it one | |
33:17 | right here and then multiply get 65 And then we | |
33:21 | need to subtract . Now unfortunately you have to do | |
33:23 | a little borrowing so let's go over here and do | |
33:25 | 91 -65 . Now we know that we can't do | |
33:32 | one minus five so make it 11 and borrow and | |
33:34 | that becomes 8 11 minus five . Go down 10 | |
33:38 | 9876 11 minus five or 68 minus six it's two | |
33:43 | . So the answer here is 26 . So we | |
33:45 | put a 26 down here Now we don't have any | |
33:48 | more digits in our problem but we also do not | |
33:51 | have a remainder of zero so we have to keep | |
33:53 | going even though you you think oh I don't have | |
33:55 | any more digits really . You need to be looking | |
33:57 | at the remains the remainder that you kind of have | |
33:59 | and you want to get it down to the point | |
34:01 | where it's essentially zero if you can . And so | |
34:05 | we have to continue the process . So we look | |
34:07 | up here and we say well We have 91 , | |
34:09 | we have a decimal , we can easily add another | |
34:11 | zero here without changing the problem at all . So | |
34:14 | we're going to insert that and add that zero . | |
34:17 | Then after we did the subtraction we just drag that | |
34:19 | zero down and now we have 260 down there . | |
34:23 | So the question then is 65 times what is 260 | |
34:29 | ? I'm not sure the answer . So let's go | |
34:30 | here and do 65 times four . You can try | |
34:32 | times three or times five five times four is 20 | |
34:36 | carry the 26 times four is 24 25 26 . | |
34:39 | I didn't know that ahead of time but you know | |
34:42 | , I also know what the answer is . So | |
34:43 | but you might try times three times five or whatever | |
34:45 | . Eventually you're gonna figure this out , Times four | |
34:48 | is the answer . So you put a four here | |
34:50 | , four times 65 is 260 Then you subtract and | |
34:55 | get a remainder of zero and now we don't have | |
34:57 | any more digits . We could continue adding zeros but | |
35:00 | it doesn't help us do anything because the remainder is | |
35:02 | already at zero . So the answer to this is | |
35:04 | 1.4 . So I guess I'll just kind of box | |
35:07 | this the answer is 1.4 . Sorry , this is | |
35:09 | kind of crowded here . The answer is 1.4 for | |
35:13 | this problem . So if we take 0.91 and we | |
35:16 | divide it by 0.65 it can go one whole time | |
35:19 | . Almost 1.5 times a little bit less than 1.5 | |
35:23 | times . All right . I think we have room | |
35:27 | for one more problem . I think that would be | |
35:31 | a good place to stop it over here . So | |
35:34 | , let's take a look at the next problem . | |
35:38 | I guess . Let's go up like this . Give | |
35:40 | me a little space . Let's take a look at | |
35:41 | the final problem . 2.52 . And we're going to | |
35:45 | divide that by 0.08 . So on the outside we | |
35:54 | don't want any decimal . So we move to spots | |
35:56 | to the right ? That means we move to spots | |
35:58 | to the right here . All right . So that | |
36:01 | means we're actually going to be solving the related problem | |
36:04 | . I'll write it over here of 252 and we'll | |
36:09 | divide that by zero point . I'm sorry eight because | |
36:12 | we moved it to , its gonna be eight on | |
36:14 | the outside . Eight now we can put the decimal | |
36:18 | here because we know that there's a decimal after every | |
36:20 | whole number . And so the decimal and the answer | |
36:22 | has to be above there as well . So let's | |
36:24 | see how this shakes out . Alright eight can go | |
36:29 | , cannot go into too , it's too small . | |
36:31 | Let's try going into 25 . 8 times two is | |
36:33 | 16 . 8 times three is 24 . So it | |
36:36 | can go three times into 25 . 8 times three | |
36:39 | is 24 . We subtract and we know that the | |
36:42 | answer is one After we subtract , grab the next | |
36:45 | digit which is a two now eight times one is | |
36:48 | 88 times two is 16 . That's too big . | |
36:50 | So it has to go only one time eight times | |
36:53 | 1 is eight subtract now we can you know borrow | |
36:58 | and all that . But really you know that if | |
36:59 | you go start from eight and count up to 12 | |
37:02 | 9 10 11 12 is four so 12 minus eight | |
37:06 | is four and then you look for another digit , | |
37:09 | you don't have another digit and you think oh I | |
37:10 | guess I'm done but you say wait a minute we're | |
37:12 | always trying to get to a remainder of zero in | |
37:15 | here , I don't have a remainder of zero . | |
37:16 | So in decimal problems I need to keep going I | |
37:19 | can insert zeros after the decimal it doesn't change anything | |
37:23 | and then that allows me to drag because I just | |
37:25 | subtracted to drag the next digit down Which is zero | |
37:29 | and I have now 40 . So now eight times | |
37:32 | what is 48 times five is 40 . Multiply you | |
37:36 | get the 40 subtract , you get a zero And | |
37:40 | so now I do have a remainder of zero . | |
37:41 | I don't have any more digit . I could keep | |
37:43 | adding zeros but I don't need to because I've already | |
37:46 | gotten to a point where my remainder is zero . | |
37:49 | So the answer to this is 31 .5 . All | |
37:57 | right . That is a long lesson . A lot | |
38:00 | of writing . A lot of you have to go | |
38:02 | off to the side and your side work to make | |
38:04 | sure you can subtract or multiply to figure out what | |
38:07 | to do . I don't want you to lose sight | |
38:08 | of the big picture . The big picture is you | |
38:11 | have to do this division but the decimal on the | |
38:14 | outside , you don't want decimals here . So you | |
38:16 | move the decimal over in the same member of positions | |
38:19 | . You have to move the the what's under here | |
38:21 | ? The decimal , the same number of places and | |
38:24 | then you do the division as normal . Sometimes you | |
38:26 | will end up where after you move the decimal you | |
38:29 | still have a decimal on the inside . It just | |
38:31 | floats up above . See here after we moved it | |
38:34 | we still had one inside . It just floats up | |
38:35 | above . But sometimes you do it and you'll end | |
38:38 | up with a whole number on the inside but you | |
38:40 | still have a decimal there , it still floats up | |
38:42 | above . It just it's there , it's just 12 | |
38:44 | has an invisible decimal there and then you go through | |
38:46 | the process is normal . Always looking to make sure | |
38:49 | that you have a remainder of zero . Then you | |
38:51 | stop when you have a remainder , then you stop | |
38:54 | here . We got to a point where the remainder | |
38:56 | what's for but we didn't have any more digits and | |
38:59 | so you're thinking you should stop but you need to | |
39:00 | keep going . And the way that you keep going | |
39:03 | is you have to add zeros after the decimal point | |
39:06 | as many times as it takes until you get to | |
39:08 | remainder of zero uh there . And then Then when | |
39:12 | you finally do get to the point where the remainder | |
39:14 | is zero down under there , then you can stop | |
39:16 | and the answer , you've calculated up above . I | |
39:18 | know it's a little weird , a little hard the | |
39:20 | first time we do it . But I think with | |
39:22 | practice you'll get the hang of it . I'd like | |
39:24 | you to solve every one of these problems yourself . | |
39:27 | Start dusting over right down the problem and do it | |
39:30 | yourself . Even if you just saw me do it | |
39:32 | then I'd like you to follow me on the part | |
39:34 | two . We'll get a little more practice with the | |
39:36 | concept of dividing decimals . |
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Learn to Divide Decimals (Long Division with Decimals) - [19] is a free educational video by Math and Science.
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